DailyCodingProblem | Problems with my solutions of Daily Coding Problem website | Learning library

 by   HouariZegai Python Version: Current License: MIT

kandi X-RAY | DailyCodingProblem Summary

kandi X-RAY | DailyCodingProblem Summary

DailyCodingProblem is a Python library typically used in Telecommunications, Media, Advertising, Marketing, Tutorial, Learning, LeetCode applications. DailyCodingProblem has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However DailyCodingProblem build file is not available. You can download it from GitHub.

Problems with my solutions of Daily Coding Problem website
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              DailyCodingProblem has a low active ecosystem.
              It has 38 star(s) with 7 fork(s). There are 5 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              DailyCodingProblem has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of DailyCodingProblem is current.

            kandi-Quality Quality

              DailyCodingProblem has 0 bugs and 0 code smells.

            kandi-Security Security

              DailyCodingProblem has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              DailyCodingProblem code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              DailyCodingProblem is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              DailyCodingProblem releases are not available. You will need to build from source code and install.
              DailyCodingProblem has no build file. You will be need to create the build yourself to build the component from source.
              DailyCodingProblem saves you 28 person hours of effort in developing the same functionality from scratch.
              It has 76 lines of code, 5 functions and 239 files.
              It has low code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed DailyCodingProblem and discovered the below as its top functions. This is intended to give you an instant insight into DailyCodingProblem implemented functionality, and help decide if they suit your requirements.
            • encode a string
            • Check if a string is well formed .
            • Decode a string .
            • Returns the value of the missing number in a list .
            • Generate num characters .
            Get all kandi verified functions for this library.

            DailyCodingProblem Key Features

            No Key Features are available at this moment for DailyCodingProblem.

            DailyCodingProblem Examples and Code Snippets

            No Code Snippets are available at this moment for DailyCodingProblem.

            Community Discussions

            QUESTION

            How to find repeated pattern in multiline text with Python regex?
            Asked 2020-May-20 at 20:55

            I am very new to Python's regex module. I am trying to find the problem number and corresponding company name which asked the question. My text looks like this:

            Text input:

            ...

            ANSWER

            Answered 2020-May-20 at 20:41

            I assumed that the line with "asked by" is always after the problem number. For me it work with pattern.

            Source https://stackoverflow.com/questions/61921742

            QUESTION

            Convert string to palindrome with fewest number of insertions
            Asked 2020-Apr-04 at 16:31

            This is a question from https://www.dailycodingproblem.com/:

            Given a string, find the palindrome that can be made by inserting the fewest number of characters as possible anywhere in the word. If there is more than one palindrome of minimum length that can be made, return the lexicographically earliest one (the first one alphabetically).

            For example, given the string "race", you should return "ecarace", since we can add three letters to it (which is the smallest amount to make a palindrome). There are seven other palindromes that can be made from "race" by adding three letters, but "ecarace" comes first alphabetically.

            As another example, given the string "google", you should return "elgoogle".

            It is similar to this SO question, or this GeeksforGeeks post. Similar, but not the same; none of them provide any explanation for the recurrence, as if they plucked the solution out of thin air, and they don't reconstruct the solution, let alone the lexicographically earliest one.

            After some thinking, my understanding is as follows:

            Observe that for any string s[i..j], if s[i] == s[j], then the number of insertions required to make it a palindrome is the same as the number of insertions required to make s[i+1..j-1] a palindrome.

            If, however, s[i] != s[j], then we may convert s[i..j-1] to a palindrome and then insert s[j] at the beginning, or convert s[i+1..j] to a palindrome and insert s[i] at the end. Since we are looking for the fewest number of insertions, we will choose the minimum of the two options. The number of insertions is one more than the number of insertions required for the chosen subproblem (for adding a character at the beginning or at the end).

            How do I reconstruct the lexicographically earliest solution?

            ...

            ANSWER

            Answered 2019-Mar-15 at 09:31

            First, lets answer "how do I reconstruct the solution", then focus on ordering. Assuming you store the number of insertions in a 2D matrix insertions[start][stop], you just need to retrace your steps, "collecting" the characters inserted as you go. We'll need a new array to store out output string, of length equal to our starting string plus the minimal number of insertions. We'll also store two indices, pointing to the next available spots from the front and back into the array.

            Start by comparing the first and last letters of the current substring, and if equal assign the output string both of those, in the next available positions from the front and back respectively. For example, if we have FYRF as our current substring, we'll assign our output string F..F, where . are undetermined characters. Our substring then becomes s[i+1..j-1] or YR.

            If the two characters do not match, we'll compare our records in insertions[i+1][j] and insertions[i][j-1], to see which is smaller (at least one of them will be exactly one less than insertions[i][j]). If they're equal, just pick one (we'll return to this later). Assign the character in our output string which corresponds to the letter of the substring we duplicated / inserted, at the next available front and back indices into the output string. That is, in the case JLL, if we decide to add a J for JLLJ, we'd take the substring s[i+1..j], so we'd store J and J in our output string J..J. If our output string already contained AR....RA, we'd have stored ARJ..JRA instead. We repeat this entire process until all characters are assigned.

            Now, to make it ordered lexicographically. Regarding the case in the previous paragraph where insertions[i+1][j] and insertions[i][j-1] are equal, we shouldn't pick one of them at random. Instead, we should compare s[i] and s[i+1] lexicographically, and if s[i] comes first, insert s[i] into the output string / proceed on insertions[i+1][j]. Otherwise, use s[i+1] / insertions[i][j-1]. This will give us the lexicographically soonest string from all available options.

            Source https://stackoverflow.com/questions/55178669

            QUESTION

            How can division be used to find the product of every value an input array except the value with a corresponding index
            Asked 2018-Jul-29 at 20:42

            In an attempt to improve my general problem solving skills, I recently subscribed to Daily Coding Problem. One of the challenges that came up has the following description:

            This problem was asked by Uber.

            Given an array of integers, return a new array such that each element at index i of the new array is the product of all the numbers in the original array except the one at i.

            For example, if our input was [1, 2, 3, 4, 5], the expected output would be [120, 60, 40, 30, 24]. If our input was [3, 2, 1], the expected output would be [2, 3, 6].

            Follow-up: what if you can't use division?

            I solved this particular challenge within minutes using the following function:

            ...

            ANSWER

            Answered 2018-Jul-29 at 20:42

            As @Steve alluded in the comments, you would:

            • first find the product of all the elements in the array:

            Source https://stackoverflow.com/questions/51583898

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install DailyCodingProblem

            You can download it from GitHub.
            You can use DailyCodingProblem like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            git@github.com:HouariZegai/DailyCodingProblem.git

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