urllib | Request HTTP URLs in a complex world | HTTP library

 by   node-modules TypeScript Version: 3.25.1 License: MIT

kandi X-RAY | urllib Summary

kandi X-RAY | urllib Summary

urllib is a TypeScript library typically used in Networking, HTTP applications. urllib has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Request HTTP URLs in a complex world — basic and digest authentication, redirections, cookies, timeout and more.
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              urllib has a low active ecosystem.
              It has 703 star(s) with 113 fork(s). There are 35 watchers for this library.
              There were 1 major release(s) in the last 6 months.
              There are 5 open issues and 128 have been closed. On average issues are closed in 458 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of urllib is 3.25.1

            kandi-Quality Quality

              urllib has 0 bugs and 0 code smells.

            kandi-Security Security

              urllib has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              urllib code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              urllib is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              urllib releases are available to install and integrate.
              Installation instructions are not available. Examples and code snippets are available.

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            urllib Key Features

            No Key Features are available at this moment for urllib.

            urllib Examples and Code Snippets

            五、代码架构及实现,2. 新闻爬取模块
            JavaScriptdot img1Lines of Code : 165dot img1no licencesLicense : No License
            copy iconCopy
            from urllib import request
            from bs4 import BeautifulSoup
            import re
            
            class ThemeSpider(object):
                def __init__(self, theme_url,judge_url):
                    self.theme_url = theme_url
                    self.judge_url = judge_url
            
                def getLinkList(self):
                    resp  
            Using with HTTP clients
            TypeScriptdot img2Lines of Code : 121dot img2License : Permissive (MIT)
            copy iconCopy
            import https from 'https';
            import { CookieJar } from 'tough-cookie';
            import { HttpsCookieAgent } from 'http-cookie-agent';
            
            const jar = new CookieJar();
            const agent = new HttpsCookieAgent({ jar });
            
            https.get('https://example.com', { agent }, (res) =  
            1 - Year Matching
            JavaScriptdot img3Lines of Code : 25dot img3no licencesLicense : No License
            copy iconCopy
            \b(19|20)\d{2}\b
            
            import re
            import urllib.request
            import operator
            
            # Download wiki page
            url = "https://en.wikipedia.org/wiki/Diplomatic_history_of_World_War_II"
            html = urllib.request.urlopen(url).read()
            
            # Find all mentioned years in the 20th or 21st  
            Is there a way to read an image from a url on openCV?
            Lines of Code : 36dot img4License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import numpy as np
            import urllib
            import cv2
            def url_to_image(url):
                resp = urllib.urlopen(url)
                image = np.asarray(bytearray(resp.read()), dtype="uint8")
                image = cv2.imdecode(image, cv2.IMREAD_COLOR)
                return image
            
            Fiona Driver Error when downloading files via URL
            Lines of Code : 26dot img5License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import geopandas as gpd
            import requests, io
            from pathlib import Path
            from zipfile import ZipFile, BadZipFile
            import urllib
            import fiona
            
            url = "https://hepgis.fhwa.dot.gov/fhwagis/AltFuels_Rounds1-5_2021-05-25.zip"
            
            try:
                gdf = gpd.read
            plotly map does not display geometries
            Lines of Code : 122dot img6License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import geopandas as gpd
            import shapely.geometry
            import numpy as np
            import plotly.express as px
            import requests
            from pathlib import Path
            from zipfile import ZipFile
            import urllib
            import pandas as pd
            
            # fmt: off
            # download boundaries
            url = "
            Which exact driver is sqlalchemy using?
            Lines of Code : 12dot img7License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import urllib
            from sqlalchemy import create_engine
            
            server = 'serverName\instanceName,port' # to specify an alternate port
            database = 'mydb' 
            username = 'myusername' 
            password = 'mypassword'
            
            params = urllib.parse.quote_plus('DRIVER={ODBC 
            S3 replication: delete files in the source bucket after they've been replicated
            Lines of Code : 28dot img8License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import boto3
            import urllib
            
            DESTINATION_BUCKET = 'bucket2'
            
            def lambda_handler(event, context):
                
                s3_client = boto3.client('s3')
            
                # Get the bucket and object key from the Event
                for record in event['Records']:
                    source_
            Django redirect and modify GET parameters
            Lines of Code : 17dot img9License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            from django.urls import resolve, reverse
            import urllib
            
            def drop_get_param(request, param):
              'helpful for redirecting while dropping a specific parameter'
              resolution = resolve(request.path_info) #simulate resolving the request
            
              new_pa
            reorganising data into prefix inside Amazon S3
            Lines of Code : 36dot img10License : Strong Copyleft (CC BY-SA 4.0)
            copy iconCopy
            import boto3
            import urllib
            
            def lambda_handler(event, context):
               
                s3_client = boto3.client('s3')
                
                bucket = event['Records'][0]['s3']['bucket']['name']
                key = urllib.parse.unquote_plus(event['Records'][0]['s3']['object']['k

