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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Constraint
Constraint Key Features
Constraint Examples and Code Snippets
def _find_max_under_constraint(self, constrained, dependent, predicate):
"""Returns the maximum of dependent_statistic that satisfies the constraint.
Args:
constrained: Over these values the constraint
is specified. A rank-1 te
def get(identifier):
if identifier is None:
return None
if isinstance(identifier, dict):
return deserialize(identifier)
elif isinstance(identifier, str):
config = {'class_name': str(identifier), 'config': {}}
return deserialize(
def _SatisfiesTypeConstraint(dtype, attr_def, param_name):
if attr_def.HasField("allowed_values"):
allowed_list = attr_def.allowed_values.list.type
allowed_values = ", ".join(dtypes.as_dtype(x).name for x in allowed_list)
if dtype not i
Community Discussions
Trending Discussions on Constraint
QUESTION
This works and outputs "1", because the function's constraints are partially ordered and the most constrained overload wins:
...ANSWER
Answered 2022-Mar-29 at 18:45C++20 recognizes that there can be different spellings of the same effective requirements. So the standard defines two concepts: "equivalent" and "functionally equivalent".
True "equivalence" is based on satisfying the ODR (one-definition rule):
Two expressions involving template parameters are considered equivalent if two function definitions containing the expressions would satisfy the one-definition rule, except that the tokens used to name the template parameters may differ as long as a token used to name a template parameter in one expression is replaced by another token that names the same template parameter in the other expression.
There's more to it, but that's not an issue here.
Equivalence for template heads includes that all constraint expressions are equivalent (template headers include constraints).
Functional equivalence is (usually) about the results of expressions being equal. For template heads, two template heads that are not ODR equivalent can be functionally equivalent:
Two template-heads are functionally equivalent if they accept and are satisfied by ([temp.constr.constr]) the same set of template argument lists.
That's based in part on the validity of the constraint expressions.
Your two template heads in versions 1 and 3 are not ODR equivalent, but they are functionally equivalent, as they both accept the same template parameters. And the behavior of that code will be different from its behavior if they were ODR equivalent. Therefore, this passage kicks in:
If the validity or meaning of the program depends on whether two constructs are equivalent, and they are functionally equivalent but not equivalent, the program is ill-formed, no diagnostic required.
As such, all of the compilers are equally right because your code is wrong. Obviously a compiler shouldn't straight-up crash (and that should be submitted as a bug), but "ill-formed, no diagnostic required" often carries with it unforeseen consequences.
QUESTION
Now that type parameters are available on golang/go:master
, I decided to give it a try. It seems that I'm running into a limitation I could not find in the Type Parameters Proposal. (Or I must have missed it).
I want to write a function which returns a slice of values of a generic type with the constraint of an interface type. If the passed type is an implementation with a pointer receiver, how can we instantiate it?
...ANSWER
Answered 2021-Oct-15 at 01:50Edit: see blackgreen's answer, which I also found later on my own while scanning through the same documentation they linked. I was going to edit this answer to update based on that, but now I don't have to. :-)
There is probably a better way—this one seems a bit clumsy—but I was able to work around this with reflect
:
QUESTION
In the current stable Rust, is there a way to write a function equivalent to BTreeMap::pop_last?
The best I could come up with is:
...ANSWER
Answered 2022-Mar-15 at 16:55Is there a way to work around this issue without imposing additional constraints on map key and value types?
It doesn't appear doable in safe Rust, at least not with reasonable algorithmic complexity. (See Aiden4's answer for a solution that does it by re-building the whole map.)
But if you're allowed to use unsafe, and if you're determined enough that you want to delve into it, this code could do it:
QUESTION
I am getting this error when I try to sign up a user. After this error, I'm still able to sign in with the user it would've created, but it always shows me this upon registration. Please let me know if there's other information you need. Been stumped on this for a few days.
Here is the callback for the error:
...ANSWER
Answered 2022-Jan-03 at 12:08This seems to a be a known issue with Rails 7 and Devise now. To fix it in the meantime simply add the following line to your devise.rb.
config.navigational_formats = ['*/*', :html, :turbo_stream]
QUESTION
Discussion about this was started under this answer for quite simple question.
ProblemThis simple code has unexpected overload resolution of constructor for std::basic_string
:
ANSWER
Answered 2022-Jan-05 at 12:05Maybe I'm wrong, but it seems that last part:
QUESTION
Constraints in C++20 are normalized before checked for satisfaction by dividing them on atomic constraints. For example, the constraint E = E1 || E2
has two atomic constrains E1
and E2
And substitution failure in an atomic constraint shall be considered as false value of the atomic constraint.
