OpenList | Chrome extension to open a list of URLs or search terms | Browser Plugin library

by cdzombak JavaScript Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | OpenList Summary

OpenList is a JavaScript library typically used in Plugin, Browser Plugin applications. OpenList has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

OpenList helps you manage lists of URLs. It's useful if you have a habit of emailing yourself lists of articles or pages to check out later.

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Quality

Security

License

Reuse

Support

OpenList has a low active ecosystem.

It has 52 star(s) with 12 fork(s). There are 6 watchers for this library.

It had no major release in the last 6 months.

There are 3 open issues and 8 have been closed. On average issues are closed in 137 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of OpenList is current.

Quality

OpenList has 0 bugs and 0 code smells.

Security

OpenList has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

OpenList code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

OpenList is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

OpenList releases are not available. You will need to build from source code and install.

Installation instructions are available. Examples and code snippets are not available.

OpenList saves you 10 person hours of effort in developing the same functionality from scratch.

It has 30 lines of code, 0 functions and 5 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed OpenList and discovered the below as its top functions. This is intended to give you an instant insight into OpenList implemented functionality, and help decide if they suit your requirements.

Open a list of strings
Initializes the popup
Determine if a string is a url
Opens textarea list

Get all kandi verified functions for this library.

OpenList Key Features

No Key Features are available at this moment for OpenList.

OpenList Examples and Code Snippets

No Code Snippets are available at this moment for OpenList.

Community Discussions

Trending Discussions on OpenList

Prepare the Bunnies Escape - Foobar

`useTheme` must be used within `NativeBaseConfigProvider`

A*(A-star) algorithm gives wrong path and crashes

Calculate the f cost in A*(A-star) algorithm on coordinated undirected graph

How to add trigger key to my javascript project

"Encountered two children with the same key, `[object Object]`."

why does my a star algorithm not work in javascript?

Beautiful Soup returning None

A-Star Search Algorithm won't find a valid path

Why is my path moving in the opposite direction of the heuristic functions in A Star Algorithm?

QUESTION

Prepare the Bunnies Escape - Foobar

Asked 2022-Mar-27 at 20:23

I've been at this for a while and for the life of me I cannot figure out why I cannot pass test cases 4 and 5. My code is below, including my own custom test cases that all execute and pass in under 5ms.

Basically I added a third dimension to each node's position that represents whether a wall has already been traversed or not. When analyzing each current node's neighbor, if it's a wall and the current node has a zero for its third coordinate, then moving to the wall and to a 1 on the third coordinate becomes an option. On paper, it works great. In my own IDE, it works great.

I'm starting to wonder if there's something in here that's Python 3 and not working correctly in foobar or something. I'd appreciate any help.

...

ANSWER

Answered 2022-Mar-27 at 20:23

So I figured it out. The line

Source https://stackoverflow.com/questions/71639714

QUESTION

`useTheme` must be used within `NativeBaseConfigProvider`

Asked 2022-Mar-27 at 13:28

In my project I faced the above error can anyone tell me how to solve this error.

The error I faced is:

Error: useTheme must be used within NativeBaseConfigProvider

This error is located at:

...

ANSWER

Answered 2022-Mar-20 at 13:59

in your app.js import NativeBaseProvider and wrap your other components around it

Source https://stackoverflow.com/questions/71540355

QUESTION

A*(A-star) algorithm gives wrong path and crashes

Asked 2021-Nov-07 at 15:41

I'm implementing A*(A-star) algorithm in react.js but my program crashes whenever startNode(green) or destinationNode(blue) have more than one neighbour or if there is a cycle in the graph. There is something wrong when adding and deleting the neighbours from/to openList or when updating the parentId in the getPath() function. I cant even see the console because the website goes down. Each node has: id, name, x, y, connectedToIdsList:[], gcost:Infinity, fcost:0, heuristic:0, parentId:null. I'm sending the path to another component "TodoList" which prints out the path. My program should not return the path but keeps updating the path as i'm adding nodes and edges to the list. Please help, I've been stuck for hours now:/

My code:

...

ANSWER

Answered 2021-Nov-06 at 18:34

There are a few issues in your code:

return originLocationId; should not happen. When the source is equal to the target, then set the path, and make sure the final return of this function is executed, as you want to return the div element.
When the target is found in the loop, not only should the path be built, but the loop should be exited. So add a break
currentNode.gcost = currentNode.gcost + manhattanDistance(currentNode, neighbourNode); is not right: you don't want to modify currentNode.gcost: its value should not depend on the outgoing edge to that neighbour. Instead store this sum in a temporary variable (like gcost)
The comparison with neighbourNode.gcost will not work when that node does not yet have a gcost member. I don't see in your code that it got a default value that makes sure this condition is true, so you should use a default value here, like (neighbourNode.gcost ?? Infinity)
path = path.reverse().join("->"); should better be executed always, also when there is no solution (so path is a string) or when the source and target are the same node.

