Perfect | The Perfect core toolset | HTTP library

 by   PerfectlySoft Swift Version: v1.0.0 License: Apache-2.0

kandi X-RAY | Perfect Summary

kandi X-RAY | Perfect Summary

Perfect is a Swift library typically used in Networking, HTTP applications. Perfect has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Perfect operates using either a standalone HTTP server, HTTPS server, or through FastCGI server. It provides a system for loading your Swift-based modules at startup, for interfacing those modules with its request/response objects, or to the built-in Mustache template processing system. Perfect is built on a completely asynchronous, high-performance networking engine to provide a scalable option for internet services. It supports Secure Sockets Layer (SSL) encryption, and it features a suite of tools commonly required by internet servers such as WebSockets and iOS push notifications, but you are not limited to those options. Feel free to use your favourite JSON or templating systems, etc.

            kandi-support Support

              Perfect has a medium active ecosystem.
              It has 13867 star(s) with 968 fork(s). There are 602 watchers for this library.
              It had no major release in the last 12 months.
              There are 53 open issues and 138 have been closed. On average issues are closed in 100 days. There are 11 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Perfect is v1.0.0

            kandi-Quality Quality

              Perfect has 0 bugs and 0 code smells.

            kandi-Security Security

              Perfect has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Perfect code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Perfect is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Perfect releases are available to install and integrate.
              Installation instructions are available. Examples and code snippets are not available.
              It has 38752 lines of code, 0 functions and 83 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Perfect
            Get all kandi verified functions for this library.

            Perfect Key Features

            No Key Features are available at this moment for Perfect.

            Perfect Examples and Code Snippets

            copy iconCopy
            const isISOString = val => {
              const d = new Date(val);
              return !Number.isNaN(d.valueOf()) && d.toISOString() === val;
            isISOString('2020-10-12T10:10:10.000Z'); // true
            isISOString('2020-10-12'); // false
            Return True if n is a perfect square search .
            pythondot img2Lines of Code : 44dot img2License : Permissive (MIT License)
            copy iconCopy
            def perfect_square_binary_search(n: int) -> bool:
                Check if a number is perfect square using binary search.
                Time complexity : O(Log(n))
                Space complexity: O(1)
                >>> perfect_square_binary_search(9)
            Check if a number is a perfect number .
            pythondot img3Lines of Code : 22dot img3License : Permissive (MIT License)
            copy iconCopy
            def isPerfectNumber(number):
                input: positive integer 'number' > 1
                returns true if 'number' is a perfect number otherwise false.
                # precondition
                assert isinstance(number, int) and (
                    number > 1
                ), "'num  
            Check if num is a perfect square square .
            pythondot img4Lines of Code : 18dot img4License : Permissive (MIT License)
            copy iconCopy
            def perfect_square(num: int) -> bool:
                Check if a number is perfect square number or not
                :param num: the number to be checked
                :return: True if number is square number, otherwise False
                >>> perfect_square(9)

            Community Discussions


            Can a function and local variable have the same name?
            Asked 2022-Mar-31 at 08:41

            Here's an example of what I mean:



            Answered 2021-Dec-16 at 10:38

            foo = 5 creates a local variable inside your function. def foo creates a global variable. That's why they can both have the same name.

            If you refer to foo inside your foo() function, you're referring to the local variable. If you refer to foo outside that function, you're referring to the global variable.

            Since it evidently causes confusion for people trying to follow the code, you probably shouldn't do this.



            The unauthenticated git protocol on port 9418 is no longer supported
            Asked 2022-Mar-27 at 13:23

            I have been using github actions for quite sometime but today my deployments started failing. Below is the error from github action logs



            Answered 2022-Mar-16 at 07:01

            First, this error message is indeed expected on Jan. 11th, 2022.
            See "Improving Git protocol security on GitHub".

            January 11, 2022 Final brownout.

            This is the full brownout period where we’ll temporarily stop accepting the deprecated key and signature types, ciphers, and MACs, and the unencrypted Git protocol.
            This will help clients discover any lingering use of older keys or old URLs.

