hongkong | A parallax scroll effect plugin | Animation library
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kandi X-RAY | hongkong Summary
A parallax scroll effect plugin
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hongkong Key Features
hongkong Examples and Code Snippets
import $ from 'jquery';
import hongkong from 'hongkong';
hongkong($);
$.hongkong();
Community Discussions
Trending Discussions on hongkong
QUESTION
i'm new to React Native and i was working on a project using api from different url's. When i use the fetch to the url's, i want so set my state with setState but when i try it, the console.warn shows my arrays empy. What is the problem in my code? I appreciate any feedback :)
...ANSWER
Answered 2021-May-19 at 02:32setState
does not update the state immediately -- it gets updated on the next render. Assuming you're actually getting data back from your API, your console.warn
is showing the state from the current render.
You can use the callback function (second argument of setState
) to see the value after it's been set.
You can also make all of the updates in one shot by using array spreading.
QUESTION
i have this file and i would like to match everything between #sent_id=\d+ and blank line. Here is my file :
...ANSWER
Answered 2021-May-17 at 06:13One way: read the file in chunks of text between empty lines.
QUESTION
I have been working on an Excel sheet using python, where i have to extract only the specific value from the column, using an list with set of charaters.
Need to check every character from the column check with the list, If it matches need to return the matched value into the dataframe which can be used for further analysis.
Input Data :
...ANSWER
Answered 2021-Mar-25 at 18:18You can use
QUESTION
from datetime import datetime, timedelta
from pytz import timezone
import pytz
import re
while True:
times=['Brazil','Hongkong','Australia','Mexico','US','Poland','Singapore','Portugal','Japan','Israel']
use=[times[0],times[2],times[3],times[4]]
print(r" enter the time zone that you want to watch ")
o=input(f"{times}\n").lower()
e=list(o)
if e=='us'or e=='usa' or e=='united state' or e=='untied states of america':
uy=list(e)
uy.remove(e[2:])
else:
mn=e[0].upper()+e[1:]
if mn not in times:
print("you need to enter time zone")
continue
else:
if mn and uy in use:
for i in re.findall(f'^{mn}'|f'{uy}',pytz.all_timezones):
u=list(re.findall(f'^{mn}'|f'{uy}',pytz.all_timezones))
if u[i]=='/':
u.remove(u[0:i])
print(u)
...ANSWER
Answered 2021-Mar-16 at 18:12You have:
QUESTION
I have 4 tables. I want all the rows and cols from my first table tbl_2021 and only those data which are not in tbl_2021 but present in the the rest 3 tables, but based on one condition
- if there id exist in tbl_2020, tbl_2019 and in tbl_2018 then i need the id and it's details from the most recent table that is tbl_2020.
- if an id is across 2019 and 2018 table, then i need the data from 2019 so on like that.If in 2020 and 018 then 020 and so on
- if the same is across 2021,2020,2019 and 2018 then the data from 2021 is selected.
And - I'm hail from a shell scripting background, and i've just started with sql. so if any noble mind could tell me the approach or what i should do to get these pieces together would mean more than happiness to me. Thank you
tbl_2021
id name addr location country contintent gdp 123 rob dware texas us us 8 456 lilly gwood london uk uk 5 670 rick utown newyrok us us 8 490 zang kcity hk hongkong hongkong 6tbl_020
id location name 999 ger roger 888 bel leslie 670 us marietbl_019
id location name data network 999 uk roger xx na 555 rus vladmir ux na 879 us marie xx ua 481 cn kimtbl_018
id location name data network 823 uk roger xx na 555 rus vladmir ux na 879 us maria xx ua 670 us marie xy uy 888 in raj xx jooutput:
id name addr location country contintent gdp 123 rob dware texas us us 8 456 lilly gwood london uk uk 5 670 rick utown newyrok us us 8 490 zang kcity hk hongkong hongkong 6 999 roger ger 888 leslie bel 555 vladmir rus 879 marie us 481 kim cn 823 roger uk ...ANSWER
Answered 2021-Mar-12 at 11:55First, you should fix your data model. It is not a good idea to store such data in separate tables. Instead, you should store in a single table with a year column.
Second, I think you can solve your problem using full join
, but it is a little tricky:
QUESTION
I'm building an ecommerce store with Django and I want that when the user selects a payment, he gets redirected to that specific payment option. Meaning that when someone clicks Stripe, it should go to the Stripe's checkout and when he clicks Paypal, it should direct them tothat option. But as for now, when the user clicks the button to proceed it does nothing. I've alread made all the form validations and the payment_option's so that it redirects correctly.
views.py:
...ANSWER
Answered 2021-Feb-04 at 12:13Add method="post"
to your html form.
QUESTION
I have data where the variable X provides information for certain years: 2003, 2007, 2011, 2015 and 2019.
For example, for a country A in 2003 the X is =10. In 2007 the X is =20; and then again in 2011 X is =30.
What I want is to fill the years from 2003 to 2006 with X=10. And then from 2007 to 2010, X=20, and so on.In other words, the latest value should be applied to all the coming years until new value.
I simply can't figure this out and I've recently taken a course in R. The only way that I can think of is to 1) create manually all the missing years in-between and 2) use this function
...ANSWER
Answered 2021-Jan-11 at 21:44I think the tidyr
functions expand
and fill
will be helpful here.
Try something like this:
QUESTION
I am receiving JSON object containing a time in following format.
...ANSWER
Answered 2020-Dec-30 at 09:06If those devices had configured the time zone correctly, you can use
QUESTION
For example:
...ANSWER
Answered 2020-Dec-02 at 09:43You can use modulo and integer division by index values and reshape by DataFrame.unstack
, last sorting second level and for avoid duplicated columns names flatten MultiIndex in columns
:
QUESTION
my webpage has the html code as below and I am having a container in the last section with a jumbotron inside. I wish to have this container displayed filling the entiree screen and curently there is a margin around it. How can I eliminate the margin for this last container with id footerContainer?
...ANSWER
Answered 2020-Nov-23 at 05:35There are two way you do this
Add Class = container-fluid div after the Id = footerContainer div and gave background to Id = footerContainer div.
With css add padding left and right 0px to Id = footerContainer div ID
#footerContainer { padding-left: 0; padding-right: 0; }
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