Here is a corrected version, slightly adapted to run here as a runnable snippet:

Source https://stackoverflow.com/questions/69865950

QUESTION

Calculate the f cost in A*(A-star) algorithm on coordinated undirected graph

Asked 2021-Nov-05 at 20:39

I'm trying to implement A* algorithm in react.js but I'm quite stuck when it comes to implement the fScore function. I know that f=g+h where g is the gScore from the start node till the current node and h is the heuristic distance from the currentNode till the end node. I calculated the heuristic using the euclidean distance where I'm sending the coordinates of the current and End nodes but I don't know how to calculate the gScore. Each node in my graph has: id, name, x, y, connectedToIds:[] //list of neihbours or connectedNodes. Update: I added the variables parentId, fscore, gscore, hscore to each node. So now each node has the variables : id, name, x, y, connectedToIds:[], fscore: 0, gscore: 0, hscore: 0, parentId: null. Update2: originLocationId is the id of the start node. destinationLocationId is the id of the end node. locations is a list of all nodes. my code:

...

ANSWER

Answered 2021-Nov-05 at 14:58

While h is the heuristic, a plausible guess of the possible cost it will be needed to reach the end node, g is the actual cost spent to reach the current node. In your case it could be even the same euclidian distance you use for h.

In a real case scenario, using euclidian distance, a graph connecting different cities, h is the air-distance of two cities while g is their road-distance.

Furthermore, if you are using a monotonic heuristic (or an underestimating heuristic, such as the euclidian distance) you will not need the close list, since it is provent that the first found path will also be the shortest: longer or already visited paths will be dropped before being explored.

Probably what is confusing is the fact that you need to keep track of g during the exploration of the graph, while h just measure a straight line between current and end nodes, g measure all the lines between the nodes you explored to reach the current.

Source https://stackoverflow.com/questions/69846782

QUESTION

How to add trigger key to my javascript project

Asked 2021-Jul-06 at 08:15

How can I add trigger key to my button when I add something to input area?

My code:

...

ANSWER

Answered 2021-Jul-06 at 08:15

To add event listener on keyboard's events you can use the keydown event and then filter the events based on the keyCodes

Here an example working when pressing enter:

Source https://stackoverflow.com/questions/68266641

QUESTION

"Encountered two children with the same key, `[object Object]`."

Asked 2021-Apr-21 at 12:00

I tried making a category filter for my ecommerce app but it keeps giving me this error. I have not connected my app to a database and i am using a json file. I dont have dublicate id's in my json files.

this is my products json file

This is my categories json file

This is my CategoryFilter.js

...

ANSWER

Answered 2021-Apr-21 at 12:00

Here:

Source https://stackoverflow.com/questions/67194264

QUESTION

why does my a star algorithm not work in javascript?

Asked 2021-Apr-15 at 21:40

function algorithm(){
if(startPoint === true && endPoint === true){
//add the heuristic distance to the start position from the final position
startPosition.h = distance([startPosition.x, startPosition.y]);

let openList = []

openList.push(startPosition)
let closedList = []
  while (openList.length > 0){
    //print(openList)
    lowPos = 0;
    for(let i = 0; i < openList.length; i++){
      if(openList[i].f < openList[lowPos].f){
        lowPos = i;
      }
    }
    let currentPosition = openList[lowPos];
    //currentPosition.check()
    //if the currentPosition is the endPosition, retrace steps and find the path, then return this path
    if(currentPosition === endPosition){
      let curr = currentPosition;
      let ret = [];
      while(curr.parent != null){
        curr.path()
        ret.push(curr);
        curr = curr.parent;
      }
      endPosition.end()
      return ret.reverse();
    }
    openList.splice(lowPos, 1);
    closedList.push(currentPosition);
    let neighbours = neighbors(currentPosition);
    for(let i = 0; i < neighbours.length; i++){
      let neighbour = neighbours[i];
      if(closedList.includes(neighbour) || neighbour.colour == "black"){
        continue;
      }
      neighbour.check()
      let gScore = currentPosition.g + 1;
      let gScoreBest = false;
      if(openList.includes(neighbour) == false){
        gScoreBest = true;
        neighbour.h = distance([neighbour.x, neighbour.y]);
        openList.push(neighbour);
      }
      else if(gScore < neighbour.g){
        gScoreBest = true;
      }
      if(gScoreBest == true){
        neighbour.parent = currentPosition;
        neighbour.g = gScore;
        neighbour.f = neighbour.g + neighbour.h;
      }
    }
  }
}
 //meaning that either the path is not possible or the final node/initial node 
 has not yet been placed.
 return [];
}

...

