ctci | Cracking the Coding Interview , 5th Edition | Learning library

 by   careercup Java Version: Current License: No License

kandi X-RAY | ctci Summary

kandi X-RAY | ctci Summary

ctci is a Java library typically used in Tutorial, Learning, Example Codes applications. ctci has no bugs, it has no vulnerabilities and it has medium support. However ctci build file is not available. You can download it from GitHub.

Solutions for "Cracking the Coding Interview v5". Adding equivalent solutions in Objective-C Adding my own solutions.
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            kandi-support Support

              ctci has a medium active ecosystem.
              It has 5079 star(s) with 2342 fork(s). There are 530 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 32 open issues and 6 have been closed. On average issues are closed in 341 days. There are 33 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of ctci is current.

            kandi-Quality Quality

              ctci has 0 bugs and 0 code smells.

            kandi-Security Security

              ctci has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              ctci code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              ctci does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              ctci releases are not available. You will need to build from source code and install.
              ctci has no build file. You will be need to create the build yourself to build the component from source.
              ctci saves you 9590 person hours of effort in developing the same functionality from scratch.
              It has 19578 lines of code, 1770 functions and 566 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed ctci and discovered the below as its top functions. This is intended to give you an instant insight into ctci implemented functionality, and help decide if they suit your requirements.
            • Test program
            • Main method for testing
            • This is the main method for debugging
            • Delete a random node
            • Select random cards
            • Prints the sub - square
            • Test entry point
            • Print a random matrix
            • Command - line entry point
            • Simple test test
            • Entry point for example
            • Main method
            • Binary test
            • Entry point for testing
            • Entry point for debugging
            • Tests ranks
            • Entry point for the example
            • Demonstrates how to create an ordered list
            • Runs a stand - alone test
            • Example of debugging
            • Prints two matrices
            • Command line tool
            • The main method for testing
            • Test to see if the tree is a leaf node
            • Main method for testing
            • The main method
            • Test function
            • Simple test program
            • Prints binary
            • Prints out the given string
            • Demonstrates how to compare two words
            Get all kandi verified functions for this library.

            ctci Key Features

            No Key Features are available at this moment for ctci.

            ctci Examples and Code Snippets

            Find path to the path of the maze .
            javascriptdot img1Lines of Code : 20dot img1no licencesLicense : No License
            copy iconCopy
            function findPath(maze, row, column, path = [], failedPoints = new Set()) {
              if (column < 0 || row < 0 || !maze[row][column]) return null;
            
              const isAtOrigin = !row && !column,
                    point = `(${row}, ${column})`;
            
              if (failedPoint  
            1 step 1
            javascriptdot img2Lines of Code : 20dot img2no licencesLicense : No License
            copy iconCopy
            function tripleStepBU(steps) {
              if (steps <= 2) {
                if (steps < 0) return 0;
                else if (steps === 0) return 1;
                else return steps;
              }
            
              let a = 1, // One step
                  b = 2, // Two steps
                  c = 4; // Three steps
            
              for (let i = 4; i   
            Prints the towers of the honic stack .
            javascriptdot img3Lines of Code : 15dot img3no licencesLicense : No License
            copy iconCopy
            function printTowersOfHanoi(numRings, startStack = 'start', endStack = 'last') {
              if (numRings > 0) {
            
                const availableSpot = ['start', 'middle', 'last']
                                      .filter(stack => stack !== startStack && stack !== e  

            Community Discussions

            QUESTION

            Github personal access token
            Asked 2021-Aug-14 at 14:14

            I just found out that from the 13th that support for password authentication was removed, and instead, I should use a personal access token. I generated the token and followed the steps in the link provided in the terminal but it still gives me some issues when I am trying to push. Does anyone know why?

            ...

            ANSWER

            Answered 2021-Aug-14 at 14:14

            That could mean your old credential (password) is still stored in the Git credential helper.

