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CtCI-6th-Edition | Cracking the Coding Interview 6th Ed. Solutions | Learning library

 by   careercup Java Version: Current License: No License

 by   careercup Java Version: Current License: No License

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kandi X-RAY | CtCI-6th-Edition Summary

CtCI-6th-Edition is a Java library typically used in Tutorial, Learning, Example Codes applications. CtCI-6th-Edition has no vulnerabilities and it has medium support. However CtCI-6th-Edition has 111 bugs and it build file is not available. You can download it from GitHub.
Cracking the Coding Interview 6th Ed. Solutions
Support
Support
Quality
Quality
Security
Security
License
License
Reuse
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kandi-support Support

  • CtCI-6th-Edition has a medium active ecosystem.
  • It has 8641 star(s) with 3647 fork(s). There are 584 watchers for this library.
  • It had no major release in the last 12 months.
  • There are 38 open issues and 21 have been closed. On average issues are closed in 56 days. There are 87 open pull requests and 0 closed requests.
  • It has a neutral sentiment in the developer community.
  • The latest version of CtCI-6th-Edition is current.
CtCI-6th-Edition Support
Best in #Learning
Average in #Learning
CtCI-6th-Edition Support
Best in #Learning
Average in #Learning

quality kandi Quality

  • CtCI-6th-Edition has 111 bugs (4 blocker, 27 critical, 71 major, 9 minor) and 3143 code smells.
CtCI-6th-Edition Quality
Best in #Learning
Average in #Learning
CtCI-6th-Edition Quality
Best in #Learning
Average in #Learning

securitySecurity

  • CtCI-6th-Edition has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
  • CtCI-6th-Edition code analysis shows 0 unresolved vulnerabilities.
  • There are 56 security hotspots that need review.
CtCI-6th-Edition Security
Best in #Learning
Average in #Learning
CtCI-6th-Edition Security
Best in #Learning
Average in #Learning

license License

  • CtCI-6th-Edition does not have a standard license declared.
  • Check the repository for any license declaration and review the terms closely.
  • Without a license, all rights are reserved, and you cannot use the library in your applications.
CtCI-6th-Edition License
Best in #Learning
Average in #Learning
CtCI-6th-Edition License
Best in #Learning
Average in #Learning

buildReuse

  • CtCI-6th-Edition releases are not available. You will need to build from source code and install.
  • CtCI-6th-Edition has no build file. You will be need to create the build yourself to build the component from source.
  • Installation instructions are not available. Examples and code snippets are available.
  • CtCI-6th-Edition saves you 11320 person hours of effort in developing the same functionality from scratch.
  • It has 22916 lines of code, 2126 functions and 584 files.
  • It has medium code complexity. Code complexity directly impacts maintainability of the code.
CtCI-6th-Edition Reuse
Best in #Learning
Average in #Learning
CtCI-6th-Edition Reuse
Best in #Learning
Average in #Learning
Top functions reviewed by kandi - BETA

kandi has reviewed CtCI-6th-Edition and discovered the below as its top functions. This is intended to give you an instant insight into CtCI-6th-Edition implemented functionality, and help decide if they suit your requirements.

  • Auxiliary method to create an array of Strings that can be used as an array of strings .
  • Returns a list of words in the dictionary .
  • Reduce the expression .
  • Internal method for debugging .
  • Gets the previous sequence .
  • Encode the tokens .
  • Flips the section at the specified direction
  • Converts two binary nodes to a circular tree .
  • Declares the lock .
  • Extend a point .

CtCI-6th-Edition Key Features

Cracking the Coding Interview 6th Ed. Solutions

Cloning

copy iconCopydownload iconDownload
  git clone --recursive https://github.com/careercup/CtCI-6th-Edition.git

What does $1 ++ $0 mean in the closure for Swift?

copy iconCopydownload iconDownload
infix operator ++

private func ++<Element>(element: Element, list: ListNode<Element>) -> ListNode<Element> {
    return list.insert(element: element)
}

How to find all possible lengths of a board made up from planks?

copy iconCopydownload iconDownload
allLengths(3, 1, 2)

What is the fastest way to increment a string in perl?

