na | Share files on your local network | HTTP library

 by   srdja Rust Version: v0.2.0 License: GPL-3.0

kandi X-RAY | na Summary

kandi X-RAY | na Summary

na is a Rust library typically used in Networking, HTTP, Nodejs applications. na has no bugs, it has no vulnerabilities, it has a Strong Copyleft License and it has low support. You can download it from GitHub.

Share your files with people next to you without having to send them under the ocean and back again. Na allows you to easily share files over a local network by serving the current working directory through HTTP.
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            kandi-support Support

              na has a low active ecosystem.
              It has 16 star(s) with 1 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              na has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of na is v0.2.0

            kandi-Quality Quality

              na has no bugs reported.

            kandi-Security Security

              na has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              na is licensed under the GPL-3.0 License. This license is Strong Copyleft.
              Strong Copyleft licenses enforce sharing, and you can use them when creating open source projects.

            kandi-Reuse Reuse

              na releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            na Key Features

            No Key Features are available at this moment for na.

            na Examples and Code Snippets

            No Code Snippets are available at this moment for na.

            Community Discussions

            QUESTION

            How to produce a point graph in R like this?
            Asked 2021-Jun-16 at 04:05

            I have basically this very odd type of data frame:

            The first column is the name of the States (say I have 3 states), the second to the last column (say I have 5 columns) contains some values recorded at different dates (not continuous). I want to create a graph that plots the values for each State on the range of the dates that starts from the earliest and end in the latest dates (continuous).

            The table looks like this:

            state 2020-01-01 2020-01-05 2020-01-06 2020-01-10 AZ NA 0.078 -0.06 NA AK 0.09 NA NA 0.10 MS 0.19 0.21 NA 0.38

            "NA" means there is not data.

            How do I produce this graph in which the x axis is from 2020-01-01 to 2020-01-10 (continuous), the y axis contains the changing values (as points) of the three States, each state occupies its separate (segmented) y-axis?

            Thank you.

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:41

            You can get the data into a long format, which makes it easier to plot. R will make it difficult to read column names that start with a number. While reading the data, ensure that you have check.names = FALSE so that column names are read as is.

            Source https://stackoverflow.com/questions/67995623

            QUESTION

            Format values in a data frame
            Asked 2021-Jun-16 at 03:47

            Replace values from a column based on the following rule: t0345_0400_d2 = 03:45, or to keep only the first part of the value in time format. How can I do this?

            Data structure:

            Output:

            Sample data:

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:47

            You can use sub to extract data in two capture groups and separate them by : -

            Source https://stackoverflow.com/questions/67996057

            QUESTION

            How to put geom_label in a geom_bar
            Asked 2021-Jun-16 at 02:58

            I am doing this graph with this code

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:58

            We can calculate the labels that we want to display and use it in geom_label.

            Source https://stackoverflow.com/questions/67995696

            QUESTION

            Counting the number of unique values based on more than two columns in bash
            Asked 2021-Jun-15 at 23:03

            I need to modify the below code to work on more than one column.

            Counting the number of unique values based on two columns in bash

            ...

            ANSWER

            Answered 2021-Jun-15 at 19:48

            QUESTION

            How to print ggplot for multiple tables in this case?
            Asked 2021-Jun-15 at 22:10

            I have this code which prints multiple tables

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:59

            So, this is a good opportunity to use purrr::map. You are half way there by applying code to one dataframe.

            You can take the code that you have written above and put it into a function.

            Source https://stackoverflow.com/questions/67992308

            QUESTION

            How to type object in a material ui select
            Asked 2021-Jun-15 at 20:40

            I'm trying to implement a Select component using reactjs material ui and typescript.

            However, I am getting the following typing error:

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:40

            From what it looks like, options is actually an array of objects rather than just an object. So all you would need to do is map over the options variable. You are currently using Object.keys which is what you use if you are wanting to iterate over the keys in an object.

            Source https://stackoverflow.com/questions/67993116

            QUESTION

            Coalescing multiple chunks of columns with the same suffix in names (R)
            Asked 2021-Jun-15 at 20:10

            I have a dataset with various "chunks" of columns with different prefixes, but the same suffix:

            ID A034 B034 C034 D034 A099 B099 A123 B123 ... 1 NA 1 NA NA NA 3 1 NA ... 2 2 NA NA NA 2 NA NA 2 ... 3 NA NA 2 NA NA 2 1 NA ...

            The number of columns within each "chunk" also varies. Is there any way (other than manually, which is what I have been painstakingly doing with coalesce(!!! select(., contains("XXX")))) to automatically coalesce by chunk based on the shared suffix? That is, the result should resemble

            ID 034 099 123 ... 1 1 3 1 ... 2 2 2 2 ... 3 2 2 1 ...

            I'm not sure how to begin doing something like this, so any suggestions would be very helpful.

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:10

            We reshape the data into 'long' format with pivot_longer, then we group by 'ID' and loop across the other columns, apply the na.omit to remove the NA elements (we assume that there is only one non-NA per each column by group)

            Source https://stackoverflow.com/questions/67992781

            QUESTION

            Sort column name when they have underline_number in dplyr()?
            Asked 2021-Jun-15 at 20:10

            I tried to sort the column by the name_underline_number - using arrange(). It didn't work.

            What's the best way to do this in dplyr()?

            ...

            ANSWER

            Answered 2021-Jun-15 at 15:11

            QUESTION

            Divide every value in one column by the largest value based on the values of another column (subject)
            Asked 2021-Jun-15 at 19:59

            I have a data list with a subject column and a size column like the sample data below. For each subject, I need to divide every value in the size column by the largest value so that the range between size values will be 0 - 1.

            Take the sample data below as example, I need to divide every size value for subject 1 by 9 and divide every size value for subject by 8.

            As there are a lot of subjects in my real data, is there any approach that I can do this for each subject automatically?

            ...

            ANSWER

            Answered 2021-Jun-15 at 19:59

            Data table makes operations easy to do "by group" using the by argument:

            Source https://stackoverflow.com/questions/67991575

            QUESTION

            Find proportion of times each character(A,B,C,D) occurs in each column of a list which has 3 datasets
            Asked 2021-Jun-15 at 19:00

            I have a list (dput() below) that has 4 datasets.I also have a variable called 'u' with 4 characters. I have made a video here which explains what I want and a spreadsheet is here.

            The spreadsheet is not exactly how my data looks like but i am using it just as an example. My original list has 4 datasets but the spreadsheet has 3 datasets.

            Essentially i have some characters(A,B,C,D) and i want to find the proportions of times each character occurs in each column of 3 groups of datasets.(Check video, its hard to explain by typing it out)

            ...

            ANSWER

            Answered 2021-Jun-09 at 19:00

            We can loop over the list 'l' with lapply, then get the table for each of the columns by looping over the columns with sapply after converting the column to factor with levels specified as 'u', get the proportions, transpose, convert to data.frame (as.data.frame), split by row (asplit - MARGIN = 1), then use transpose from purrr to change the structure so that each column from all the list elements will be blocked as a single unit, bind them with bind_rows

            Source https://stackoverflow.com/questions/67909583

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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