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kandi X-RAY | Algorithm Summary
Algorithm is a library of tools that is used to create intelligent applications.
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Algorithm Key Features
Algorithm Examples and Code Snippets
Lines of Code : 16
License : No License
Copyconst bubbleSort = arr => {
let swapped = false;
const a = [...arr];
for (let i = 1; i < a.length; i++) {
swapped = false;
for (let j = 0; j < a.length - i; j++) {
if (a[j + 1] < a[j]) {
[a[j], a[j + 1]] = [a[j const binarySearch = (arr, item) => {
let l = 0,
r = arr.length - 1;
while (l <= r) {
const mid = Math.floor((l + r) / 2);
const guess = arr[mid];
if (guess === item) return mid;
if (guess > item) r = mid - 1;
els def pollard_rho(
num: int,
seed: int = 2,
step: int = 1,
attempts: int = 3,
) -> int | None:
"""
Use Pollard's Rho algorithm to return a nontrivial factor of ``num``.
The returned factor may be composite and require fur def hill_climbing(
search_prob,
find_max: bool = True,
max_x: float = math.inf,
min_x: float = -math.inf,
max_y: float = math.inf,
min_y: float = -math.inf,
visualization: bool = False,
max_iter: int = 10000,
) -> S def boruvka(self) -> None:
"""Performs Borůvka's algorithm to find MST."""
# Initialize additional lists required to algorithm.
component_size = []
mst_weight = 0
minimum_weight_edge: list[Any] = [-1] * se Community Discussions
Trending Discussions on Algorithm
QUESTION
I was reading this code (source):
...ANSWER
Answered 2021-Jun-16 at 02:16The n2 - n1 in the case of a negative number as a result when converted to bool will yield true. So n1 turns out to be less than n2. That's why it is a bad practice to use ints in such Boolean context.
Yes, as stated in the documentation:
...comparison function object which returns true if the first argument is less than the second
But the implementation of the comparison here leads to failure. Try this and see for yourself:
QUESTION
I have trouble understanding the first line of code inside this implementation of the bsearch function in C. I understand the search algorithm itself and I have played around with this function to get a good grasp of it but I still do not get what
...ANSWER
Answered 2021-Jun-15 at 21:44Within the function you need to find each element in the passed array. However the type of the array is unknown. You only know the size of each element of the array and the starting address of the array that is passed through the parameter base0. of the type const void *..
To access an element of the array you need to use the pointer arithmetic. But the type void is incomplete type. Its size is unknown/ So you may not use the pointer of the type (const) void *` in expressions with the pointer arithmetic.
Thus this declaration
QUESTION
I'm trying to parallelize a merge-sort algorithm. What I'm doing is dividing the input array for each thread, then merging the threads results. The way I'm trying to merge the results is something like this:
...ANSWER
Answered 2021-Jun-15 at 01:58I'm trying to parallelize a merge-sort algorithm. What I'm doing is dividing the input array for each thread, then merging the threads results.
Ok, but yours is an unnecessarily difficult approach. At each step of the merge process, you want half of your threads to wait for the other half to finish, and the most natural way for one thread to wait for another to finish is to use pthread_join(). If you wanted all of your threads to continue with more work after synchronizing then that would be different, but in this case, those that are not responsible for any more merges have nothing at all left to do.
This is what I've tried:
QUESTION
I need to find the intersection of two arrays and print out the number of elements in the intersection of the two arrays. I must also account for any duplicate elements in both the arrays. So, I decide to take care of the duplicate elements by converting the two arrays into sets and then take the intersection of both the sets. However, I encounter a segmentation fault when I run my code. I'm not sure where this occurs, any way to fix this?
...ANSWER
Answered 2021-Jun-15 at 14:37set_intersection does not allocate memory: https://en.cppreference.com/w/cpp/algorithm/set_intersection
You need a vector with some space. Change vector v; to vector v(n+m);
QUESTION
The Question
How do I best execute memory-intensive pipelines in Apache Beam?
Background
I've written a pipeline that takes the Naemura Bird dataset and converts the images and annotations to TF Records with TF Examples of the required format for the TF object detection API.
I tested the pipeline using DirectRunner with a small subset of images (4 or 5) and it worked fine.
The Problem
When running the pipeline with a bigger data set (day 1 of 3, ~21GB) it crashes after a while with a non-descriptive SIGKILL.
I do see a memory peak before the crash and assume that the process is killed because of a too high memory load.
