shiplift | 🐳 🦀 rust interface for maneuvering docker containers | Continuous Deployment library

Your clearest mistake is the ; at the end of the None branch. A semicolon always discards the value of the previous expression, and a block ending with a semicolon has type () (assuming the end is reachable).

After removing the ;, you’ll see that the types still don’t match. The Some branch has type FutureResult<&NetworkDetails>, while the None branch now has type impl Future. I’m not sure what you’re trying to do here, since even the base NetworkDetails and NetworkCreateInfo types are incompatible. You’ll need to figure out what type you want and how to get the same type in both branches.

Edit for updated question: Okay, you want to get a String out of both branches. You have two different types that both implement the Future trait, and you need both branches to be of the same type. This is exactly the purpose of future::Either. Simply wrap one branch in Either::A and the other branch in Either::B.

After that, you’ll also find a trivial borrowing problem in the first branch: you’ll need to copy the string with net.id.clone().