vectorial | Vector math library with NEON/SSE support | Math library

 by   scoopr C++ Version: Current License: BSD-2-Clause

kandi X-RAY | vectorial Summary

kandi X-RAY | vectorial Summary

vectorial is a C++ library typically used in Utilities, Math, WebGL applications. vectorial has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Vector math library with NEON/SSE support
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              vectorial has a low active ecosystem.
              It has 329 star(s) with 42 fork(s). There are 23 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 4 open issues and 2 have been closed. On average issues are closed in 7 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of vectorial is current.

            kandi-Quality Quality

              vectorial has no bugs reported.

            kandi-Security Security

              vectorial has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              vectorial is licensed under the BSD-2-Clause License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              vectorial releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            vectorial Key Features

            No Key Features are available at this moment for vectorial.

            vectorial Examples and Code Snippets

            No Code Snippets are available at this moment for vectorial.

            Community Discussions

            QUESTION

            c++ search for string in an vector of strings
            Asked 2021-Apr-19 at 01:42

            I am working on a project to read a Context-free Grammar and represent it 1.Vectorial, 2. Branched chained lists, 3. Array (Table). I encounter a problem with string comparison. When I read a string from keyboard representing right side of a Production rule, I want to check if that string exists in a vector of strings. The problem is that comparison is not working right. If the string I compare is the first string from the vector of strings than the comparison is working fine. But if the string I compare is a string from the vector of strings other than first comparison is not working, it's like the string is not from the vector of strings. Sorry for my English. I better let the code explain

            ...

            ANSWER

            Answered 2021-Apr-19 at 01:42

            To do that you'd have to loop into the vector with a for loop and compare every string in it, it would be something like:

            Source https://stackoverflow.com/questions/67151808

            QUESTION

            grepl functionality in vectorial conditional statement
            Asked 2021-Mar-26 at 04:28

            How may I obtain the same functionality as grepl within a vectorial conditional statement?

            I wish to transform raw data of geographical divisions (mixed with other categories) by prepending the city name where it is missing from district names:

            ...

            ANSWER

            Answered 2021-Mar-26 at 04:01

            Change your code like this using Vectorize, It should work, instead of grepl use vgrepl like below. Vectorize function vectorizes on the parameters, although you can choose what parameters to vectorize upon using vectorize.args, since by default grepl is not vectorized on patterns with input you are getting this error:

            Source https://stackoverflow.com/questions/66810784

            QUESTION

            How to find the common eigenvectors of two matrices with distincts eigenvalues
            Asked 2021-Jan-16 at 21:30

            I am looking for finding or rather building common eigenvectors matrix X between 2 matrices A and B such as :

            ...

            ANSWER

            Answered 2021-Jan-05 at 16:28

            I don't think there is a built-in facility in Matlab for computing common eigenvalues of two matrices. I'll just outline brute force way and do it in Matlab in order to highlight some of its eigenvector related methods. We will assume the matrices A and B are square and diagonalizable.

            Outline of steps:
            1. Get eigenvectors/values for A and B respectively.

            2. Group the resultant eigenvectors by their eigenspaces.

            3. Check for intersection of the eigenspaces by checking linear dependency among the eigenvectors of A and B one pair eigenspaces at a time.

            Matlab does provide methods for (efficiently) completing each step! Except of course step 3 involves checking linear dependency many many times, which in turn means we are likely doing unnecessary computation. Not to mention, finding common eigenvectors may not require finding all eigenvectors. So this is not meant to be a general numerical recipe.

            How to get eigenvector/values

            The syntax is

            Source https://stackoverflow.com/questions/65548452

            QUESTION

            Plotting the results of a Newton-Raphson solution for multiple cases
            Asked 2020-Dec-14 at 10:50

            Consider the following problem:

            I am now in the third part of this question. I wrote the vectorial loop equations (q=teta2, x=teta3 and y=teta4):

            ...

            ANSWER

            Answered 2020-Dec-14 at 10:42

            Please take a look at my solution below, and study how it differs from your own.

            Source https://stackoverflow.com/questions/65270276

            QUESTION

            Convergence tests of Leapfrog method for vectorial wave equation in Python
            Asked 2020-Nov-05 at 13:11

            Considering the following Leapfrog scheme used to discretize a vectorial wave equation with given initial conditions and periodic boundary conditions. I have implemented the scheme and now I want to make numerical convergence tests to show that the scheme is of second order in space and time.

            I'm mainly struggling with two points here:

            1. I'm not 100% sure if I implemented the scheme correctly. I really wanted to use slicing because it is so much faster than using loops.
            2. I don't really know how to get the right error plot, because I'm not sure which norm to use. In the examples I have found (they were in 1D) we've always used the L2-Norm.
            ...

            ANSWER

            Answered 2020-Nov-05 at 13:11

            Apart from the initialization, I see no errors in your code.