            Community Discussions

            QUESTION

            Beautfiul Soup HTML parsing returning empty list when scraping YouTube
            Asked 2021-Jun-15 at 20:43

            I'm trying to use BS4 to parse through the HTML for an about page on a youtube channel so I can scrape the number of channel views. Below is the code to scrape the channel views (located in the 'yt-formatted-string') and also the whole right column of the page. Both lines of code return either an empty list and a "None" value for the findAll() and find() functions, respectively.

            I read another thread saying I may be receiving an empty list or "None" value because the page is accessing an API to get the total channel views to count and the values aren't actually in the HTML I'm parsing.

            I know I could access much of this info through the Youtube API, but I want to iterate this code over multiple channels that are not my own. Moreover, I want to understand how to use BS4 to its full extent so I can replicate this process on an Instagram page or Facebook page.

            Should I be using a different library that isn't BS4? Is what I'm looking to accomplish even possible?

            My CODE

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:43

            YouTube is loaded dynamically, therefore urlib won't support it. However, the data is available in JSON format on the website. You can convert this data to a Python dictionary (dict) using the built-in json library.

            This example is using the URL you have provided: https://www.youtube.com/c/Rozziofficial/about, you can change the channel name, it will work for all channels.

            Here's an example using requests, you can use urlib instead:

            Source https://stackoverflow.com/questions/67992121

            QUESTION

            How to properly read large html in chunks with .iter_content?
            Asked 2021-Jun-13 at 19:35

            So, I'm a very amateur python programmer but hope all I'll explain makes sense.

            I want to scrape a type of Financial document called "10-K". I'm just interested in a little part of the whole document. An example of the URL I try to scrape is: https://www.sec.gov/Archives/edgar/data/320193/0000320193-20-000096.txt

            Now, if I download this document as a .txt, It "only" weights 12mb. So for my ignorance doesn't make much sense this takes 1-2 min to .read() (even I got a decent PC).

            The original code I was using:

            ...

            ANSWER

            Answered 2021-Jun-13 at 18:07

            The time it takes to read a document over the internet is really not related to the speed of your computer, at least in most cases. The most important determinant is the speed of your internet connection. Another important determinant is the speed with which the remote server responds to your request, which will depend in part on how many other requests the remote server is currently trying to handle.

            It's also possible that the slow-down is not due to either of the above causes, but rather to measures taken by the remote server to limit scraping or to avoid congestion. It's very common for servers to deliberately reduce responsiveness to clients which make frequent requests, or even to deny the requests entirely. Or to reduce the speed of data transmission to everyone, which is another way of controlling server load. In that case, there's not much you're going to be able to do to speed up reading the requests.

            From my machine, it takes a bit under 30 seconds to download the 12MB document. Since I'm in Perú it's possible that the speed of the internet connection is a factor, but I suspect that it's not the only issue. However, the data transmission does start reasonably quickly.

            If the problem were related to the speed of data transfer between your machine and the server, you could speed things up by using a streaming parser (a phrase you can search for). A streaming parser reads its input in small chunks and assembles them on the fly into tokens, which is basically what you are trying to do. But the streaming parser will deal transparently with the most difficult part, which is to avoid tokens being split between two chunks. However, the nature of the SEC document, which taken as a whole is not very pure HTML, might make it difficult to use standard tools.

            Since the part of the document you want to analyse is well past the middle, at least in the example you presented, you won't be able to reduce the download time by much. But that might still be worthwhile.

            The basic approach you describe is workable, but you'll need to change it a bit in order to cope with the search strings being split between chunks, as you noted. The basic idea is to append successive chunks until you find the string, rather than just looking at them one at a time.

            I'd suggest first identifying the entire document and then deciding whether it's the document you want. That reduces the search issue to a single string, the document terminator (\n\n; the newlines are added to reduce the possibility of false matches).

            Here's a very crude implementation, which I suggest you take as an example rather than just copying it into your program. The function docs yields successive complete documents from a url; the caller can use that to select the one they want. (In the sample code, the first matching document is used, although there are actually two matches in the complete file. If you want all matches, then you will have to read the entire input, in which case you won't have any speed-up at all, although you might still have some savings from not having to parse everything.)

            Source https://stackoverflow.com/questions/67958718

            QUESTION

            python urllib, returns empty page for specific urls
            Asked 2021-Jun-13 at 15:32

            I am having trouble with specific links with urllib. Below is the code sample I use:

            ...

