keiko | Enable Kubernetes at scale | Continuous Deployment library

 by   keikoproj Shell Version: Current License: No License

kandi X-RAY | keiko Summary

kandi X-RAY | keiko Summary

keiko is a Shell library typically used in Devops, Continuous Deployment applications. keiko has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Keiko is a set of independent open source declarative tools for orchestration and management of multi-tenant, reliable, secure and efficient Kubernetes clusters in production.
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              keiko has a low active ecosystem.
              It has 228 star(s) with 20 fork(s). There are 10 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              keiko has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of keiko is current.

            kandi-Quality Quality

              keiko has no bugs reported.

            kandi-Security Security

              keiko has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              keiko does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              keiko releases are not available. You will need to build from source code and install.

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            keiko Key Features

            No Key Features are available at this moment for keiko.

            keiko Examples and Code Snippets

            No Code Snippets are available at this moment for keiko.

            Community Discussions

            QUESTION

            Debug Java program to find correct person from listed traits
            Asked 2021-Jan-04 at 17:33

            I am trying to make a program that takes in the Name, Sex, Age and/or Country of a Person and outputs the correct Name from the Registry, when queried with any of the mentioned traits. If such a Person does not exist, then the output is "Unknown". 

            For example,

            Testcase # 1:

            Input:

            • Name=Rob Sex=Man Age=42 Country=US
            • Name=Robin Sex=Man Age=62 Country=US
            • Name=Magda Sex=Woman Age=29 Country=PL
            • Name=Peter Sex=Man Age=66 Country=RU
            • Name=Pete Sex=Man Age=6 Country=US
            • Name=Xiaoling Sex=Woman Age=26 Country=CH

            Output:

            • Required output criteria: Age=6 Country=US

            Therefore, the program should return a Person of Age=6 and Country=US, which is "Pete". However, my code is returning "Unknown".

            Testcase # 2:

            Input:

            • Name=John Sex=Man Age=46 Country=UK

            • Name=Anita Sex=Woman Age=22 Country=NL

            • Name=Keiko Sex=Woman Age=37 Country=JP

            • Name=Denny Sex=Man Age=13 Country=NL

            • Name=Mirjam Sex=Woman Age=28 Country=BE

            • Name=Johnny Sex=Man Age=8 Country=UK

            • Name=Anna Sex=Woman Age=71 Country=SW

            • Name=Fred Sex=Man Age=51 Country=NL

            • Name=Frederique Sex=Woman Age=51 Country=FR

            • Name=Rob Sex=Man Age=42 Country=US

            • Name=Robin Sex=Man Age=46 Country=US

            • Name=Magda Sex=Woman Age=29 Country=PL

            • Name=Peter Sex=Man Age=66 Country=RU

            • Name=Pete Sex=Man Age=66 Country=US

            • Name=Frederique Sex=Woman Age=51 Country=FR

            • Name=Xiaoling Sex=Woman Age=26 Country=CH

            Output:

            • Required output criteria: Name=Xiaoling

            Therefore, the program should return a Person of Name=Xiaoling, which is "Xialong. However, my code is returning "Unknown".

            My code:

            ...

            ANSWER

            Answered 2021-Jan-04 at 17:33

            You have a problem here

            Source https://stackoverflow.com/questions/65565967

            QUESTION

            Add column names to data read from csv file without column names
            Asked 2017-Nov-05 at 12:18

            I am using Apache Spark with Scala.

            I have a csv file that does not have column names in the first row. It's like this:

            ...

            ANSWER

            Answered 2017-Nov-05 at 12:18

            You can use toDF to specify column names when reading the CSV file:

            Source https://stackoverflow.com/questions/47120778

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install keiko

            You can download it from GitHub.

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            CLONE
          • HTTPS

            https://github.com/keikoproj/keiko.git

          • CLI

            gh repo clone keikoproj/keiko

          • sshUrl

            git@github.com:keikoproj/keiko.git

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