menagerie | orchestration platform for Docker containers running batch | BPM library

 by   ibm-security-innovation Go Version: Current License: Apache-2.0

kandi X-RAY | menagerie Summary

kandi X-RAY | menagerie Summary

menagerie is a Go library typically used in Automation, BPM, Docker applications. menagerie has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

An orchestration platform for Docker containers runnning batch jobs. This was driven by a need to run multiple malware analyzers side by side, each with a different set of installation requirements and technologies. These needed to be exposed as services to other systems and users.
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              menagerie has a low active ecosystem.
              It has 54 star(s) with 3 fork(s). There are 8 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 1 have been closed. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of menagerie is current.

            kandi-Quality Quality

              menagerie has no bugs reported.

            kandi-Security Security

              menagerie has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              menagerie is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              menagerie releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed menagerie and discovered the below as its top functions. This is intended to give you an instant insight into menagerie implemented functionality, and help decide if they suit your requirements.
            • handleJob processes a single task
            • handleResult returns the result of a job
            • workerSentry is the main entry point for worker .
            • read reads the engine configuration file
            • GetEngineStats returns a map of engine statuses .
            • rows2MapsArray converts sql . Rows to maps .
            • handleLink handles a link request .
            • newfileUploadRequest creates a new http . Request .
            • handleGetPagination handles GET requests .
            • handleGetJobs handles GET requests .
            Get all kandi verified functions for this library.

            menagerie Key Features

            No Key Features are available at this moment for menagerie.

            menagerie Examples and Code Snippets

            No Code Snippets are available at this moment for menagerie.

            Community Discussions

            QUESTION

            Replicate self join method SQL on Pandas
            Asked 2021-Jun-05 at 14:36

            Problem: Trying to produce this table by using Pandas to replicate self join method in SQL. The objective is just to produce pair of movie_title where the length are the same.

            ...

            ANSWER

            Answered 2021-Jun-05 at 14:28

            QUESTION

            How to execute the except block if try prints an empty string
            Asked 2020-Nov-28 at 06:12

            I want to search a record in a SQL table and if that record is not found, I want to print an error message. I am using a try/except block to do that. But, the error message is not shown. What I think is happening is that when SQL fails to find that record, it won't raise an error. It will just print an empty line. So, the except block is not being executed as python thinks the try block was executed successfully.

            Code:

            ...

            ANSWER

            Answered 2020-Nov-28 at 05:47

            when there are no records satisfying the given condition (name='Fluff' in your case), mysql returns an empty set and no error is produced.

            Source https://stackoverflow.com/questions/65046749

            QUESTION

            How to pass a function with a parameter without calling it
            Asked 2020-Sep-01 at 22:37

            I've looked everywhere and I can't seem to find an answer, or at least one I can understand at my very limited skill level (I'm essentially teaching myself html, css, and js with practice and Google). I am trying to use document.getElementById("button").onclick = buttonfunc; as part of a function with buttonfunc as a parameter. I've been able to call this function easily enough with something equivalent to Buttons(MyFunction);, because if I put the parentheses like Buttons(MyFunction()); my understanding is that it treats the parameter as the value of MyFunction(), even though it's a void function. The problem with this is that I can't pass parameters with the function, meaning I have to make a new function for every new thing I want a button to do, which I would like to avoid if I can because there might be very mundane or similar function. Is there a way to pass a parameter with the function so that I don't have to make a new one for every minute difference? Thanks in advance!

            Here is the full code of the function and some examples of its use (I'm making a text adventure with 8 buttons).

            ...

            ANSWER

            Answered 2020-Sep-01 at 22:37

            QUESTION

            Displaying Objects Inside JSON Object in Angular
            Asked 2020-Apr-17 at 16:20

            I have a JSON database that has some nested Objects in it:

            ...

            ANSWER

            Answered 2020-Apr-17 at 16:20

            Please try like this . In the template you can keyvalue pipe . using this pipe you can access the key and value of the objects item1 and item2.

            Source https://stackoverflow.com/questions/61275292

            QUESTION

            IntelliJ Scala "Package" not in "New" menu
            Asked 2018-Jun-27 at 21:06

            I am using IntelliJ and would like to create a new Scala Package. In all of the instructions that I find online I see that I am supposed to select "Package" from the "New" menu. However, my "New" menu does not include "Package" as an option.

            How can I add "Package" to this list or otherwise add a package to my Scala application?

            Also as a side note, I am developing Scala applications and as such I would like for primarily Scala related templates to appear in this list as opposed to the menagerie or irrelevant templates that currently presents itself. How can I edit the list of templates that appears in this menu?

            ...

            ANSWER

            Answered 2018-Jun-27 at 21:06

            I solved this problem by taking the following steps:

            1. Making sure to install both the Scala and SBT plugins. (I was missing the SBT plugin)
            2. Copying all the source files (*.scala) into a temporary location
            3. Deleting the project.
            4. Creating a new project with the same structure and copying the source files into their proper location.