            Check the output of git config --global credential.helper: it could have cached another user/email/password.
            If that setting is xxx, type:

            Source https://stackoverflow.com/questions/68783641

            QUESTION

            code work in intellij but not hackerrank ide
            Asked 2021-May-27 at 16:19

            I'm doing this question on hackerrank: https://www.hackerrank.com/challenges/ctci-bubble-sort/problem?h_l=interview&playlist_slugs%5B%5D=interview-preparation-kit&playlist_slugs%5B%5D=sorting

            I wrote the solution in intellij, and it gives me the correct output there, but when I copied it over to the hackerrank ide, it gave me an error.

            This is the code I'm talking about:

            ...

            ANSWER

            Answered 2021-May-27 at 16:04

            You have put the Solution class within your Result class. HackerRank wants you to put the Solution class as its own class, like this:

            Source https://stackoverflow.com/questions/67725856

            QUESTION

            Tests failing on Hackerrank but answer correct
            Asked 2021-May-21 at 11:54

            I have the following solution:

            ...

            ANSWER

            Answered 2021-May-21 at 11:54

            after testing this for about an hour or so, I realized where you're mistaken. Namely, using prn instead of print prints out the quote characters alongside the actual text. This was a surprise to me, since I always thought that these two are interchangeable. If you change your prns to printlns, you should be okay.

            The final code that I created which passed all of the tests:

            Source https://stackoverflow.com/questions/67545956

            QUESTION

            Java Hackerank left array Rotation
            Asked 2020-Sep-09 at 14:53

            We have a method in which an array and number of rotations are passed as input and we have to return the array after left rotations. Here is my solution.

            ...

            ANSWER

            Answered 2020-Sep-09 at 14:51

            When you do the following:

            Source https://stackoverflow.com/questions/63814155

            QUESTION

            What if I just dont visit the children of the queue_front node but just push them into the queue? Will it still be BFS?
            Asked 2020-Aug-01 at 07:31

            https://www.hackerrank.com/challenges/ctci-bfs-shortest-reach/problem In this problem, I tried BFS by just (first approach) visiting the queue_front node and pushing its children into the queue and not visiting its children nodes instead of (second approach) visiting all its children and then pushing them into the queue. In the first approach, the test cases failed, but in the second approach, it passed. But in both the cases I am using BFS. So why is it failing then. The code is below.In this code first approach is enabled which is failing some test cases in the above hackerrank problem. The second approach passes all the test cases. Please look at the bfs function. I am using adjacency list to implement graph. PLEASE HELP!! THANK YOU!!

            ...

            ANSWER

            Answered 2020-Aug-01 at 07:31

            Visiting nodes when you pop them out of the queue will be same as dfs it will not ensure you shortest path.if you will visit nodes then push it into the queue it will give you the shortest path consider the case :

            node 1 is connected to node 2 and node 2 with node3 and node3 with node1 in a cyclic form

            we will use a queue> q; first element of pair is the node and second element is distance to the node from start.

            Case 1: this is a cyclic graph with start node as 1 we want to find min distance from 1 to 3.we push 1 into queue.we will pop it out and push node 2 and 3 into the queue without visiting it.when we will pop out 2 then we visit 2 and push 3 so when we pop out 3 we will check it the popped node is equal to 3 and we store the min distance.so in this case our min distance is 2.which we have find out using depth traversal.

            But the answer should be 1 as 1 is directly connected with 3.

            case 2:we will visit the node before pushing it into queue

            start node is 1 and push it.visit 2 and 3 and then push both into stack.when we will pop node 2 we check the adjacent elements and both 3 and 2 are visited.so we will pop 3 and check if it is destination node.so we will store the distance.so in this case dist[1] to dist[3]=0+1 which is 1.

            Source https://stackoverflow.com/questions/62891955

            QUESTION

            What makes the 'getCharNumber' method case-insensitive while it only every checks for lowercase (by author of CtCI)
            Asked 2020-Jul-13 at 08:20
            public class Common {
            
                public static int getCharNumber(Character c) {
                    int a = Character.getNumericValue('a');
                    int z = Character.getNumericValue('z');
                    
                    int val = Character.getNumericValue(c);
                    if (a <= val && val <= z) {
                        return val - a;
                    }
                    return -1;
                }
                
                public static int[] buildCharFrequencyTable(String phrase) {
                    int[] table = new int[Character.getNumericValue('z') - Character.getNumericValue('a') + 1];
                    for (char c : phrase.toCharArray()) {
                        int x = getCharNumber(c);
                        if (x != -1) {
                            table[x]++;
                        }
                    }
                    return table;
                }
            }
            
            ...