I ran the pipeline through strace. These are the last lines in the trace:
ANSWER
Answered 2021-Jun-15 at 13:51Multiple things could cause this behaviour, because the pipeline runs fine with less Data, analysing what has changed could lead us to a resolution.
Option 1 : clean your input dataThe third line of the logs you provide might indicate that you're processing unclean data in your bigger pipeline mmap(NULL, could mean that | "Get Content" >> beam.Map(lambda x: x.read_utf8()) is trying to read a null value.
Is there an empty file somewhere ? Are your files utf8 encoded ?
Option 2 : use smaller files as inputI'm guessing using the fileio.ReadMatches() will try to load into memory the whole file, if your file is bigger than your memory, this could lead to errors. Can you split your data into smaller files ?
If files are too big for your current machine with a DirectRunner you could try to use an on-demand infrastructure using another runner on the Cloud such as DataflowRunner
QUESTION
i/p 1:
test_list = [1, 1, 3, 4, 4, 4, 5,6, 6, 7, 8, 8, 6]
o/p
[3, 5, 7, 6]
ANSWER
Answered 2021-Jun-15 at 12:29You can use itertools.groupby to group adjacent identical values, then only keep values that have group length of 1.
QUESTION
I have this kind of input as below. It is a list of strings, every odd string is a number starting with MR and every even string is some mixed text. I need to convert this list of strings to a pandas data-frame which strictly has two columns, but because some of the MR numbers are present several times paired with different mixed text counter parts I am getting extra columns everywhere where an MR is repeated, as I am demonstrating below:
...ANSWER
Answered 2021-Jun-15 at 11:48Try this
QUESTION
I try to find the optimal number of topics in the LDA algorithm for my database. For this purpose I try to use the package "ldatuning". After the implementation of the LDA algorithm with the "gibbs" method I try to use the function:
Griffiths2004(models, control) The arguments should be: models An object of class "LDA control A named list of the control parameters for estimation or an object of class "LDAcontrol".
I used it like that:
...ANSWER
Answered 2021-Jun-15 at 11:13The problem probably lies in how you pass the control parameter list to the Griffiths2004 function.
In the Griffiths2004 function, the parameters are addressed as in a list using control$param. However, lda_5@control returns an S4 object where the parameters should be addressed with control@param. (An S4 object is an advanced class in R, but the only important difference for this application is, that we address objects in these lists with @ instead of $)
You can see that lda@control is an S4 object when calling it:
QUESTION
I'm kinda new at algorithms and I'm afraid that my solutions are not correct, help me fix them.
...ANSWER
Answered 2021-Jun-15 at 07:53- the first one is correct
- so as you said valuation instructions are how many time we are assigning values with the operator then I can see almost 10 assign variables(considering that initializing of i and j as well as i++ (i=i+1) and j++)
- for the third question as you are using an array of size n your space complexity is O(n)
- for the 4th question, as you are using two nestedfor loops and you are iterating like n+(n-1)+(n-2)+... = n*(n+1)/2 = (n^2+n)/2 = O(n^2) (Time complexity)
QUESTION
We are programmatically creating PDF using our in house lib (C++) by adding all the required objects so that PDF readers can render them properly. Currently we are enhancing the lib to support digital signatures in PDF. Our users will use USB token or Windows certificates to sign the PDF. On studying raw PDF file with digital signature, we were able to make sense of all the objects except for the contents of Sig type object.
...ANSWER
Answered 2021-Jun-10 at 16:48Ok, the signature container is embedded correctly.
But there are issues with the signature container itself:
Both in the
SignedData.digestAlgorithmscollection and in theSignerInfo.digestAlgorithmvalue you have used the OID of SHA1withRSA, but that is a full signature algorithm, not the mere digest algorithm SHA1 expected there.Then the SHA1 hash of the signed bytes is BB78A402F7A537A34D6892B83881266501A691A8 but the hash you signed is 90E28B8A0D8E48691DAFE2BA10A4761FFFDCCD3D. This might be because you hash buffer2 and
buffer2 has empty contents data (/Contents <>)
The hex string delimiters '<' and '>' also belong to the contents value and, therefore, must also be removed in buffer2.
Furthermore, your signature is very weak:
- It uses SHA1 as hash algorithm. SHA1 meanwhile has been recognized as too weak a hash algorithm for document signatures.
- It doesn't use signed attributes, neither the ESS signing certificate nor the algorithm identifier protection attribute. Many validation policies require such special attributes.
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