awesome-cheatsheets | Super Cheat Sheets - Cheat sheets | Android library

by skywind3000 Shell Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | awesome-cheatsheets Summary

awesome-cheatsheets is a Shell library typically used in Mobile, Android applications. awesome-cheatsheets has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Super Cheat Sheets - Cheat sheets for programming languages, frameworks and development tools, everything you need to know in a single file :zap:

Support

Quality

Security

License

Reuse

Support

awesome-cheatsheets has a medium active ecosystem.

It has 10162 star(s) with 1968 fork(s). There are 272 watchers for this library.

It had no major release in the last 6 months.

There are 7 open issues and 13 have been closed. On average issues are closed in 128 days. There are 15 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of awesome-cheatsheets is current.

Quality

awesome-cheatsheets has no bugs reported.

Security

awesome-cheatsheets has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

awesome-cheatsheets is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

awesome-cheatsheets releases are not available. You will need to build from source code and install.

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awesome-cheatsheets Key Features

No Key Features are available at this moment for awesome-cheatsheets.

awesome-cheatsheets Examples and Code Snippets

No Code Snippets are available at this moment for awesome-cheatsheets.

Community Discussions

Trending Discussions on awesome-cheatsheets

Interpret output from bash in Python's subprocess module

QUESTION

Interpret output from bash in Python's subprocess module

Asked 2018-Dec-25 at 17:26

I have been going through the subprocess module examples on Doug Helmann's PYMOPTW. Here's the code snippet that I have trouble with.

...

ANSWER

Answered 2018-Dec-25 at 17:26

Because you captured it, sou you have it available at completed.stdout.
Because you only captured stdout: stdout=subprocess.PIPE, but no stderr=subprocess.PIPE
It is actually sent to stderr, that's why it is printed at the beginning, because you didn't captured it and that stream is unbuffered.

Source https://stackoverflow.com/questions/53924268

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install awesome-cheatsheets

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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