            ANSWER

            Answered 2020-Jul-13 at 08:20

            Why is the getCharNumber case-insensitive?

            The getCharNumber method uses Java's Character#getNumericValue(char) method for which its JavaDoc states in particular:

            The letters A-Z in their uppercase ('\u0041' through '\u005A'), lowercase ('\u0061' through '\u007A'), and full width variant ('\uFF21' through '\uFF3A' and '\uFF41' through '\uFF5A') forms have numeric values from 10 through 35. This is independent of the Unicode specification, which does not assign numeric values to these char values.

            Meaning that for example for character A and a this API method returns the same value, i.e. 10, and thus there's no case-sensitivity.

            For reference, see also

            Source https://stackoverflow.com/questions/62867433

            QUESTION

            Hackerrank Python3 Hash Tables: Ransom Note and dictionary comprehension
            Asked 2020-Jun-11 at 14:44

            I am learning Python, and i use it to solve tasks on HackerRank. I have the problem with exercise Hash Tables: Ransom Note. I have written that code:

            ...

            ANSWER

            Answered 2020-Jun-11 at 14:44

            You cannot referenze the varible your dict comp is assigned to inside itself - it does not update "iteratively".

            It is easy to show:

            Source https://stackoverflow.com/questions/62326895

            QUESTION

            Space complexity of a recursive algorithm from the CTCI book
            Asked 2020-May-01 at 08:25

            I am going through the CTCI book and can't understand one of their examples. They start with:

            ...

            ANSWER

            Answered 2020-May-01 at 08:24

            Unlike the time complexity, which is simply a total time that is needed to run a program, the space complexity describes the space required to execute the program. So it doesn't really matter that there are 2n nodes in the execution tree of the program. The call stack automatically folds and releases the additional memory used. What matters is the maximal depth of the call tree, which is O(n) for this program. Should be noted, though, that recursion is a special case that naturally releases any used memory upon stack fold. If memory is allocated explicitly during runtime, it should be released explicitly as well.

            Regarding the first example, the call tree is simply a list of depth n, resulting in similar complexity of O(n).

            Source https://stackoverflow.com/questions/61538037

            QUESTION

            I have written an anagrams finder that has a double for loop - how do I increase the efficiency of this code?
            Asked 2020-Apr-29 at 11:39

            In response to the Hackerank problem: https://www.hackerrank.com/challenges/ctci-making-anagrams/problem where one must find the number, as an integer, of characters to be removed from a string to make it an anagram of another string.

            I have completed the code and the program passes the tests but I am wanting help with increasing its efficiency. How do I go about thinking how to improve the efficiency of the following code?

            ...

            ANSWER

            Answered 2020-Apr-29 at 11:39

            First rule of optimization: Avoid unnecessary operations:

            • Like calling to contains before calling add.

            Second rule of optimization: If you want it faster, you'd better lean on memory:

            • Do not call the same function several times with the same input values: Better call only once, store the value in a local variable, and use it afterwards.
            • Also, computing the number of occurrences of a character in a string is not efficient (the longer the strings, the least efficient): Better create a map for each string, mapping each character to a number of occurrences.
            • Dave's suggestion about how to optimize such maps is interesting, too.

            Source https://stackoverflow.com/questions/61482502

            QUESTION

            What does $1 ++ $0 mean in the closure for Swift?
            Asked 2020-Apr-13 at 18:36

            I was looking at the code for how to remove duplicates from a list and I came upon some syntax I am unfamiliar with. What does $1 ++ $0 mean?

            ...

            ANSWER

            Answered 2020-Apr-13 at 18:36

            $0 is the first parameter passed into the closure.

            $1 is the second parameter.

            ++ is a custom infix operator

            Source https://stackoverflow.com/questions/61194177

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install ctci

            You can download it from GitHub.
            You can use ctci like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the ctci component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/careercup/ctci.git

          • CLI

            gh repo clone careercup/ctci

          • sshUrl

            git@github.com:careercup/ctci.git

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