business-hours | 🕰 Find the next working day , defined business hours | BPM library
kandi X-RAY | business-hours Summary
kandi X-RAY | business-hours Summary
Find the next working day, defined business hours.
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QUESTION
I have the below issue and I feel I'm just a few steps away from solving it, but I'm not experienced enough just yet. I've used business-duration for this. I've looked through other similar answers to this and tried many methods, but this is the closest I have gotten (Using this answer). I'm using Anaconda and Spyder, which is the only method I have on my work laptop at the moment. I can't install some of the custom Business days functions into anaconda.
I have a large dataset (~200k rows) which I need to solve this for:
...ANSWER
Answered 2022-Mar-24 at 14:16Use:
QUESTION
How do I check if a time is in the range of two timefields?
...ANSWER
Answered 2022-Mar-22 at 20:41Its not a pretty solution but at the end of the day it works
this answer solved my question
QUESTION
I'm drawing a Gantt chart using timeline. I want to use add_shape
to draw dependencies, but seem to be constrained to day boundaries. The examples at https://plotly.com/python/time-series/#hiding-nonbusiness-hours hints that time deltas of <1day are possible on an axis of type='date'
, but my code doesn't work.
I'm on the verge of resorting to using an int
axis and unix timestamps, which looks like I will then have a bunch more questions about how to format that stuff as dates for the ticks.
ANSWER
Answered 2022-Jan-13 at 14:27You can use a combination of pd.to_datetime()
with your dates and pd.DateOffset()
like this:
QUESTION
I am trying to calculate the number of minutes a logged job has been running. Each job has a start time and an end time.
In this particular case, the working hours are between 01:00 and 10:00, and only business days (weekends excluded)
In order to calculate this, I tried and made a JavaScript based UDF like this:
...ANSWER
Answered 2021-Apr-26 at 19:47Did you test this outside of Snowflake? I just created the following file and running node /tmp/dates.js
produces this output which matches up with Snowflake
QUESTION
I have a form where I am trying to show and hide different input fields based on a user selection from a dropdown menu. I have it working in that when an option is selected, it shows the desired form, but hides everything around the form as well. If I set it to not hide anything and only show, it displays one form after the other.
What I am trying to do is set it so that when a user makes a selection, it displays the relevant forms without hiding anything extra, and if a user selects a new form, the new form is displayed and the old one hidden, all without hiding the pre-existing elements that are there from the beginning.
HTML
...ANSWER
Answered 2021-Jan-15 at 22:11After some more looking around and playing with it, I did find a solution, though I don't think it is written as well as it could be, but it works.
jQuery that worked
QUESTION
I'm making home page for employee management. I want to get business hours between two dates. I already searched and get one method from this link. http://rion.io/2014/06/20/calculating-business-hours-in-javascript/
...ANSWER
Answered 2021-Jan-07 at 15:39I would optimize your problem so that I'd be working with full dates.
If you take your range of 2020-01-01 12:45:00 - 2028-10-06 23:10:33
, then there are essentially three parts to this:
2020-01-01 12:45:00 - 2020-01-01 23:59:59
2020-01-02 00:00:00 - 2028-10-05 23:59:59
2020-10-06 00:00:00 - 2028-10-06 23:10:33
Calculating business hours in full days is easy: dayAmount * (dayEnd - dayStart) * 60
Use whatever method you can figure out to calculate minutes in part 1 and 3. Then just sum everything together.
Edit: On the other hand, you might even have to split it into weekly chunks since it might not be a full week. And you'd have to calculate the amount of holidays, unless you're fine with a naive approach.
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