ANSWER

Answered 2021-Apr-13 at 12:34

It looks like you are not checking the diagonals. It is not a mistake. You are doing great.

Source https://stackoverflow.com/questions/67060406

QUESTION

Beautiful Soup returning None

Asked 2021-Mar-05 at 21:46

I am trying to scrape the th element, but the result keeps returning None. What am I doing wrong?

This is the code I have tried:

...

ANSWER

Answered 2021-Mar-05 at 21:14

I think the request object doesn't have a text attribute. Try soup = bs4.BeautifulSoup(r.content, 'lxml')

Source https://stackoverflow.com/questions/66499663

QUESTION

A-Star Search Algorithm won't find a valid path

Asked 2021-Feb-07 at 15:03

I'm trying to implement an A* algorithm for pathfinding in my 3D grid. I've been following a tutorial but I'm not getting a valid path. I've stepped through my code to find out what's going on, but I don't know how to solve the problem. For the most basic test I'm just using a 2-D grid (it's 3-D, but there's only one Z option, so basically 2-D).

Here's what it's doing:

So we start at 0,0 (orange) and want to get to 1,2 (green). First it calculates the two options for the orange square, north and east, and gets distances of 2 and 1.414 for F values of 3 and 2.414. It moves to the east square (0,1). Great. But now it calculates the two open squares from 0,1 which are 1,1 and 0,2, both of which have a g value of 2 and an h value (distance) of 1, making their F values both be 3.

Since their F values are 3 and we already have an option with an F value of 3 (1,0 from the starting point), these two options are ignored even though they are clearly the best options.

It then continues onward and switches to moving to 1,0 where it then calculates 1,1 as 3 again and 2,0 as 4.236. 1,1's f value is not bigger than our current f value though, so it's ignored and we move upward to 2,0.

2,0 can only move right so it does.

2,1 can only move down since 2,2 is an invalid square, but the f value of moving to 1,1 is saved as 3, so it's again ignored, leaving us with no valid path between 0,0 and 1,2. What am I missing?

Here's a snippet of my path loop. There's a bunch of custom structs in here, and I'm using TMap from Unreal Engine to store my closed list, but I don't think that matters to the question. Here's a quick and dirty about what these structs are:

PCell: Holds cell coordinates
PPair: Holds cell coordinates as a PCell and an F value
FVectorInt: 3-D integer vector
FPathCell: Holds parent coordinates, and f, g, and h values.
cellDetails is a 3D dynamic array of FPathCell
closedMap is a TMap with as

Also locationIsWalkable(FVectorInt, StepDirection) is just code that checks to see if the player can walk to a cell from a certain direction. You can ignore that part.

...

ANSWER

Answered 2021-Feb-07 at 15:03

Since their F values are 3 and we already have an option with an F value of 3 (1,0 from the starting point), these two options are ignored even though they are clearly the best options.

This must be your mistake. These options shall not be 'ignored', but rather 'delayed till they are the next-best options'. The way it's done is that on every iteration of A* you ought to select the open cell with the lowest F-score.

In your example, once you expand 0,1 (to get 0,2 and 1,1), your open set should look like:

Source https://stackoverflow.com/questions/66077980

QUESTION

Why is my path moving in the opposite direction of the heuristic functions in A Star Algorithm?

Asked 2021-Jan-11 at 17:27

Background

I want to implement an A-Star Algorithm with a GUI for user input to set the start and end node, and draw obstacles. However, I have spent a great deal of time pondering why the Algorithm isn't working.

Issue

The path goes in the opposite direction of the end node and to the corner of the matrix. For example, if start: 2,2 and end: 8,8 the path will map to the origin: 0,0 and vice versa.

Troubleshooting

I have already checked all the areas that I could possibly think is going wrong and even referring to source code from a medium article: A-Star Algorithm by Nicholas Swift

Euclidean distance is not negative
Adjacent nodes are not out of bounds
Other smaller troubleshoot

The obstacles on the graph have not yet been implemented because I was trying to get the path to map correctly before adding additional complexity to the motivating problem.

I simply cannot see where I am going wrong. I come from a Java background so there could be some basic Python syntax that is escaping me and making everything break. Any suggestions will be appreciated.

Source code:

...

ANSWER

Answered 2021-Jan-11 at 17:27

As pointed out by user @Ghoti the issue was a simple comparison error in the algorithm. With the current comparison statement in the code above the first node in the adjNode list is always selected.

Source https://stackoverflow.com/questions/65634821

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install OpenList

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