            Second, check your package.json dependencies for any git:// URL, as in this example, fixed in this PR.

            As noted by Jörg W Mittag:

            There was a 4-month warning.
            The entire Internet has been moving away from unauthenticated, unencrypted protocols for a decade, it's not like this is a huge surprise.

            Personally, I consider it less an "issue" and more "detecting unmaintained dependencies".

            Plus, this is still only the brownout period, so the protocol will only be disabled for a short period of time, allowing developers to discover the problem.

            The permanent shutdown is not until March 15th.

            For GitHub Actions:

            As in actions/checkout issue 14, you can add as a first step:



            How to perfectly forward `*this` object inside member function
            Asked 2022-Mar-04 at 22:55

            Is it possible to perfectly forward *this object inside member functions? If yes, then how can we do it? If no, then why not, and what alternatives do we have to achieve the same effect.

            Please see the code snippet below to understand the question better.



            Answered 2022-Mar-04 at 17:44

            This is not possible in C++11 without overloading sum for & and && qualifiers. (In which case you can determine the value category from the qualifier of the particular overload.)

            *this is, just like the result of any indirection, a lvalue, and is also what an implicit member function call is called on.

            This will be fixed in C++23 via introduction of an explicit object parameter for which usual forwarding can be applied:



            Paramiko authentication fails with "Agreed upon 'rsa-sha2-512' pubkey algorithm" (and "unsupported public key algorithm: rsa-sha2-512" in sshd log)
            Asked 2022-Jan-13 at 14:49

            I have a Python 3 application running on CentOS Linux 7.7 executing SSH commands against remote hosts. It works properly but today I encountered an odd error executing a command against a "new" remote server (server based on RHEL 6.10):

            encountered RSA key, expected OPENSSH key

            Executing the same command from the system shell (using the same private key of course) works perfectly fine.

            On the remote server I discovered in /var/log/secure that when SSH connection and commands are issued from the source server with Python (using Paramiko) sshd complains about unsupported public key algorithm:

            userauth_pubkey: unsupported public key algorithm: rsa-sha2-512

            Note that target servers with higher RHEL/CentOS like 7.x don't encounter the issue.

            It seems like Paramiko picks/offers the wrong algorithm when negotiating with the remote server when on the contrary SSH shell performs the negotiation properly in the context of this "old" target server. How to get the Python program to work as expected?

            Python code



            Answered 2022-Jan-13 at 14:49

            Imo, it's a bug in Paramiko. It does not handle correctly absence of server-sig-algs extension on the server side.

            Try disabling rsa-sha2-* on Paramiko side altogether:



            Local Swift Packages Stopped Working in Xcode 13
            Asked 2021-Dec-02 at 02:29

            I've local Swift Packages added to a workspace. They reside in the project subfolders and connected to different git repositories as git submodules. Everything had been working perfectly (the project was able to build, packages were able to resolve, and I could edit the packages within the same workspace).

            After I updated Xcode to 13.0, the project started failing to build with multiple errors Missing package product for each local package dependency. Removing derived data, resetting packages, cleaning build folder and restarting Xcode didn't help.



            Answered 2021-Sep-22 at 09:42

            Removing package references from workspace and re-adding them (by simple drag-n-drop from Finder) resolved the problem.

            I even didn't need to reconfigure corresponding schemes, or re-adding dependencies in targets.



            Inverting an Order-Preserving Minimal Perfect Hash Function in Better than O(K*lg N) Running Time
            Asked 2021-Nov-20 at 16:05

            I am trying to find a more efficient solution to a combinatorics problem than the solution I have already found.

            Suppose I have a set of N objects (indexed 0..N-1) and wish to consider each subset of size K (0<=K<=N). There are S=C(N,K) (i.e., "N choose K") such subsets. I wish to map (or "encode") each such subset to a unique integer in the range 0..S-1.

