StackUnderflow | Tampermonkey script | Browser Plugin library

by MarcinOrlowski JavaScript Version: v1.2.1 License: No License

X-Ray Key Features Code Snippets Community Discussions(5)Vulnerabilities Install Support

kandi X-RAY | StackUnderflow Summary

StackUnderflow is a JavaScript library typically used in Plugin, Browser Plugin applications. StackUnderflow has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

StackUnderflow is Greasemonkey/Tampermonkey (or compatible) user script that aims to improve your experience with StackExchange sites like StackOverflow.com, ServerFault.com, SuperUser.com, StackApps.com and StackExchange.com.

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Quality

Security

License

Reuse

Support

StackUnderflow has a low active ecosystem.

It has 14 star(s) with 2 fork(s). There are 1 watchers for this library.

It had no major release in the last 12 months.

There are 6 open issues and 5 have been closed. On average issues are closed in 72 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of StackUnderflow is v1.2.1

Quality

StackUnderflow has no bugs reported.

Security

StackUnderflow has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

StackUnderflow does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

StackUnderflow releases are available to install and integrate.

Installation instructions are available. Examples and code snippets are not available.

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StackUnderflow Key Features

No Key Features are available at this moment for StackUnderflow.

StackUnderflow Examples and Code Snippets

No Code Snippets are available at this moment for StackUnderflow.

Community Discussions

Trending Discussions on StackUnderflow

Stack implementation java

Stack implementation using arrays java

Unable to implement Stack using Java

how to clean a query string in a URL?

$uibModal templateUrl does not change modal content

QUESTION

Stack implementation java

Asked 2020-Jul-04 at 12:09

Unable to implement stack through this code...

UseStack.java

...

ANSWER

Answered 2020-Jul-04 at 12:09

pop() is not working because you are using different objects for push and pop.

You don't need to define another class for push and pop, they are operation add those function inside Stack class.

Source https://stackoverflow.com/questions/62728760

QUESTION

Stack implementation using arrays java

Asked 2020-Jul-04 at 08:10

I am unable to implement stack using array in Java through this code as my push() is unable to store value in the array...

UseStack

...

ANSWER

Answered 2020-Jul-04 at 08:08

You are creating new object every time when push and show in switch case, then always top is initialized by -1 before operation

Source https://stackoverflow.com/questions/62726569

QUESTION

Unable to implement Stack using Java

Asked 2020-Jul-03 at 13:20

I am unable to understand why my value is not storing in the stack..

UseStack.java

...

ANSWER

Answered 2020-Jul-03 at 12:56

In Push.java you need to initialize the obj Scanner, for example

Source https://stackoverflow.com/questions/62715793

QUESTION

how to clean a query string in a URL?

Asked 2019-Aug-14 at 13:29

Consider this simple example

www.stackunderflow.com?q=snack%20over%20flow

I am interested in parsing the query string of the url. However, as you can see, I have these annoying URL encoding strings (such as %20) that I need convert.

How can I do that in R? I would like to obtain a clean string such as snack over flow. I know how to get the query part :

...

ANSWER

Answered 2019-Aug-14 at 12:46

One with sub and gsub. Using sub extract the part after "?q=" and with gsub remove the "%" followed by a number and replace it with empty space.

Source https://stackoverflow.com/questions/57494962

QUESTION

$uibModal templateUrl does not change modal content

Asked 2019-Jan-23 at 20:28

all! I'm making an angular application and want to implement a simple modal window popup, that will allow users to "construct" a URL.

My page looks like this:

Here's the HTML of the URL button (third in row) that is to trigger my button.

...

ANSWER

Answered 2019-Jan-23 at 20:28

The error might be hidden in the reference of the html file.

Make sure that the parent directory of the /url_modal/ directory is set as the root folder you set with express.static function call.

Source https://stackoverflow.com/questions/54162738

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install StackUnderflow

To enjoy StackUnderflow you need to.
install user script host extension for your web browser: Chrome and compatible browsers - Tampermonkey Firefox - Greasemonkey
install StackUnderflow script: Get Official, stable version by clicking here If you are brave, you may try Development version by clicking here
script will be fetched, installed and ready to use. No browser restart required. If you got some SO's pages opened, you need to reload them for script to kick off though.

Support

I created this script with my needs in mind, however I hope you find it useful too. I am also open for new features ideas or code! If you find a bug, feel free to report it or even send pull request. If you miss a feature, use GitHub issues tracker to let me know.

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