someone | A Discord bot that adds the @ someone functionality | Bot library
kandi X-RAY | someone Summary
kandi X-RAY | someone Summary
A Discord bot that adds the @someone functionality.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of someone
someone Key Features
someone Examples and Code Snippets
def thank_elder():
adv.say("It is we who should thank you. Go with our love and hopes!")
Community Discussions
Trending Discussions on someone
QUESTION
I just updated my Android studio to the version 2021.1.1 Canary 12. After struggling to make it work, I had to also upgrade my Gradle and Gradle plugin to 7.0.2. Now I can compile my project and launch my app on my mobile, everything is working. But when I try to generate a Signed APK, I get a strange message after building telling me: APK(s) generated successfully for module 'android-mobile-app-XXXX.app' with 0 build variants:
Even though the build seem to be successful I cannot find the generated APK anywhere (and considering the time it takes to give me that error, I don't even think it is building anything). Now, I have been generating an APK every week for years now, so I know my way around the folders, the different build variant output folders etc... Nothing changed in my way of generating an APK. I do it via AS and follow the very standard procedure.
Can someone point to me what am I missing here? I assume there is a way to select a specific build variant when generating a signed APK, how does it works?
PS: Obviously, I am selecting my variant here during the process:
PS2: I can generate a debug APK without any issue whatsoever.
...ANSWER
Answered 2021-Oct-05 at 07:39After a few days of struggle, I ended up switching to Bundle. It achieves the same purpose for me and it actually works so... That's my solution here.
QUESTION
I'm trying to make a Discord bot that just says if someone is online on the game.
However I keep getting this message:
[ERR_REQUIRE_ESM]: require() of ES Module from not supported. Instead change the require of index.js in... to a dynamic import() which is available in all CommonJS modules.
This is my code:
...ANSWER
Answered 2021-Sep-07 at 06:38node-fetch
v3 recently stopped support for the require
way of importing it in favor of ES Modules. You'll need to use ESM imports now, like:
QUESTION
After Android Studio upgraded itself to version Arctic Fox, I now get these strange sub-windows in my code editor that I can't get rid of. If I click in either of the 2 sub-windows (a one-line window at the top or a 5-line window underneath it (see pic below), it scrolls to the code in question and the sub-windows disappear. But as soon as I navigate away from that code, these sub-windows mysteriously reappear. I can't figure out how to get rid of this.
I restarted Studio and it seemed to go away. Then I refactored a piece of code (Extract to Method Ctrl+Alt+M) and then these windows appeared again. Sometimes these windows appear on a 2nd monitor instead of on top of the code area on the monitor with Android Studio. But eventually they end up back on top of my code editor window.
I have searched hi and low for what this is. Studio help, new features, blog, etc. I am sure that I am just using the wrong terminology to find the answer, so hoping someone else knows.
...ANSWER
Answered 2021-Aug-15 at 15:29Just stumbled upon the same thing (strange windows upon attempting to refactor some code after updating to Arctic Fox). After a lot of searching around the options/menus/internet this fixed it for me:
Navigate to:
File > Settings... > Editor > Code Editing
under
Refactorings > Specify refactoring options:
select
In modal dialogs
Press OK.
Fingers crossed refactoring works.
🤞
Further step: Restart Android Studio
QUESTION
Apparently, the constexpr std::string has not been added to libstdc++ of GCC yet (as of GCC v11.2).
This code:
...ANSWER
Answered 2022-Jan-03 at 21:36C++20 supports allocation during constexpr time, as long as the allocation is completely deallocated by the time constant evaluation ends. So, for instance, this very silly example is valid in C++20:
QUESTION
I know (-0 === 0) comes out to be true. I am curious to know why -0 < 0 happens?
When I run this code in stackoverflow execution context, it returns 0
.
ANSWER
Answered 2021-Dec-22 at 14:17This is a specialty of Math.min
, as specified:
21.3.2.25 Math.min ( ...args )
[...]
- For each element number of coerced, do
a. If number is NaN, return NaN.
b. If number is -0𝔽 and lowest is +0𝔽, set lowest to -0𝔽.
c. If number < lowest, set lowest to number.
- Return lowest.
Note that in most cases, +0 and -0 are treated equally, also in the ToString conversion, thus (-0).toString()
evaluates to "0"
. That you can observe the difference in the browser console is an implementation detail of the browser.
QUESTION
I am aware of how ODR, linkage, static
, and extern "C"
work with functions. But I am not sure about visibility of types since they cannot be declared static
and there are no anonymous namespaces in C.
In particular, I would like to know the validity of the following code if compiled as C and C++
...ANSWER
Answered 2021-Oct-20 at 09:43For C. The program is valid. The only requirement that applies here is "strict aliasing rule" saying that the object can be accessed only via a l-value of a compatible type (+ a few exception described in 6.5p7).
