Dict | A universal dictionary application | Dictionary library
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kandi X-RAY | Dict Summary
A universal dictionary application.
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Lines of Code : 57License : Non-SPDX (Apache License 2.0)
Copydef _wrap_and_check_metrics(self, metrics):
"""Handle the saving of metrics.
Metrics is either a tuple of (value, update_op), or a dict of such tuples.
Here, we separate out the tuples and create a dict with names to tensors.
Args:
def _wrap_and_check_metrics(self, metrics):
"""Handle the saving of metrics.
Metrics is either a tuple of (value, update_op), or a dict of such tuples.
Here, we separate out the tuples and create a dict with names to tensors.
Args:
def _transform_features_v2(features, feature_columns, state_manager):
"""Returns transformed features based on features columns passed in.
Please note that most probably you would not need to use this function. Please
check `input_layer` and ` Community Discussions
Trending Discussions on Dict
QUESTION
I'm new to Python. I have a dictionary where some fields are dates ( datetime.datetime type) and I need to use comprehension to convert those to MM/DD/YYYY strings in a new cloned dictionary.
I was getting started with
...ANSWER
Answered 2021-Jun-16 at 02:15You can use a conditional expression:
QUESTION
I have translated a program from javascript to python 3.9 and I am only missing sorting the result, but I just can't get any further.
The list consists of dicts that has an id "components", which is itself a list.
...ANSWER
Answered 2021-Jun-15 at 17:56For your original code:
QUESTION
I have data which looks like this:
...ANSWER
Answered 2021-Jun-15 at 18:35import numpy as np
features_dict = {
'feat1': np.array([[0,1],[2,3],[4,5]]),
'feat2': np.array([[6,7],[8,9],[10,11]]),
'feat3': np.array([1, 0, 0]),
'feat4': np.array([[1],[2],[1]])
}
ind = features_dict['feat3'] == 0
features_dict = {k: v[ind] for k,v in features_dict.items()}
QUESTION
I need help. I am having an table like this:
...ANSWER
Answered 2021-Jun-15 at 14:39You can use a numeric for loop with a negative step size to go back in your table, starting from the previous element. Check wether the achan and aseq fields exist, then compare them vs the dchan and dseq fields of your current entry.
QUESTION
I am getting a bad request response to my request. I have checked with an online JSON validator my dictionary data to be correct, and everything seems fine.
My code is the following:
...ANSWER
Answered 2021-Jun-15 at 11:58You are telling your server, you are sending JSON data, but the request body is not a JSON string but a url-encoded string (because that's the default behaviour of $.ajax() when you pass an object as data).
Use JSON.stringify, to pass a correct JSON body
QUESTION
Sorting data from huge lists with two levels of keys is helpful for interpreting dataset and calling by couple or one level of keys some slice of data, especially when creating plots.
I use a very naive and, I guess, inefficient way to create from a 2D-list of data a dict of dicts (two levels of keys) that returns a list of data. How to make this code more elegant, possibly faster and more readable? I guess using collection module but I didn't find a smart way.
Example:
...ANSWER
Answered 2021-Jun-15 at 07:35from itertools import groupby
first=lambda l: l[0]
def group_by_first(listo):
grouped = groupby(sorted(listo,key=first), key=first) # group by first elem, need to sort first
return {k: [e[1:] for e in g] for k,g in grouped} # remove key (first elem) from values
{k: group_by_first(l) for k,l in group_by_first(listo).items()} # group first elem and then by second
QUESTION
In the following code, queryResult is a Nested Lists. A nested list means all of the list values had another list.
LIKE:
...ANSWER
Answered 2021-Jun-15 at 08:38Your list is a two level nest list. You do not need a nested loop for dispatching your values. In your first loop on queryResult you get in record the tuples. At that point record already contains what you want to get individual element by their indexes.
QUESTION
I have generated the below plotly graph using the code as below :
...ANSWER
Answered 2021-Jun-15 at 06:28There are several themes you can try out. If you use 'solar', you will get the color you want. The source of the theme can be found here for your reference.
QUESTION
I have this list of dict:
...ANSWER
Answered 2021-Jun-15 at 05:35You can make use of a frozenset() for this
QUESTION
I have the following code in Python Jupyter:
...ANSWER
Answered 2021-Jun-14 at 18:48Since you are benchmarking in a top-level scope you have to interpolate variables in @btime with $ so the way to benchmark your code is:
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