            ANSWER

            Answered 2021-Jun-13 at 15:32

            Try using. You will get the response. Certain websites are secured and only respond to certain user-agents only.

            Source https://stackoverflow.com/questions/67959641

            QUESTION

            How to edit columns in .CSV files using pandas
            Asked 2021-Jun-13 at 15:06
            import urllib.request
            import pandas as pd
            
            # Url file Website
            url = 'https://......CSV'
            
            # Download file
            urllib.request.urlretrieve(
                url, "F:\.....A.CSV")
            
            csvFilePath = "F:\.....A.CSV"
            
            df = pd.read_csv(csvFilePath, sep='\t')
            
            rows=[0,1,2,3]
            df2 = df.drop(rows, axis=0, inplace=True)
            df.to_csv(
                r'F:\....New_A.CSV')
            
            ...

            ANSWER

            Answered 2021-Jun-13 at 14:40

            QUESTION

            Want to get the text from the li tag using selenium
            Asked 2021-Jun-13 at 08:49

            I want the text from the li tag that is the specification of the product but when i am searching using driver.find_element_by_css_selector it gives the error as path cannot find .So not able to get the text .

            ...

            ANSWER

            Answered 2021-Jun-13 at 08:49

            There are anti-scraping measures. If those do not affect you then you can use css classes to target the li elements to loop over, and the title/values for each specification:

            Source https://stackoverflow.com/questions/67955673

            QUESTION

            How to scrape the ratings and all the reviews from the website using selenium
            Asked 2021-Jun-13 at 08:20

            I want to scrape the rating and all the reviews on the page .But not able to find the path .

            ...

            ANSWER

            Answered 2021-Jun-13 at 04:51

            Perhaps there is a problem with your path? (apologies I'm not on windows to test). From memory, Windows paths use \ characters instead of /. Additionally, you may need two backticks after the drive path (C:\\).

            c:\\Users\91940\AppData\Local\...

            Source https://stackoverflow.com/questions/67954661

            QUESTION

            extract information from p tag and insert into dict python with beautifulsoap
            Asked 2021-Jun-13 at 02:24

            I am trying to web scrape a government public page that contains speeches and biography of ministers. At the end I would like a dictionary like this:

            ...

            ANSWER

            Answered 2021-Jun-13 at 02:24

            Based on the provided target data structure above, you appear to be using a dictionary. It isn't clear what you would like your keys to be so I would probably suggest using a list/array.

            I would suggest a slightly different way to dissect the problem.One potential implementation would be to iterate over each row (paragraph

            of the table (div

            ) and consume the data as it is present. This allows us to populate the data array one index at a time.

            From here, if the link(s) are present you could then query the external data source (or read from a different location on the page) to collect the respective data. In the example below, I choose to do this in a different iteration of data to help make the code a bit more readable.

            I have not used the BeautifulSoap4 library before. I apologise if my solution isn't the most elegant regarding the libraries usage.

            Source https://stackoverflow.com/questions/67953915

            QUESTION

            AIOHTTP replacing %3A with :
            Asked 2021-Jun-13 at 00:22

            FIX FOR THIS ISSUE:

            ...

            ANSWER

            Answered 2021-Jun-13 at 00:22

            EDIT:

            Minimal working code based on @Weeble answer.

            It uses yarl with encoded=True to stop requoting %3A to :

            Source https://stackoverflow.com/questions/67952708

            QUESTION

            Want to scrape all the specific href from the a tag
            Asked 2021-Jun-12 at 11:12

            I have search the specific brand Samsung , for this number of products are search ,I just wanted to scrape all the href from the of the search products with the product name .

            ...

            ANSWER

            Answered 2021-Jun-12 at 11:12

            Couple of things. You are trying to mix bs4 syntax with selenium which is causing your current error. Additionally, you are targeting potentially dynamic values. Finally, there are anti-scraping measures which may later impact on your work.

            Ignoring the last, a more robust, syntax appropriate version, might be:

            Source https://stackoverflow.com/questions/67947409

            QUESTION

            how to parse query string parameters in python?
            Asked 2021-Jun-11 at 08:21

            I am working on a REST API and using python. say for a get request ( sample below), I am assuming , anyone who makes a call will URL encode the URL, what is the correct way to decode and read query parameters in python?

            'https://someurl.com/query_string_params?id=1&type=abc'

            ...

            ANSWER

            Answered 2021-Jun-11 at 08:21

            Here's an example of how to split a URL and get the query parameters:

            Source https://stackoverflow.com/questions/67928935

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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