na | Share files on your local network | HTTP library
kandi X-RAY | na Summary
kandi X-RAY | na Summary
Share your files with people next to you without having to send them under the ocean and back again. Na allows you to easily share files over a local network by serving the current working directory through HTTP.
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QUESTION
I have basically this very odd type of data frame:
The first column is the name of the States (say I have 3 states), the second to the last column (say I have 5 columns) contains some values recorded at different dates (not continuous). I want to create a graph that plots the values for each State on the range of the dates that starts from the earliest and end in the latest dates (continuous).
The table looks like this:
state 2020-01-01 2020-01-05 2020-01-06 2020-01-10 AZ NA 0.078 -0.06 NA AK 0.09 NA NA 0.10 MS 0.19 0.21 NA 0.38"NA" means there is not data.
How do I produce this graph in which the x axis is from 2020-01-01 to 2020-01-10 (continuous), the y axis contains the changing values (as points) of the three States, each state occupies its separate (segmented) y-axis?
Thank you.
...ANSWER
Answered 2021-Jun-16 at 03:41You can get the data into a long format, which makes it easier to plot. R will make it difficult to read column names that start with a number. While reading the data, ensure that you have check.names = FALSE
so that column names are read as is.
QUESTION
ANSWER
Answered 2021-Jun-16 at 03:47You can use sub
to extract data in two capture groups and separate them by :
-
QUESTION
I am doing this graph with this code
...ANSWER
Answered 2021-Jun-16 at 02:58We can calculate the labels that we want to display and use it in geom_label
.
QUESTION
I need to modify the below code to work on more than one column.
Counting the number of unique values based on two columns in bash
...ANSWER
Answered 2021-Jun-15 at 19:48Consider this awk
:
QUESTION
I have this code which prints multiple tables
...ANSWER
Answered 2021-Jun-15 at 20:59So, this is a good opportunity to use purrr::map
. You are half way there by applying code to one dataframe.
You can take the code that you have written above and put it into a function.
QUESTION
I'm trying to implement a Select component using reactjs material ui and typescript.
However, I am getting the following typing error:
...ANSWER
Answered 2021-Jun-15 at 20:40From what it looks like, options is actually an array of objects rather than just an object. So all you would need to do is map over the options variable. You are currently using Object.keys which is what you use if you are wanting to iterate over the keys in an object.
QUESTION
I have a dataset with various "chunks" of columns with different prefixes, but the same suffix:
ID A034 B034 C034 D034 A099 B099 A123 B123 ... 1 NA 1 NA NA NA 3 1 NA ... 2 2 NA NA NA 2 NA NA 2 ... 3 NA NA 2 NA NA 2 1 NA ...The number of columns within each "chunk" also varies. Is there any way (other than manually, which is what I have been painstakingly doing with coalesce(!!! select(., contains("XXX")))
) to automatically coalesce by chunk based on the shared suffix? That is, the result should resemble
I'm not sure how to begin doing something like this, so any suggestions would be very helpful.
...ANSWER
Answered 2021-Jun-15 at 20:10We reshape the data into 'long' format with pivot_longer
, then we group by 'ID' and loop across
the other columns, apply the na.omit
to remove the NA elements (we assume that there is only one non-NA per each column by group)
QUESTION
I tried to sort the column by the name_underline_number - using arrange()
. It didn't work.
What's the best way to do this in dplyr()?
...ANSWER
Answered 2021-Jun-15 at 15:11Does this work:
QUESTION
I have a data list with a subject
column and a size
column like the sample data below. For each subject, I need to divide every value in the size
column by the largest value so that the range between size values will be 0 - 1.
Take the sample data below as example, I need to divide every size value for subject 1 by 9 and divide every size value for subject by 8.
As there are a lot of subjects in my real data, is there any approach that I can do this for each subject automatically?
...ANSWER
Answered 2021-Jun-15 at 19:59Data table makes operations easy to do "by group" using the by
argument:
QUESTION
I have a list (dput() below) that has 4 datasets.I also have a variable called 'u' with 4 characters. I have made a video here which explains what I want and a spreadsheet is here.
The spreadsheet is not exactly how my data looks like but i am using it just as an example. My original list has 4 datasets but the spreadsheet has 3 datasets.
Essentially i have some characters(A,B,C,D) and i want to find the proportions of times each character occurs in each column of 3 groups of datasets.(Check video, its hard to explain by typing it out)
...ANSWER
Answered 2021-Jun-09 at 19:00We can loop over the list
'l' with lapply
, then get the table
for each of the columns by looping over the columns with sapply
after converting the column to factor
with levels
specified as 'u', get the proportions
, t
ranspose, convert to data.frame
(as.data.frame
), split by row (asplit
- MARGIN = 1), then use transpose
from purrr
to change the structure so that each column from all the list
elements will be blocked as a single unit, bind them with bind_rows
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