Express | js bot for music and moderation | Bot library

 by   ItzLightyHD JavaScript Version: v1.3.0 License: MIT

kandi X-RAY | Express Summary

kandi X-RAY | Express Summary

Express is a JavaScript library typically used in Automation, Bot, Discord applications. Express has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Express is a music and moderation bot with simple commands and made in discord.js.
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              Express has a low active ecosystem.
              It has 59 star(s) with 32 fork(s). There are 8 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 5 have been closed. On average issues are closed in 21 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Express is v1.3.0

            kandi-Quality Quality

              Express has no bugs reported.

            kandi-Security Security

              Express has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Express is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Express releases are available to install and integrate.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Express
            Get all kandi verified functions for this library.

            Express Key Features

            No Key Features are available at this moment for Express.

            Express Examples and Code Snippets

            No Code Snippets are available at this moment for Express.

            Community Discussions

            QUESTION

            How to print ggplot for multiple tables in this case?
            Asked 2021-Jun-15 at 22:10

            I have this code which prints multiple tables

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:59

            So, this is a good opportunity to use purrr::map. You are half way there by applying code to one dataframe.

            You can take the code that you have written above and put it into a function.

            Source https://stackoverflow.com/questions/67992308

            QUESTION

            Primary expression error when defining a vector with ternary operator
            Asked 2021-Jun-15 at 21:48

            I have a simple code where I try to define a vector as one of two initializer lists using a ternary operator:

            ...

            ANSWER

            Answered 2021-Jun-15 at 21:48

            Because you can't have braces in that context. If you look at cppreference on list initialization, you see that the case inside a ternary operator isn't defined. So it can't be parsed correctly and you get the error you have.

            You'd have to use something like this :

            Source https://stackoverflow.com/questions/67993769

            QUESTION

            How to make substring optional Kotlin regex
            Asked 2021-Jun-15 at 21:32

            I am practicing regular expressions in Kotlin and trying to start with a multiline string. However, I am not receiving any matches. I feel like I am doing it right and can't figure out the problem.

            Test lines:

            ...

            ANSWER

            Answered 2021-Jun-15 at 21:32

            QUESTION

            What are the differences between GNU grep's basic/extended and PCRE (`-P`) regular expressions?
            Asked 2021-Jun-15 at 20:55

            GNU grep's basic (BRE) and extended (ERE) syntax is documented at https://www.gnu.org/software/grep/manual/html_node/Regular-Expressions.html and PCRE is summarized at man pcresyntax, but there is no explicit comparison. What are the differences between GNU grep's basic/extended and PCRE (-P) regular expressions?

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:55

            My research of the major syntax and functionality differences from http://www.greenend.org.uk/rjk/tech/regexp.html:

            Perl supports much more additional functionality:

            • "nongreedy {}" with syntax re{...}?
            • additional anchors and character types \A, \C, \d, \D, \G, \p, \P, \s, \S, \X. \Z, \z.
            • (?#comment)
            • shy grouping (?:re), shy grouping + modifiers (?modifiers:re)
            • lookahead and negative lookahead (?=re) and (?!re), lookbehind and negative lookbehind (?<=p) and (?
            • Atomic groups (?>re)
            • Conditional expression (?(cond)re)
            • ... and more, see man pcresyntax

            Source https://stackoverflow.com/questions/67943781

            QUESTION

            Comparing Week of Year with "overflow"
            Asked 2021-Jun-15 at 20:49

            So I want to be able to look at a specific week of the year and look at all data in the preceding and following 6 weeks.

            WHERE t1.weeknum >= week-6 AND t1.weeknum <=week+6

            So if week is 20, I want to return everything between 14 and 26.

            The problem is weeks >=47 and <=6. For instance, if week is 4, I want the range to be 50 through 10. Years are a separate dimension and I am including all data regardless of year.

            I think this would be similar to a compass heading. Say you are at 350 degrees and turn right 30 degrees. 350+30 = 20 degree bearing.

            I'm using SQL Server Express

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:11

            The Modulus operator (%) seems to be what you want. Since you are using the range 1 to 52 to represent week numbers you need to shift the range to 0 to 51 while calculating:

            Source https://stackoverflow.com/questions/67990100

            QUESTION

            JLEX lexical generator error: unterminated string at the end of the line
            Asked 2021-Jun-15 at 20:46

            I am generating lexical analyzer with JLEX. I found a regular expression for string literal from this link and used it in .jflex file same of other expressions. but it gives me this error : unterminated string at the end of the line
            StringLiteral = \"(\\.|[^"\\])*\"

            can anyone help me please, thanks.

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:46

            The regular expression you copied is for (f)lex, which uses a slightly different syntax for regular expressions. In particular, (f)lex treats " as an ordinary character inside bracketed classes, so [^"\\] is a character class matching anything other than (^) a quotation mark (") or a backslash (\\).

            However, in JFlex, the " is a quoting character, whether outside or inside brackets. So the " in the character class is unterminated. Hence the error message.

            So you need to backslash-escape it:

            Source https://stackoverflow.com/questions/67991038

            QUESTION

            what is the best regular expression to replace non numeric character in a string preceded by certain phrase in python?
            Asked 2021-Jun-15 at 20:02

            I have to parse lists of names, addresses, etc. that were OCRed and have invalid/incorrect characters in them and on the state postal code I need to recognize the pattern with a 2 character state followed by a 5 digit postal code and replace any non numeric characters in the postal code. I might have OK 7-41.03 at the end of a string I need to remove the hyphen and period. I know that re.sub('[^0-9]+', '', '7-41.03') will remove the desired characters but I need it only replace characters in numbers when found at the end of the string and only if preceded by a two character state wrapped in spaces like OK. It seems if I add anything to the regular expression as far as a lookbehind expression then I can't seem to get the characters replaced. I've come up with the following but I think there must be a simpler expression to accomplish this. Example:

            ...

            ANSWER

            Answered 2021-Jun-15 at 20:02

            You need to make use of re.sub callbacks:

            Source https://stackoverflow.com/questions/67990895

            QUESTION

            How to use a generic method to remove outliers only if they exist in R
            Asked 2021-Jun-15 at 19:58

            I am using a method to remove univariate outliers. This method only works if the vector contains outliers.

            How is it possible to generalize this method to work also with vectors without outliers. I tried with ifelse without success.

            ...

            ANSWER

            Answered 2021-Jun-15 at 19:58

            Negate (!) instead of using - which would work even when there are no outliers

            Source https://stackoverflow.com/questions/67992709

            QUESTION

            Lifetime of async closure return type
            Asked 2021-Jun-15 at 18:22

            Consider the following code:

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:22

            i think you are looking for this:

            Source https://stackoverflow.com/questions/67991159

            QUESTION

            Moq System.NotSupportedException
            Asked 2021-Jun-15 at 18:09

            I get it again and again

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:09

            You have to make the property overridable, so make it virtual:

            Source https://stackoverflow.com/questions/67991390

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Express

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

            Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items

            Find more libraries

            Stay Updated

            Subscribe to our newsletter for trending solutions and developer bootcamps

            Agree to Sign up and Terms & Conditions

            Share this Page

            share link