FAQ | language crowdsourcing project to help novice Telegram bot | Bot library
kandi X-RAY | FAQ Summary
kandi X-RAY | FAQ Summary
Russian-language crowdsourcing project to help novice Telegram bot developers
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Top functions reviewed by kandi - BETA
- Start a message
- Increase the ref count of a user
- Check if a user exists
- Create a user
- Get a user
- Get my references
- Return the ref count of the given user
FAQ Key Features
FAQ Examples and Code Snippets
One
Two
Three
let counter = new CounterContainer();
function Counter() {
return (
{counter => ...}
);
}
class CounterContainer extends Container {
constructor(props = {}) {
super();
this.state = {
a
import torch
from vit_pytorch import ViT
v = ViT(
image_size = 256,
patch_size = 32,
num_classes = 1000,
dim = 1024,
depth = 6,
heads = 16,
mlp_dim = 2048,
dropout = 0.1,
emb_dropout = 0.1
)
img = torch.randn(1,
Community Discussions
Trending Discussions on FAQ
QUESTION
I want to set an active
class just to first button in this code:
ANSWER
Answered 2021-Aug-11 at 12:08You can make a dynamic class based on a condition like
QUESTION
I am learning about references in C++. In particular, i have learnt that references are not actual objects. Instead they refer to some other object. That is, reference are just alias for other objects.
Then i came across this which says:
Important note: Even though a reference is often implemented using an address in the underlying assembly language, please do not think of a reference as a funny looking pointer to an object. A reference is the object, just with another name. It is neither a pointer to the object, nor a copy of the object. It is the object. There is no C++ syntax that lets you operate on the reference itself separate from the object to which it refers.
I get that the above quote means that we can't operate on the reference itself separate from the object to which it refers but it still seems to imply that "a reference is an object".
Also, i have come across the the sentence given below:
In ISO C++, a reference is not an object. As such, it needs not have any memory representation.
I don't have a link to this 2nd quote but i read it in one of SO's post somewhere.
My question is that assuming the second quote is also from the standard(which may not be the case), doesn't these 2 quoted statements contradict each other. Or at least the first quote is misleading. Which one is correct.
My current understanding(by reading books like C++ Primer 5th edition) is that references are an alias for objects. Which leads me to the thinking that they should not take any space in memory.
...ANSWER
Answered 2022-Mar-18 at 17:40The first quote is really saying the reference is not separable from the object.
... still seems to imply that "a reference is an object".
It really implies that a reference is a non-separable, non-first-class alias for an object, exactly as you first said.
The difficulty with these discussions is that the standardese meaning of "object" is already different from the meaning used in most less-formal contexts.
Let's start simple:
int a;
Would often be described as declaring an integer object a
, right? It actually
- declares an integer object
- binds the name
a
to that object in the appropriate scope
Now, if we write
int &b = a;
we could say that b
is the object in the same way as we could say that a
is the object. Actually neither are correct, but given that informal text already uses the latter, it's no worse.
We should instead say that the name b
refers to the same object as the name a
. This is exactly consistent with calling it an alias, but informal or introductory texts would seem pretty cumbersome if they wrote "... the integer object referred to by the name a
..." everywhere instead of just "the integer a
".
As for taking space in memory ... it depends. If I introduce 100 aliases for a single object inside a single function I'd be really surprised if the compiler didn't just collapse them (although of course they might still show up in debug symbols). No information is being lost here by eliding the redundant names.
If I pass an argument by reference to a non-inlined function, some actual information is being communicated, and that information must be stored somewhere.
QUESTION
Until yesterday (20 Jan) I could connect to another google drive account (using drive._mount), but when I tried this today, google colab showed me this error:
...ANSWER
Answered 2022-Jan-21 at 14:00Alright, until this problem get solved, I did this trick for my project:
I shared which files I need (like datasets) with my other accounts. For this, you should:
- Go to your google drive (where your file is stored) then right-click on it and choose "Share"
- Click on "Change to anyone with the link"
- Copy link and open it in new window
- In top-right side, click on your google accounts list and select which one you need
- At the opened window, in top-right side click on "Add shortcut to Drive" and choose location where you want to save file in it
- Your file now is accessible in account you did choose
QUESTION
MapStruct generates code at compile-time and it should not require any runtime dependencies:
How is MapStruct different from other bean mapping tools?
Unlike most other bean mapping tools, MapStruct doesn’t work at runtime but is a compile-time code generator.
Generating mapping code at build time has many advantages:
- Excellent performance, as no reflection or byte code generation at runtime is needed; the generated code contains plain method invocations, just as if the mapper was hand-written
- No runtime dependencies, making MapStruct a great solution for Android applications
Which dependency scope should be used in a Maven project? Should MapStruct be included as a provided dependency?
...ANSWER
Answered 2022-Feb-12 at 08:23The org.mapstruct:mapstruct
dependency contains the needed annotations to signal the org.mapstruct:mapstruct-processor
what to do.
It also contains the Mappers
factory that is used when using the default component model. Therefore, the scope of org.mapstruct:mapstruct
depends on the component model that you are using:
If you are using this component model then you need org.mapstruct:mapstruct
during runtime if you are using Mappers
or if you have dependencies between different mappers.
