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kandi X-RAY | meerkat Summary
kandi X-RAY | meerkat Summary
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Top functions reviewed by kandi - BETA
- Run starts the Meakat
- run runs the merkat daemon .
- New returns a new Meerkat struct
- exists returns true if the given path exists .
- Runs the main loop
meerkat Key Features
meerkat Examples and Code Snippets
Community Discussions
Trending Discussions on meerkat
QUESTION
I am trying to build a lambda expression progressively in this manner:
...ANSWER
Answered 2022-Apr-02 at 22:26LINQ Expression
s are trees of objects, not collections of text to be compiled. While the parameters from the source function expressions may look the same on the outside they are in fact different objects that just happen to have the same properties. So when you combine two function expressions and throw out the parameter(s) from one of them you're left with an Expression
that doesn't have all the information.
To make this more obvious, imagine you're adding a => a.Name == "test"
to b => b.Age > 0
. Your code will produce a LINQ expression equivalent to a => a.Name == "test" && b.Age > 0
... which leaves an unknown object b
in the mix. Even if you changed the name in the source expression it would still be an unknown object.
Fortunately we can use an ExpressionVisitor
to fix this up for us. Here's one I've used in similar situations:
QUESTION
I'm building a scripts to compare lines from two text files but I got the thing wrong looping through each line in the 2 files. I don't know why but it just didn't do anything for me as I wanted it in the code to do. Here is the sample text in the text files I'm processing.
...ANSWER
Answered 2020-Jun-23 at 08:45I'm not quite sure what your aim is in comparing, but I would parse the files in a single loop, resulting in an array of two PsCustomObject arrays like this:
QUESTION
I have an array that I want to convert to a dictionary and I declared a function to do so but I get this error each time I compile "Cannot subscript a value of type '[String : [String]]' with an argument of type 'String.SubSequence' (aka 'Substring')"
my code is
...ANSWER
Answered 2020-Feb-18 at 15:45You can simply use Dictionary's
init(grouping:by:)
initializer
like so,
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