copy iconCopydownload iconDownload
#!/usr/bin/perl
use strict;
use warnings;
use Benchmark qw(cmpthese);

my $dna;
$dna .= [qw(G A T C)]->[rand 4] for 1 .. 10000;

sub frequency_concat {
    my $result = '';

    for my $idx (0 .. length($dna) - 1) {
            $result .= substr($dna, $idx, 1);
    }

    return $result;
 }

 sub frequency_join {
    my $result = '';

    for my $idx (0 .. length($dna) - 1) {
            $result = join '', $result, substr($dna,$idx,1);
    }

    return $result;
}

sub frequency_list_push {
       my @result = ();

       for my $idx (0 .. length($dna) - 1) {
               push @result, substr($dna,$idx,1);
       }

       return join '', @result;
 }

 sub frequency_list_prealloc {
            my @result = (' ' x length($dna));

            for my $idx (0 .. length($dna) - 1) {
                    $result[$idx] = substr($dna,$idx,1);
            }

            return join '', @result;
 }


cmpthese(-1, # Run each for at least 1 second(s)   {
               concat => \&frequency_concat,
               join => \&frequency_join,
               list_push => \&frequency_list_push,
               list_list_prealloc => \&frequency_list_prealloc
       }
   );
                    Rate         join   list_push list_list_prealloc          concat
join               213/s           --        -38%               -41%        -74%
list_push          342/s          60%          --                -5%        -58%
list_list_prealloc 359/s          68%          5%                 --        -56%
concat             822/s         285%        140%               129%          --
-----------------------
#!/usr/bin/perl
use strict;
use warnings;
use Benchmark qw(cmpthese);

my $dna;
$dna .= [qw(G A T C)]->[rand 4] for 1 .. 10000;

sub frequency_concat {
    my $result = '';

    for my $idx (0 .. length($dna) - 1) {
            $result .= substr($dna, $idx, 1);
    }

    return $result;
 }

 sub frequency_join {
    my $result = '';

    for my $idx (0 .. length($dna) - 1) {
            $result = join '', $result, substr($dna,$idx,1);
    }

    return $result;
}

sub frequency_list_push {
       my @result = ();

       for my $idx (0 .. length($dna) - 1) {
               push @result, substr($dna,$idx,1);
       }

       return join '', @result;
 }

 sub frequency_list_prealloc {
            my @result = (' ' x length($dna));

            for my $idx (0 .. length($dna) - 1) {
                    $result[$idx] = substr($dna,$idx,1);
            }

            return join '', @result;
 }


cmpthese(-1, # Run each for at least 1 second(s)   {
               concat => \&frequency_concat,
               join => \&frequency_join,
               list_push => \&frequency_list_push,
               list_list_prealloc => \&frequency_list_prealloc
       }
   );
                    Rate         join   list_push list_list_prealloc          concat
join               213/s           --        -38%               -41%        -74%
list_push          342/s          60%          --                -5%        -58%
list_list_prealloc 359/s          68%          5%                 --        -56%
concat             822/s         285%        140%               129%          --
-----------------------
use strict;
use warnings;

use Benchmark qw(cmpthese);
use Inline C => './compress_c.c';

my $str_len = 10000;
my @chars = qw(a b c d);
my $str;
$str .= [@chars]->[rand 4] for 1 .. $str_len;

cmpthese(
    -1,
    {
        compress_array => sub { compress_array( $str ) },
        compress_regex => sub { compress_regex( $str ) },
        compress_str   => sub { compress_str( $str ) },
        compress_c     => sub { compress_c( $str ) },
    }
);

# Suggested by @melpomene in the comments   
sub compress_regex {
    return $_[0] =~ s/([a-z])\1+/($+[0] - $-[0]) . $1/egr;
}

sub compress_array {
    my $result = '';

    my @chrs = split //, $_[0];

    my $prev = $chrs[0];
    my $count = 1;
    my @result;
    for my $i ( 1..$#chrs ) {
        my $char = $chrs[$i];
        if ( $prev eq $char ) {
            $count++;
            next if $i < $#chrs;
        }
        if ( $count > 1) {
            push @result, $count, $prev;
        }
        else {
            push @result, $prev;
        }
        if ( ( $i == $#chrs ) and ( $prev ne $char ) ) {
            push @result, $char;
            last;
        }
        $count = 1;
        $prev = $char;
    }

    return join '', @result;
}

sub compress_str {
    my $result = '';
    my $prev = substr $_[0], 0, 1;
    my $count = 1;
    my $lastind = (length $_[0]) - 1;
    for my $i (1 .. $lastind) {
        my $char = substr $_[0], $i, 1;
        if ( $prev eq $char ) {
            $count++;
            next if $i < $lastind;
        }

        if ( $count > 1) {
            $result .= $count;
        }
        $result .= $prev;
        if ( ( $i == $lastind ) and ( $prev ne $char ) ) {
            $result .= $char;
            last;
        }
        $count = 1;
        $prev = $char;
    }

    return $result;
}
SV *compress_c(SV* str_sv) {
    STRLEN len;
    char* str = SvPVbyte(str_sv, len);

