Victoria | Lavalink wrapper for Discord.NET | Bot library
kandi X-RAY | Victoria Summary
kandi X-RAY | Victoria Summary
- Lavalink wrapper for Discord.NET which provides more options and performs better than all .NET Lavalink libraries combined.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Victoria
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Trending Discussions on Victoria
QUESTION
I have the following document.
...ANSWER
Answered 2022-Apr-08 at 19:48If you use remove all the interference from markdown, you are more flexible with the placement of the bibliography:
QUESTION
I have a database with the following tables :
...ANSWER
Answered 2022-Mar-24 at 17:12One option is to use UNION ALL to normalize your data then then perform a simple conditional aggregation/string_agg()
Example
QUESTION
I have a Pandas dataframe looking like this:
...ANSWER
Answered 2022-Mar-04 at 15:21Try:
QUESTION
I've read similar solved questions on this website but they do to help me! So, I'm sorry to make a similar question.
I've the following .txt file named "Asteroids_Numbered.txt" (the file has lots of rows, i.e. 607013, but I put a lot less for simplicity):
...ANSWER
Answered 2022-Jan-13 at 15:54To expand on @HighPerformanceMark's comments, the best thing to do is to define an Asteroid
type which holds all of the information about an asteroid, and then to create an array of Asteroid
s.
Asteroid
type
The Asteroid
type should initially just contain the data about an asteroid,
QUESTION
I am using the following function (based on https://rpubs.com/sprishi/twitterIBM) to extract bigrams from text. However, I want to keep the hash symbol for analysis purposes. The function to clean text works fine, but the unnest tokens function removes special characters. Is there any way to run unnest tokens without removing special characters?
...ANSWER
Answered 2022-Jan-09 at 06:43Here is a solution that involving create a custom n-grams function
SetupQUESTION
I'm struggling to tackle the task here - I have 2 files: a HTML and external JS file. I need a function to take an element from the 'cities' array as input, to then return a string as an output to be used in the for-loop that populates my table.
I have a function with a switch statement and call it from my for-loop which makes sense to me, but clearly I'm missing something fundamental - Really appreciate any guidance !
...ANSWER
Answered 2022-Jan-08 at 23:30function buildCitiesList() {
const cityListJSON = {
cities: [
{
name: "Adelaide",
state: "SA",
text: "Lovely city on the Torrens River",
avgrainfall: 547,
sunnydays: 224,
},
{
name: "Brisbane",
state: "QLD",
text: "Capital city of Queensland",
avgrainfall: 1080,
sunnydays: 261,
},
{
name: "Canberra",
state: "ACT",
text: "Where the federal politicians are!",
avgrainfall: 602,
sunnydays: 246,
},
{
name: "Darwin",
state: "NT",
text: "Crazy and funny folks, up north!",
avgrainfall: 1812,
sunnydays: 239,
},
{
name: "Hobart",
state: "TAS",
text: "Beautiful but very chilly winters...",
avgrainfall: 569,
sunnydays: 193,
},
{
name: "Melbourne",
state: "VIC",
text: "City with four seasons in one day",
avgrainfall: 518,
sunnydays: 185,
},
{
name: "Perth",
state: "WA",
text: "A long drive but worth it!",
avgrainfall: 734,
sunnydays: 265,
},
{
name: "Sydney",
state: "NSW",
text: "Prettiest harbour in the world!",
avgrainfall: 1042,
sunnydays: 236,
},
],
};
mytable =
"" +
"#CityStateCommentAvg RainfallSunny DaysBest Activity";
const numberOfCities = cityListJSON.cities.length
for (i = 0; i < numberOfCities; i++)
mytable +=
"" +
i +
"" +
cityListJSON.cities[i].name +
"" +
fullStateName(cityListJSON.cities[i].state) +
"" +
cityListJSON.cities[i].text +
"" +
cityListJSON.cities[i].avgrainfall +
"" +
cityListJSON.cities[i].sunnydays +
"";
mytable += "";
document.getElementById("table").outerHTML = mytable;
}
QUESTION
$ cat /etc/issue
Ubuntu 18.04.6 LTS \n \l
...ANSWER
Answered 2022-Jan-02 at 05:50Does the support for Ubuntu 18.04.6 LTS (bionic) deprecated?
Not exactly.
As a general rule, the latest version of the script targets the latest supported (by Openstack) versions of the host operating systems. Older versions may work. But there might be minor issues ... that someone with the ability to read / diagnose shell scripts ought to be able to figure out.
If you need a version of the script that explicitly supports (say) Bionic, there will be one in the Git6 repo history.
(This is in line with general OpenStack Ubuntu support. The latest OpenStack release is Wallably and Wallaby no longer supports Bionic. The Bionic -> Focal cross-over release of Openstack was Ussuri; see https://ubuntu.com/openstack/docs/supported-versions. Note that Devstack is not an official OpenStack product, but they are effectively forced to track the "supported release" rules, at least loosely.)
The version of the Devstack script that you checked out does not explicitly supports Focal rather than Bionic.
If you look at https://opendev.org/openstack/devstack/src/branch/master/stack.sh on line 230, it currently says:
QUESTION
I am trying to write a program that will create a link to the API. To do this, I use bs4
, with which I search for the div I need, but I get an error due to the program not working correctly. I want to find only this coin name
that are in the coin list
. How I can fix it? Please, give me a hand.
My code:
...ANSWER
Answered 2022-Jan-02 at 00:11There are two issues with your code:
- This:
if check_name == coins_list:
will always return false, sincecheck_name
is a string andcoins_list
is a list. You wantif check_name in coins_list:
. baseurl
isn't defined in the code snippet. Change it tourl
.
Perform both these changes, and you should have a nonempty output in your text file. The URLs in this file appear to be well-formed.
QUESTION
There are some raw rows with two or more addresses, I want to split them based on the last part of the Canadian postal code using a look-arround mechanism. The Canadian postal code format is A1A 1A1, where A is a letter and 1 is a digit, with a space separating the third and fourth characters.
Here is an example
160 Rue, Notre Dame N, Bureau 140, Sainte-Marie, G6E 3Z9 887 Chemin du Bord de l'Eau, Saint-Henri de Levis, G0R 3E0
I want to split the address based on the space after the last part of postal code if it exists The result:
...ANSWER
Answered 2021-Dec-24 at 18:03You can use
QUESTION
I have NAME column data like
NAME Victoria Brown Sam Allen JR Ray M James IIII want to split base on the number of space the firstname, lastname. HERE is what I did but last case statement is coming wrong it still getting the suffix when we have 3 space.
expecting:
NAME Victoria Brown Sam Allen Ray James ...ANSWER
Answered 2021-Dec-09 at 22:29If string_split is available in your version
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