Titan | Create Discord server widgets for websites of all sizes | Bot library
kandi X-RAY | Titan Summary
kandi X-RAY | Titan Summary
There was a time when Discord doesn't support embedding the chat on a webpage. But with Titan, you can! It is as simple as 1, 2, 3!.
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Top functions reviewed by kandi - BETA
- Update a post
- Get guild by id
- Check if a guild is enabled
- Delete webhook if the webhook is too big enough
- Update a guild
- Lists disabled guilds
- Check if user has permission to the guild
- Administrate a guild
- Prepare the guild members list
- View for a donor
- Render a guild
- Ban a bot
- Unban a bot
- Authenticate user
- Return information about a user
- Emit a guild user
- Called when the client is listening
- Create an authenticated user
- Called when the channel belongs to
- Change unauthenticated username
- Get all messages from a channel
- Shortcut to create a payer
- Called when the connection is ready
- Lookup user info
- List all members of a message
- Create an unauthenticated user
Titan Key Features
Titan Examples and Code Snippets
def get_device_details(device):
"""Returns details about a physical devices.
This API takes in a `tf.config.PhysicalDevice` returned by
`tf.config.list_physical_devices`. It returns a dict with string keys
containing various details about th
Community Discussions
Trending Discussions on Titan
QUESTION
My goal is to create barplots with counts on the y axis and have the bars labelled with the percentage of the group. The code below gets me halfway there -
...ANSWER
Answered 2022-Mar-26 at 04:15Generate within-feature proportions manually, e.g. for feature sex
:
- Compute the proportions of
survived
within eachsex
usinggroupby.value_counts()
- Access a given bar's proportion via its group (male/female
sex
) and label (0/1survived
)- The groups will be ordered differently per dtype, so
unique()
won't always work (see the full example in the next section) - The label of a container
c
isc.get_label()
, which can be converted to the appropriate type viadf[hue].dtype.type
- The groups will be ordered differently per dtype, so
QUESTION
I am very new to SQL and I am having difficulties working on my project for school. I have 3 tables: material, costs, and usages. I can only query the "material" table (used a SELECT * FROM statement to display everything), but when I try it on my other tables, it says ERROR: relation "costs" does not exist. I am completely stumped. I posted the raw code and an image for legibility. Any help is greatly appreciated. I do not know too much about SQL as a whole, but I also am following my teacher's project example, and syntactically speaking, it is setup the exact same way, which is why I am at a loss as to why only one of my three tables are accessible.
...ANSWER
Answered 2022-Mar-22 at 00:56You have a lot of errors
MysqL, has not taht ssyntax for creatig users and Provileges
Every row must have if it is not the last statement a comma which sperates dieffrent columns or constraints
The part with giveing gant to the tables, is so not possible, you can only grant one at a time, or use the sytax equipment.* for all tables
Last yyour last 3 INSERT INTO
are missing VALUES
bedore the new contenet
QUESTION
I just got started on Kaggle and for my first project I was working on the Titanic dataset.
I ran the following codeblock
...ANSWER
Answered 2022-Mar-18 at 13:24Use OneHotEncoder
from sklearn
QUESTION
I'm trying to query for all movies that have a higher score than a randomly selected movie score. I don't understand the error to fix my query.
List the titles of movies that have a higher score than some movie in the database.
(Don't hardcode "some" movie as any specific movie such as "Titanic".)
ANSWER
Answered 2022-Feb-21 at 01:40The sub-query SELECT SCORE FROM MOVIE
does not return a random score of a movie in other words a scalar but a list of scores.
You can't compare a scalar to the left of the > to a list at its right (the result of the sub-query). This is syntactically wrong.
You can correct this in many different ways. It depends on what you want.
Here are some working examples with > operator:
QUESTION
I get an error when I try to fit Poisson model in a given dataset in R. Am struggling to understand the cause of the error.
...ANSWER
Answered 2022-Feb-15 at 00:19You might be confused. You can't fit a Poisson to a categorical response. You could fit a Poisson to binary data after converting survival
"yes"/"no" to 0/1, but it doesn't really make sense:
QUESTION
As I have mentioned in Question title, I have following INI file, which contains umpteen number of sections and each section containing umpteen lines:
...ANSWER
Answered 2022-Jan-30 at 16:35In Notepad++ and Sublime Text, you can use
Find What: (\R){2,}(?!\R*\[[^][]*]$)
Replace With: $1
See the regex demo. Details:
(\R){2,}
- two or more line break sequences (the last one captured is saved in Group 1 memory buffer)(?!\R*\[[^][]*]$)
- a negative lookahead that fails the match if there are\R*
- zero or more line break sequences\[
- a[
char[^][]*
- zero or more chars other than[
and]
]
- a]
char$
- end of a line.
In Visual Studio Code, this regex needs tweaking a bit:
QUESTION
If the data in the column 'embark_town' is 'Southampton', I want to change them all to 'manchester'. So after accessing the data with condition setting, I applied the 'apply' function. What's the problem?
...ANSWER
Answered 2022-Jan-22 at 03:34As Michael Szczesny also pointed out in the comment. DataFrame.apply
uses a Series
as input. The change(name)
function defined expects a string. The message ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
comes from trying to compare a Series
to a string.
One fix pointed out by Register Sole is to use conditions instead.
QUESTION
While touring the "class" column, I want to change the value to "01" if the data value is "one", "02" if it is "two", and "03" if it is "three", what's the problem?
...ANSWER
Answered 2022-Jan-21 at 13:47As outlined in comment, pandas.DataFrame.iloc
only takes integers as indexers. Or, given how you iterate over df['class']
, it turns out that your x
s are strings of characters. Hence the TypeError
you get.
That being said, if you want to replace your occurrence by something else, what about using pandas.Series.map
, as follows:
QUESTION
I would like to place labels on bars in Seaborn depending on how much space there is available.
For example in the example below I would like to use outside labels if they fit on the figure and inside labels when they don't. I would like to do this automatically for many plots, so I am looking for a smart way to do this flexibly. Any ideas?
...ANSWER
Answered 2022-Jan-15 at 21:06Does this help?
QUESTION
I am working on the Kaggle Titanic problem. I have a function that creates cross products of survival means by characteristics of the passengers. For SibSp by Embarked I get the following survival table:
...ANSWER
Answered 2022-Jan-02 at 08:19Try:
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