If we consider a sample program, there concept Complete = sizeof(T)>0
checks for the class T
being defined:
ANSWER
Answered 2022-Jan-07 at 15:39This is Clang bug #49513; the situation and analysis is similar to this answer.
sizeof(T)>0
is an atomic constraint, so [temp.constr.atomic]/3 applies:
To determine if an atomic constraint is satisfied, the parameter mapping and template arguments are first substituted into its expression. If substitution results in an invalid type or expression, the constraint is not satisfied. [...]
sizeof(void)>0
is an invalid expression, so that constraint is not satisfied, and constraint evaluation proceeds to sizeof(U)>0
.
As in the linked question, an alternative workaround is to use "requires requires requires"; demo:
QUESTION
When running this simple program, different behaviour is observed depending on the compiler.
It prints true
when compiled by GCC 11.2, and false
when compiled by MSVC 19.29.30137 with the (both are the latest release as of today).
ANSWER
Answered 2021-Dec-08 at 16:06GCC and Clang report that S
is trivially copyable in C++11 through C++23 standard modes. MSVC reports that S
is not trivially copyable in C++14 through C++20 standard modes.
N3337 (~ C++11) and N4140 (~ C++14) say:
A trivially copyable class is a class that:
- has no non-trivial copy constructors,
- has no non-trivial move constructors,
- has no non-trivial copy assignment operators,
- has no non-trivial move assignment operators, and
- has a trivial destructor.
By this definition, S
is trivially copyable.
N4659 (~ C++17) says:
A trivially copyable class is a class:
- where each copy constructor, move constructor, copy assignment operator, and move assignment operator is either deleted or trivial,
- that has at least one non-deleted copy constructor, move constructor, copy assignment operator, or move assignment operator, and
- that has a trivial, non-deleted destructor
By this definition, S
is not trivially copyable.
N4860 (~ C++20) says:
A trivially copyable class is a class:
- that has at least one eligible copy constructor, move constructor, copy assignment operator, or move assignment operator,
- where each eligible copy constructor, move constructor, copy assignment operator, and move assignment operator is trivial, and
- that has a trivial, non-deleted destructor.
By this definition, S
is not trivially copyable.
Thus, as published, S
was trivally copyable in C++11 and C++14, but not in C++17 and C++20.
The change was adopted from DR 1734 in February 2016. Implementors generally treat DRs as though they apply to all prior language standards by convention. Thus, by the published standard for C++11 and C++14, S
was trivially copyable, and by convention, newer compiler versions might choose to treat S
as not trivially copyable in C++11 and C++14 modes. Thus, all compilers could be said to be correct for C++11 and C++14.
For C++17 and beyond, S
is unambiguously not trivially copyable so GCC and Clang are incorrect. This is GCC bug #96288 and LLVM bug #39050
QUESTION
The following code fails to compile with Clang 13 and MSVC v19.29 VS16.11 but successfully compiles with GCC 11.2.
...ANSWER
Answered 2021-Nov-03 at 13:37QUESTION
In C++20, we are now able to constrain the auto
keyword to only be of a specific type. So if I had some code that looked like the following without any constraints:
ANSWER
Answered 2021-Nov-01 at 18:38A constraint on the deduced auto
type doesn't mean it needs to be a specific type, it means it needs to be one of a set of types that satisfy the constraint. Note that a constraint and a type are not the same thing, and they're not interchangeable.
e.g. a concept like std::integral constrains the deduced type to be an integral type, such as int
or long
, but not float
, or std::string
.
If I really need a
std::integral
datatype, couldn't I just omit theauto
completely?
In principle, I suppose you could, but this would at the minimum lead to parsing difficulties. e.g. in a declaration like
QUESTION
In C++20, some ranges have both const
and non-const
begin()/end()
, while others only have non-const
begin()/end()
.
In order to enable the range adapters that wraps the former to be able to use begin()/end()
when it is const
qualified, some range adapters such as elements_view
, reverse_view
and common_view
all provide constrained const
-qualified begin()/end()
functions, for example:
ANSWER
Answered 2021-Oct-09 at 03:58Recent SG9 discussion on LWG3564 concluded that the intended design is that x
and as_const(x)
should be required to be substitutable with equal results in equality-preserving expressions for which both are valid. In other words, they should be "equal" in the [concepts.equality] "same platonic value" sense. Thus, for instance, it is not valid for x
and as_const(x)
to have entirely different elements.
The exact wording and scope of the rule will have to await a paper, and we'll have to take care to avoid banning reasonable code. But certainly things like "x
is a range of pairs but as_const(x)
is a range of ints" are not within any reasonable definition of "reasonable".
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