            Now "Package" appears in the menu (and full syntax hilighting now works, which was the reason why I wanted to fix this in the first place). Note that simply installing the SBT plugin (step 1) was not sufficient in fix this problem.

            Maybe it was a bug.

            Source https://stackoverflow.com/questions/51070628

            QUESTION

            ModelBindingContext.ValueProvider.GetValue(key) always returns null
            Asked 2017-Oct-16 at 20:28

            I'm using AngularJS to manipulate a fairly complex parent object with children that need to behave quite differently server-side. Based on this answer, which appears pretty solid, I've created the test case below. The issue I'm running into is that whenever I enter the CreateModel function, any call to bindingContext.ValueProvider.GetValue(key) returns null. I've checked all values in the debugger. The object type appears to be loaded, but no values have yet been bound.

            My Models:

            ...

            ANSWER

            Answered 2017-Oct-16 at 20:28

            The solution I was hoping existed:

            When posting JSON data, it appears that all keys have the model name prepended. This can be solved simply by changing the first line of CreateModel to:

            Source https://stackoverflow.com/questions/46710841

            QUESTION

            Custom x-label for ordered stacked bar graph in R ggplot2
            Asked 2017-Aug-15 at 18:01

            I am trying to create a custom label for an ordered stacked bar graph in ggplot2.

            I have six different animals in my garden - a beaver, an elephant, a kangaroo, a mouse, a dragon and a chihuahua.

            I asked them each to sing to me on two occasions, once when they were happy, and once when they were sad. I recorded how long they sang for on each occasion.

            I want to plot the animals' total singing time in a stacked bar graph, with one stacked bar corresponding to one animal, and each component of the stacked bar corresponding to the animal’s mood, but I want to order the stacked bars by the animal’s size, with the animal’s name displayed underneath the bars.

            In an attempt to do this, I created a column in my data frame that combines the size order information with the animal factor (e.g. "1.mouse", etc.). This allows the bars to be displayed in the size order. I then tried to use ‘substring' to extract the letters corresponding to the name for the x label (so that it reads e.g. "mouse", etc.) That didn’t work.

            If I just use ‘animal’ to label the axis then ggplot labels the bars with the animal names listed in alphabetical order. I did try using the function ‘order’ too.

            I have looked on stack overflow and other sites and can't find the exact problem elsewhere.

            Many thanks from me and my menagerie!

            ...

            ANSWER

            Answered 2017-Aug-15 at 18:01

            Part of the problem is that your use of cbind is coercing different data types (numeric, factor) into a matrix of a single data type (numeric). Try the data.frame constructor with vector arguments.

            You don't need to put numbers into the factor levels, and you don't need an "ordered factor" (which is useful for regression and other modeling but not needed here). Just use a regular factor with levels= which will take care of the display order.

            Your other problem is that your animal size order isn't right, so the example results don't look right.

            Source https://stackoverflow.com/questions/45697243

            QUESTION

            C# create an association between nodes
            Asked 2017-May-15 at 02:18

            I have a library class that has a Serve() method. What it does is dequeue a person from a queue and Pop a book from a stack. A Book is associated to a Borrower when it is borrowed, that way the method ReturnBook() can accept a string value that corresponds to the name of the person who borrowed the book.

            How can I create an association between the Book and the Borrower? It's my first time encountering associations in C#. Here is a sample input and output

            ...

            ANSWER

            Answered 2017-May-15 at 02:18

            One way to do this is to create a property of one item that is of the type of the other item. For example, a Borrower may have a Book property. Then, when the borrower borrows a book, you just set the value of the Book property to the book they just borrowed.

            Following is an illustrative example of how this might work:

            To start with, you should create some classes to represent the objects. Here's an example:

            Source https://stackoverflow.com/questions/43969699

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install menagerie

            Once the system is up and running it can be used as follows (from outside the Vagrant box):.
            Launches the entire system, with a sample engine wrapping apktool
            We are using ubuntu 14.04 box and docker 1.10 - you can adapt it to your env but keep in mind at least docker 1.10 is expected, for features we are using
            It is recommended to install the vagrant-vbguest plugin - this will align the guest additions in the imported box
            Submit job to engine via curl -v -XPOST http://localhost:8100/apktool/upload -F "upload=@<path-to-sample-apk>". The response is a job-id number
            Get response via curl -v http://localhost:8100/result/<job-id>
            Console and result viewer via menagerie console
            RabbitMQ monitoring via RabbitMQ admin. Use the credentials provided in confs/default.json, by default menagerie|menagerie

            Support

            Contributions to the project are welcomed. It is required however to provide alongside the pull request one of the contribution forms (CLA) that are a part of the project. If the contributor is operating in his individual or personal capacity, then he/she is to use the individual CLA; if operating in his/her role at a company or entity, then he/she must use the corporate CLA.
            Find more information at:

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            gh repo clone ibm-security-innovation/menagerie

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            git@github.com:ibm-security-innovation/menagerie.git

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