    SV* result = newSV(len);
    char *buf = SvPVX(result);

    char prev = str[0];
    int count = 1;
    int j = 0;
    int i;
    for (i = 1; i < len; i++ )
    {
    char cur = str[i];
        if ( prev == cur ) {
            count++;
            if ( i < (len - 1) )
                continue;
        }

        if ( count > 1) {
            buf[j++] = count + '0';  // assume count is less than 10
        }

        buf[j++] = prev;
        if ( (i == (len - 1)) && (prev != cur) ) buf[j++] = cur;
        count = 1;
        prev = cur;
    }

    buf[j] = '\0';
    SvPOK_on(result);
    SvCUR_set(result, j);
    return result;
}
                  Rate compress_array  compress_str compress_regex    compress_c
compress_array   311/s             --          -42%           -45%          -99%
compress_str     533/s            71%            --            -6%          -98%
compress_regex   570/s            83%            7%             --          -98%
compress_c     30632/s          9746%         5644%          5273%            --
-----------------------
use strict;
use warnings;

use Benchmark qw(cmpthese);
use Inline C => './compress_c.c';

my $str_len = 10000;
my @chars = qw(a b c d);
my $str;
$str .= [@chars]->[rand 4] for 1 .. $str_len;

cmpthese(
    -1,
    {
        compress_array => sub { compress_array( $str ) },
        compress_regex => sub { compress_regex( $str ) },
        compress_str   => sub { compress_str( $str ) },
        compress_c     => sub { compress_c( $str ) },
    }
);

# Suggested by @melpomene in the comments   
sub compress_regex {
    return $_[0] =~ s/([a-z])\1+/($+[0] - $-[0]) . $1/egr;
}

sub compress_array {
    my $result = '';

    my @chrs = split //, $_[0];

    my $prev = $chrs[0];
    my $count = 1;
    my @result;
    for my $i ( 1..$#chrs ) {
        my $char = $chrs[$i];
        if ( $prev eq $char ) {
            $count++;
            next if $i < $#chrs;
        }
        if ( $count > 1) {
            push @result, $count, $prev;
        }
        else {
            push @result, $prev;
        }
        if ( ( $i == $#chrs ) and ( $prev ne $char ) ) {
            push @result, $char;
            last;
        }
        $count = 1;
        $prev = $char;
    }

    return join '', @result;
}

sub compress_str {
    my $result = '';
    my $prev = substr $_[0], 0, 1;
    my $count = 1;
    my $lastind = (length $_[0]) - 1;
    for my $i (1 .. $lastind) {
        my $char = substr $_[0], $i, 1;
        if ( $prev eq $char ) {
            $count++;
            next if $i < $lastind;
        }

        if ( $count > 1) {
            $result .= $count;
        }
        $result .= $prev;
        if ( ( $i == $lastind ) and ( $prev ne $char ) ) {
            $result .= $char;
            last;
        }
        $count = 1;
        $prev = $char;
    }

    return $result;
}
SV *compress_c(SV* str_sv) {
    STRLEN len;
    char* str = SvPVbyte(str_sv, len);

    SV* result = newSV(len);
    char *buf = SvPVX(result);

    char prev = str[0];
    int count = 1;
    int j = 0;
    int i;
    for (i = 1; i < len; i++ )
    {
    char cur = str[i];
        if ( prev == cur ) {
            count++;
            if ( i < (len - 1) )
                continue;
        }

        if ( count > 1) {
            buf[j++] = count + '0';  // assume count is less than 10
        }

        buf[j++] = prev;
        if ( (i == (len - 1)) && (prev != cur) ) buf[j++] = cur;
        count = 1;
        prev = cur;
    }

    buf[j] = '\0';
    SvPOK_on(result);
    SvCUR_set(result, j);
    return result;
}
                  Rate compress_array  compress_str compress_regex    compress_c
compress_array   311/s             --          -42%           -45%          -99%
compress_str     533/s            71%            --            -6%          -98%
compress_regex   570/s            83%            7%             --          -98%
compress_c     30632/s          9746%         5644%          5273%            --
-----------------------
use strict;
use warnings;

use Benchmark qw(cmpthese);
use Inline C => './compress_c.c';

my $str_len = 10000;
my @chars = qw(a b c d);
my $str;
$str .= [@chars]->[rand 4] for 1 .. $str_len;

cmpthese(
    -1,
    {
        compress_array => sub { compress_array( $str ) },
        compress_regex => sub { compress_regex( $str ) },
        compress_str   => sub { compress_str( $str ) },
        compress_c     => sub { compress_c( $str ) },
    }
);