In theory you can use the default component model and instantiate your own mappers. However, dependencies between mappers are still going to use Mappers
, unless you have instantiated your mapper in MyMapper.INSTANCE
somehow already, then MapStruct will use MyMapper.INSTANCE
to get the instance of the MyMapper
. This would mean that you can still use the same scope as the other component models (see below for more information)
In this case you do not need org.mapstruct:mapstruct
during runtime and you can use true
with provided
.
With Gradle this would be compileOnly
dependency.
Note: Be careful when using Spring Boot and provided
the Spring Boot maven plugin will still include the org.mapstruct:mapstruct
dependency in the final provided jar. You'll need to ignore it by configuring the Spring Boot Maven plugin.
QUESTION
I am trying to do a function of decumulation with a for loop in R because the financial information provided by the company is accumulated for different concepts (this means that the info of January is only of January, the info of February is the sum of January and February, the one of March is the sum of January, February and March, etc.).
For example, let's say that I have the next dataframe:
...ANSWER
Answered 2021-Dec-29 at 18:21First note that if you apply
base function diff
to the months columns, you will get one column less but transposed.
QUESTION
In reservation system, only 5 different user can create bookings. If 100 user call booking api at same time than how to handle concurrency with locking. I am using nodejs with mongodb. I went through mongo concurrency article and transactions in mongodb, but cannot find any sample coding solution with locking.
I have achieved solution with Optimistic concurrency control (when there is low contention for the resource - This can be easily implemented using versionNumber or timeStamp field).
Thank you in advance for suggesting me solution with locking.
Now the algorithm is:
Step 1: Get userAllowedNumber from userSettings collection.
...ANSWER
Answered 2021-Oct-17 at 05:57I had deep discussion about locking with transaction in mongodb community. In the conclusion, I learn and found the limitation of transaction. There is no lock we can use to handle concurrent request for this task.
You can see the full Mongodb community conversation at this link https://www.mongodb.com/community/forums/t/implementing-locking-in-transaction-for-read-and-write/127845
Github demo code with Jmeter testing shows the limitation and not able to handle concurrent request for this task. https://github.com/naisargparmar/concurrencyMongo
New suggestion are still welcome and appreciate
QUESTION
Hello I am creating an FAQ page that has to be filtered using javascript as below
Credit : https://makitweb.com/jquery-search-text-in-the-element-with-contains-selector/
...ANSWER
Answered 2022-Feb-02 at 23:09Expanding on my comment, this is an example of how you could implement something like this.
To reiterate - the main problem was that the error was being shown if any result didn't match instead of showing if none match
To fix that, we can add a variable outside the loop to determine if any result was matched
QUESTION
Unambiguous DNA sequences consist only of the nucleobases adenine (A), cytosine (C), guanine (G), thymine (T). For human consumption, the bases may be represented by the corresponding char
in either uppercase or lowercase: A
, C
, G
, T
, or a
, c
, g
, t
. This representation is inefficient, however, when long sequences need to be stored. Since only four symbols need to be stored, each symbol can be assigned a 2-bit code. The commonly used .2bit
-format specified by UCSC does exactly that, using the following encoding: T = 0b00
, C = 0b01
, A = 0b10
, G = 0b11
.
The C code below shows a reference implementation written for clarity. Various open-source software that converts genomic sequences represented as a char
sequence typically uses a 256-entry lookup table indexed by each char
in sequence. This also isolates from the internal representation of char
. However, memory access is energetically expensive, even if the access is to an on-chip cache, and generic table look-ups are difficult to SIMDize. It would therefore be advantageous if the conversion could be accomplished by simple integer arithmetic. Given that ASCII is the dominating char
encoding, one can restrict to that.
What are efficient computational approaches to convert nucleobases given as ASCII characters to their .2bit
-representation?
ANSWER
Answered 2022-Jan-09 at 08:28If one stares at the binary codes for the ASCII characters for the nucleobases intently, it becomes clear that bits 1 and 2 provide a unique two-bit code: A
= 0b01000001
-> 0b00
, C
= 0b01000011
-> 0b01
, G
= 0b01000111
-> 0b11
, T
= 0b01010100
-> 0b10
. Analogous for the lowercase ASCII characters, which differ merely in bit 5. Unfortunately this simple mapping does not quite match the .2bit
-encoding, in that the codes for A and T are swapped. One way of fixing this is with a simple four-entry permutation table stored in a variable, likely assigned to a register after optimization ("in-register lookup-table"):
QUESTION
What I want to do
Based on the FAQ
I want to update the package.json version number on a new release.
What I did
- Create a new empty private Github repository for an organization
temp
with a README.md and .gitignore for node - Clone the repository
- Fix the first commit message via git
rebase -i --root
and change it tofeat: initial commit
- Create a package.json with the content
ANSWER
Answered 2021-Dec-29 at 12:28Based on this issue
https://github.com/semantic-release/semantic-release/issues/1593
you also need the npm module.
npm install @semantic-release/npm -D
- add
"private": true,
to your package.json if you don't want to publish to npm - add the npm plugin to the release configuration file (the order matters)
.
QUESTION
Consider the following code:
...ANSWER
Answered 2021-Oct-27 at 12:26If
std::exit
is called to end a program during the destruction of an object with static or thread storage duration, the program has undefined behavior.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install FAQ
You can use FAQ like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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