            As to the initialization, consider the first step. There you should compute, per the method description, approximations for p(dt,j*dx) from the values of p(0,j*dx) and u(0.5*dt, (j+0.5)*dx). This means that you need to initialize at time==0

            Source https://stackoverflow.com/questions/64613909

            QUESTION

            Runge-Kutta 4 for solving systems of ODEs Python
            Asked 2020-Sep-09 at 13:08

            I wrote code for Runge-Kutta 4 for solving system of ODEs.
            It works fine for 1-D ODE but when I try to solve x'' + kx = 0 I have a problem trying to define a vectorial function:

            Let u1 = x and u2 = x' = u1', then the system looks like:

            ...

            ANSWER

            Answered 2020-Aug-26 at 23:22

            The model is this: enter image description here

            From the Langtangen’s book Programming for Computations - Python.

            Source https://stackoverflow.com/questions/63606503

            QUESTION

            Avoiding plotting odes divergenet solution ODEint
            Asked 2020-Aug-29 at 12:51

            I'm trying to plot a phase plane and I want it to look nice, however some solutions of the system of equations diverge because of the initial conditions. Is there some way that I can make a try/except chain in order when the solution diverges it doesn't plot it. Here is my code:

            ...

            ANSWER

            Answered 2020-Aug-29 at 12:51

            This is a discontinuous ODE which can lead to unusual effects like a sliding mode. One way to quickly work around that is to mollify the jump by implementing a blending zone where the vector field changes quickly but continuously from one phase to the other (see Unsure about how to use event function in Matlab for other generic work-arounds). The changes for that can be implemented as

            Source https://stackoverflow.com/questions/63641982

            QUESTION

            Thresholding a numpy array with different threshold on each column
            Asked 2020-Aug-28 at 20:12

            I'm trying to do exactly what this question asked for R in Python: Different hard threshold for each column That is, apply a different threshold per column on an $n\times m$ numpy array.

            The only way I know is to iterate over the columns but there must be a vectorial way to do it (perhaps using views or strides)?

            ...

            ANSWER

            Answered 2020-Aug-28 at 19:39

            You can use broadcasting:

            Source https://stackoverflow.com/questions/63639849

            QUESTION

            Runge–Kutta methods for ODE integration in Python with additional constraints
            Asked 2020-Jun-22 at 08:15

            I have a question on solving second order differential equations using RK4, considering additional constraints on the first derivative. I am doing the example shown here with some modifications

            θ′′(t) + b θ′(t) + c sin(θ(t)) = 0

            The additional constraint is:

            when θi θ(i+1)<0, then θ′(i+1)=0.9θ′i,

            where i is the steps of t, i+1 is one step after i. In the real world, it says when the direction of displacement reverses, its velocity is reduced to 90%.

            Vectorially if y(t) = (θ(t), ω(t)), then the equation is = f(t,y), where f(t,y) = (y₂(t), −by₂(t) − cos(y₁(t))).

            In this problem, how should I modify the code if I want to add constraints on ω or θ′(t) (which are the same thing)? Here is my code which didn't work. The additional condition makes θ′ non-continuous. The following "homemade" solution cannot update θ′ properly. I am new to Python and this is my first StackOverflow post. Any guidance is much appreciated.

            ...

            ANSWER

            Answered 2020-Jun-21 at 10:08

            Unless I completely misunderstand you, what you want is a simple case distinction in f: Mathematically, you have f₂(t,y) = −by₂(t) − cos(y₁(t)) if θi²−1 = y₁(t)²−1 < 0 and 0.9·(y₂−1) otherwise. This is all still only a dependency of f on y, which can simply implemented programming-wise.

            For example, you could define:

            Source https://stackoverflow.com/questions/62492418

            QUESTION

            Finding the unknown third point
            Asked 2020-Jun-17 at 18:48

            As provided in the image i know co-ordinates of two points A(x1, y1) and C(x2, y2), and also i have distance D from C to third point i.e B(x, y) and the angle thetha made by three points. Here thetha can range from 0 to 360.

            Please i need the know third point from the following data given, any code would be helpful.

            As i have tried the possible way using the method provided in the following link i was not able to find correct result

            Javascript function to find third point of triangle when all sides, angles and first two points are known

            PS.

            Vectorial answers is cool, but I use javascript and don't know how to add vectors over there.

            ...

            ANSWER

            Answered 2020-Jun-17 at 18:48
            CA_unit[0] = (A[0] - C[0]);
            CA_unit[1] = (A[1] - C[1]);
            
            norm_CA = sqrt( CA_unit[0] * CA_unit[0] + CA_unit[1] * CA_unit[1] );
            
            CA_unit[0] = CA_unit[0] / norm_CA;
            CA_unit[1] = CA_unit[1] / norm_CA;
            
            cs = cos(theta);
            sn = sin(theta);
            
            // point after clockwise rotation:
            B[0] = D*(  cs * CA_unit[0] + sn*CA_unit[1]) + C[0];
            B[1] = D*(- sn * CA_unit[0] + cs*CA_unit[1]) + C[1];
            
            // alternative point, counter clockwise rotation:
            B_[0] = D*( cs * CA_unit[0] - sn*CA_unit[1]) + C[0];
            B_[1] = D*( sn * CA_unit[0] + cs*CA_unit[1]) + C[1];
            
            

            Source https://stackoverflow.com/questions/62433772

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            You can download it from GitHub.

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