# Suggested by @melpomene in the comments   
sub compress_regex {
    return $_[0] =~ s/([a-z])\1+/($+[0] - $-[0]) . $1/egr;
}

sub compress_array {
    my $result = '';

    my @chrs = split //, $_[0];

    my $prev = $chrs[0];
    my $count = 1;
    my @result;
    for my $i ( 1..$#chrs ) {
        my $char = $chrs[$i];
        if ( $prev eq $char ) {
            $count++;
            next if $i < $#chrs;
        }
        if ( $count > 1) {
            push @result, $count, $prev;
        }
        else {
            push @result, $prev;
        }
        if ( ( $i == $#chrs ) and ( $prev ne $char ) ) {
            push @result, $char;
            last;
        }
        $count = 1;
        $prev = $char;
    }

    return join '', @result;
}

sub compress_str {
    my $result = '';
    my $prev = substr $_[0], 0, 1;
    my $count = 1;
    my $lastind = (length $_[0]) - 1;
    for my $i (1 .. $lastind) {
        my $char = substr $_[0], $i, 1;
        if ( $prev eq $char ) {
            $count++;
            next if $i < $lastind;
        }

        if ( $count > 1) {
            $result .= $count;
        }
        $result .= $prev;
        if ( ( $i == $lastind ) and ( $prev ne $char ) ) {
            $result .= $char;
            last;
        }
        $count = 1;
        $prev = $char;
    }

    return $result;
}
SV *compress_c(SV* str_sv) {
    STRLEN len;
    char* str = SvPVbyte(str_sv, len);

    SV* result = newSV(len);
    char *buf = SvPVX(result);

    char prev = str[0];
    int count = 1;
    int j = 0;
    int i;
    for (i = 1; i < len; i++ )
    {
    char cur = str[i];
        if ( prev == cur ) {
            count++;
            if ( i < (len - 1) )
                continue;
        }

        if ( count > 1) {
            buf[j++] = count + '0';  // assume count is less than 10
        }

        buf[j++] = prev;
        if ( (i == (len - 1)) && (prev != cur) ) buf[j++] = cur;
        count = 1;
        prev = cur;
    }

    buf[j] = '\0';
    SvPOK_on(result);
    SvCUR_set(result, j);
    return result;
}
                  Rate compress_array  compress_str compress_regex    compress_c
compress_array   311/s             --          -42%           -45%          -99%
compress_str     533/s            71%            --            -6%          -98%
compress_regex   570/s            83%            7%             --          -98%
compress_c     30632/s          9746%         5644%          5273%            --

Community Discussions

Trending Discussions on CtCI-6th-Edition
  • What does $1 ++ $0 mean in the closure for Swift?
  • How to find all possible lengths of a board made up from planks?
  • What is the fastest way to increment a string in perl?
Trending Discussions on CtCI-6th-Edition

QUESTION

What does $1 ++ $0 mean in the closure for Swift?

Asked 2020-Apr-13 at 18:36

I was looking at the code for how to remove duplicates from a list and I came upon some syntax I am unfamiliar with. What does $1 ++ $0 mean?

extension List where Element: Hashable {

    func removeDuplicates() -> List {
        var set = Set<Element>()
        let list = reduce(List()) {
            guard !set.contains($1) else { return $0 }
            set.insert($1)
            return $1 ++ $0
        }
        return list.reversed()
    }
}

ANSWER

Answered 2020-Apr-13 at 18:36

$0 is the first parameter passed into the closure.

$1 is the second parameter.

++ is a custom infix operator

infix operator ++

private func ++<Element>(element: Element, list: ListNode<Element>) -> ListNode<Element> {
    return list.insert(element: element)
}

It will insert the element on the right to list on right of the operator

Source https://stackoverflow.com/questions/61194177

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install CtCI-6th-Edition

You can download it from GitHub.
You can use CtCI-6th-Edition like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the CtCI-6th-Edition component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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