numeric | N-dimensional matrix class for Rust | Math library
kandi X-RAY | numeric Summary
kandi X-RAY | numeric Summary
General-purpose N-dimensional matrix class for Rust. It links to OpenBLAS and LAPACK to make tensor operations fast (such as matrix multiplications and linear solvers). It utilizes Rust's move semantics as much as possible to avoid unnecessary copies.
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QUESTION
I have a dataset with many columns and I'd like to locate the columns that have fewer than n unique responses and change just those columns into factors.
Here is one way I was able to do that:
...ANSWER
Answered 2021-Jun-15 at 20:29Here is a way using tidyverse
.
We can make use of where
within across
to select the columns with logical short-circuit expression where we check
- the columns are
numeric
- (is.numeric
) - if the 1 is TRUE, check whether number of distinct elements less than the user defined n
- if 2 is TRUE, then check
all
theunique
elements in the column are 0 and 1 - loop over those selected column and convert to
factor
class
QUESTION
I have this code which prints multiple tables
...ANSWER
Answered 2021-Jun-15 at 20:59So, this is a good opportunity to use purrr::map
. You are half way there by applying code to one dataframe.
You can take the code that you have written above and put it into a function.
QUESTION
im getting this message all over the place and cant figure out why its happening, any help would be appreciated.
the error message is A non well formed numeric value encountered in
the code where im getting the error message is $stmt->bindParam("ss",$delete, $dateMaker->getTodayDate());
the class im calling is set up very simple return date("Y-m-d");
ANSWER
Answered 2021-Jun-15 at 21:21The 3rd parameter of bindParam must be integer not a date
QUESTION
I have to parse lists of names, addresses, etc. that were OCRed and have invalid/incorrect characters in them and on the state postal code I need to recognize the pattern with a 2 character state followed by a 5 digit postal code and replace any non numeric characters in the postal code. I might have OK 7-41.03
at the end of a string I need to remove the hyphen and period. I know that re.sub('[^0-9]+', '', '7-41.03')
will remove the desired characters but I need it only replace characters in numbers when found at the end of the string and only if preceded by a two character state wrapped in spaces like OK
. It seems if I add anything to the regular expression as far as a lookbehind expression then I can't seem to get the characters replaced. I've come up with the following but I think there must be a simpler expression to accomplish this. Example:
ANSWER
Answered 2021-Jun-15 at 20:02You need to make use of re.sub
callbacks:
QUESTION
I am using a method to remove univariate outliers. This method only works if the vector contains outliers.
How is it possible to generalize this method to work also with vectors without outliers. I tried with ifelse
without success.
ANSWER
Answered 2021-Jun-15 at 19:58Negate (!
) instead of using -
which would work even when there are no outliers
QUESTION
looking for a quick solution to pick up the text following a numeric value that looks like this:
text to extract
...ANSWER
Answered 2021-Jun-04 at 07:28We can use re.findall
here as follows:
QUESTION
I have a list (dput() below) that has 4 datasets.I also have a variable called 'u' with 4 characters. I have made a video here which explains what I want and a spreadsheet is here.
The spreadsheet is not exactly how my data looks like but i am using it just as an example. My original list has 4 datasets but the spreadsheet has 3 datasets.
Essentially i have some characters(A,B,C,D) and i want to find the proportions of times each character occurs in each column of 3 groups of datasets.(Check video, its hard to explain by typing it out)
...ANSWER
Answered 2021-Jun-09 at 19:00We can loop over the list
'l' with lapply
, then get the table
for each of the columns by looping over the columns with sapply
after converting the column to factor
with levels
specified as 'u', get the proportions
, t
ranspose, convert to data.frame
(as.data.frame
), split by row (asplit
- MARGIN = 1), then use transpose
from purrr
to change the structure so that each column from all the list
elements will be blocked as a single unit, bind them with bind_rows
QUESTION
I have a dataset that was recorded by observation(each observation has its own row of data). I am looking to combine/condense these rows by the plant they were found on - currently a character variable. All other columns are numerical vales.
EX:
This is the raw data |Sci_Name|Honeybee_count|Other_bee_Obsevrved|Stem_count| |---|---|---|---| |Zizia aurea|1|5|10| |Asclepias viridiflora|15|1|3| |Viola unknown|0|0|4| |Zizia aurea|0|2|6| |Zizia aurea|3|6|3| |Asclepias viridiflora|8|2|17|
and I want:
Sci_Name Honeybee_count Other_bee_Obsevrved Stem_count Zizia aurea 4 13 19 Asclepias viridiflora 23 3 20 Viola unknown 0 0 4I am currently pulling this data from a CSV already in table form. I have been attempting to create a new table/data frame with one entry of each plant species, and blanks/0s for each other variable, which I can then use to c-binding the two together. This, however, has been clunky at best and I am having trouble figuring out how to have each row check itself. I am open to any approach, let me know what you think!
Thanks :D
...ANSWER
Answered 2021-Jun-15 at 18:02We can use the formula method in aggregate
from base R
. On the rhs of the ~
, specify the grouping variable and on the lhs, use .
for denoting the rest of the variables. Specify the FUN
as sum
and it will do the column wise sum by group
QUESTION
I wish to move a large set of files from an AWS S3 bucket in one AWS account (source), having systematic filenames following this pattern:
...ANSWER
Answered 2021-Jun-15 at 15:28You can use sort -V
command to consider the proper versioning of files and then invoke copy command on each file one by one or a list of files at a time.
ls | sort -V
If you're on a GNU system, you can also use ls -v
. This won't work in MacOS.
QUESTION
I am trying to compute the divergence of a vector field:
...ANSWER
Answered 2021-Jun-15 at 15:26Let me 1. explain the reason behind this observation, and 2. how to fix it.
Reason:One needs to be careful about how the data is oriented when computing the divergence (or the gradient in general), since it is important to compute the gradient along the correct axis to obtain a physically valid result.
np.meshgrid can output the mesh in two ways, depending on how you set the index parameter
Index "xy" : Here, for every y value, we sweep the x-values.Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Rust is installed and managed by the rustup tool. Rust has a 6-week rapid release process and supports a great number of platforms, so there are many builds of Rust available at any time. Please refer rust-lang.org for more information.
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