            Using N=7 (i.e., indexes are 0..6) and K=4 (S=35) as an example, the following mapping is the goal:
            0 1 2 3 --> 0
            0 1 2 4 --> 1
            2 4 5 6 --> 33
            3 4 5 6 --> 34

            N and K were chosen small for the purposes of illustration. However, in my actual application, C(N,K) is far too large to obtain these mappings from a lookup table. They must be computed on-the-fly.

            In the code that follows, combinations_table is a pre-computed two-dimensional array for fast lookup of C(N,K) values.

            All code given is compliant with the C++14 standard.

            If the objects in a subset are ordered by increasing order of their indexes, the following code will compute that subset's encoding:



            Answered 2021-Oct-21 at 02:18

            Take a look at the recursive formula for combinations:

            Suppose you have a combination space C(n,k). You can divide that space into two subspaces:

            • C(n-1,k-1) all combinations, where the first element of the original set (of length n) is present
            • C(n-1, k) where first element is not preset

            If you have an index X that corresponds to a combination from C(n,k), you can identify whether the first element of your original set belongs to the subset (which corresponds to X), if you check whether X belongs to either subspace:

            • X < C(n-1, k-1) : belongs
            • X >= C(n-1, k-1): doesn't belong

            Then you can recursively apply the same approach for C(n-1, ...) and so on, until you've found the answer for all n elements of the original set.

            Python code to illustrate this approach:



            How to add void/null as default argument to a function/lambda pointer, in C++?
            Asked 2021-Nov-16 at 20:34

            Present signature is



            Answered 2021-Oct-21 at 13:46

            You can use a default initialized std::function with the correct prototype for that:



            How to fix function/symbol 'pango_context_set_round_glyph_positions' error
            Asked 2021-Aug-18 at 21:33

            I have deployed a Django project using Apache2, everything is working fine except for weazyprint which creates PDF file for forms. The pdf was working fine in testing and local host.

            Now everytime I access the pdf it is showing this error:



            Answered 2021-Aug-15 at 12:07

            Probably Weasyprint was not downloaded properly:




            The argument type 'String' can't be assigned to the parameter type 'Uri'
            Asked 2021-Jun-11 at 09:44

            I am trying to make an HTTP POST request with the flutter plugin HTTP but I am getting an error of the title. Does anyone know the cause of this since in my other applications this works just perfectly fine?



            Answered 2021-May-08 at 22:09

            To improve compile-time type safety, package:http 0.13.0 introduced breaking changes that made all functions that previously accepted Uris or Strings now accept only Uris instead. You will need to explicitly use Uri.parse to create Uris from Strings. (package:http formerly called that internally for you.)

            Old Code Replace With http.get(someString) http.get(Uri.parse(someString))

            (and so on.)

            In your specific example, you will need to use:



            Sophisticated proportional triple element progress bar design using only CSS
            Asked 2021-Jun-07 at 13:39

            I have made a custom progress bar, consisting of three separete parts (a uniquely customisable center piece, a left part and a right part) but I'm having difficulty aligning the center block correctly in all phases.

            First I will show the desired end state using three graphical layouts, then I will describe the current problem and finally I will provide my current workaround hack, which is faulty and needs a fix of some sort.

            Three Desired States:
            Desired outcome of a starting state showing 1% left aligned:

            Desired outcome of halfway sate with center block perfectly in the middle at 50%:

            Desired end sate with center block perfectly stopping at 100% right aligned:



            Answered 2021-May-22 at 14:44

            You can do like below. I am using different colorations to better see the result


            Community Discussions, Code Snippets contain sources that include Stack Exchange Network


            No vulnerabilities reported

            Install Perfect

            Access a tutorial to help you get started using Perfect quickly. It includes straightforward examples of how Perfect can be used.


            Get started working with Perfect, deploy your apps, and find more detailed help by consulting our reference library. We welcome contributions to Perfect’s documentation. If you spot a typo, bug, or other errata, or have additions or suggestions to recommend, please create a pull request or issue in Github.
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