The compatibility of structures/unions defined in separate translation units is defined in 6.2.7p1.
... two structure, union, or enumerated types declared in separate translation units are compatible if their tags and members satisfy the following requirements: If one is declared with a tag, the other shall be declared with the same tag. If both are completed anywhere within their respective translation units, then the following additional requirements apply: there shall be a one-to-one correspondence between their members such that each pair of corresponding members are declared with compatible types; if one member of the pair is declared with an alignment specifier, the other is declared with an equivalent alignment specifier; and if one member of the pair is declared with a name, the other is declared with the same name. For two structures, corresponding members shall be declared in the same order. For two structures or unions, corresponding bit-fields shall have the same widths. For two enumerations, corresponding members shall have the same values.
Therefore the structures are not compatible in the example.
However, it is not an issue because the f
object is created and accessed via locally defined type. UB would be invoked if the object was created with Foo
type defined in one translation unit and accessed via other Foo
type in the other translation unit:
QUESTION
I am trying to import a box component from @mui/material/Box
. I have installed MUI 5 using the following command npm i @mui/material
.
But this error is occurring, Module not found: Can't resolve '@emotion/react' in 'E:\frontend\node_modules\@mui\styled-engine'
Here is my code.
...ANSWER
Answered 2021-Sep-21 at 13:42Could be that the dependency @emotion/react
is out of package.json somehow.
So try to run npm install @emotion/react --save
.
QUESTION
Some answer originally had this sorting algorithm:
...ANSWER
Answered 2021-Oct-24 at 16:59To prove that it's correct, you have to find some sort of invariant. Something that's true during every pass of the loop.
Looking at it, after the very first pass of the inner loop, the largest element of the list will actually be in the first position.
Now in the second pass of the inner loop, i = 1
, and the very first comparison is between i = 1
and j = 0
. So, the largest element was in position 0, and after this comparison, it will be swapped to position 1.
In general, then it's not hard to see that after each step of the outer loop, the largest element will have moved one to the right. So after the full steps, we know at least the largest element will be in the correct position.
What about all the rest? Let's say the second-largest element sits at position i
of the current loop. We know that the largest element sits at position i-1
as per the previous discussion. Counter j
starts at 0. So now we're looking for the first A[j]
such that it's A[j] > A[i]
. Well, the A[i]
is the second largest element, so the first time that happens is when j = i-1
, at the first largest element. Thus, they're adjacent and get swapped, and are now in the "right" order. Now A[i]
again points to the largest element, and hence for the rest of the inner loop no more swaps are performed.
So we can say: Once the outer loop index has moved past the location of the second largest element, the second and first largest elements will be in the right order. They will now slide up together, in every iteration of the outer loop, so we know that at the end of the algorithm both the first and second-largest elements will be in the right position.
What about the third-largest element? Well, we can use the same logic again: Once the outer loop counter i
is at the position of the third-largest element, it'll be swapped such that it'll be just below the second largest element (if we have found that one already!) or otherwise just below the first largest element.
Ah. And here we now have our invariant: After k
iterations of the outer loop, the k-length sequence of elements, ending at position k-1
, will be in sorted order:
After the 1st iteration, the 1-length sequence, at position 0, will be in the correct order. That's trivial.
After the 2nd iteration, we know the largest element is at position 1, so obviously the sequence A[0]
, A[1]
is in the correct order.
Now let's assume we're at step k
, so all the elements up to position k-1
will be in order. Now i = k
and we iterate over j
. What this does is basically find the position at which the new element needs to be slotted into the existing sorted sequence so that it'll be properly sorted. Once that happens, the rest of the elements "bubble one up" until now the largest element sits at position i = k
and no further swaps happen.
Thus finally at the end of step N
, all the elements up to position N-1
are in the correct order, QED.
QUESTION
Sometimes I get ReferenceError in my sentry with this instantSearchSDKJSBridgeClearHighlight. Google says nothing.
All I found is https://github.com/algolia/instantsearch-android and https://github.com/algolia/instantsearch-ios that may be related to my issue.
I got 53 issues from 5 different users and all of them Edge Mobile on iphone. Maybe someone knows what this thing is (or know method how to know)?
Edit: I also found this issue using github search. Same issue as mine and created by bot
...ANSWER
Answered 2021-Oct-14 at 20:12This is a bug in the Bing Instant Search feature in Edge on iOS; the feature tries to call a function that no longer exists. Thanks for the bug; I've passed it along to the feature owners.
The basic idea is that for Edge on iOS the actual web engine is not our normal one (Blink); it is instead Safari's WkWebView.
In order to implement features like Bing's instant search, we have to inject JavaScript into the pages we load. Then our outer browser calls those JavaScript functions we injected.
Here, someone goofed and got rid of (or renamed) the injected JavaScript function, but failed to remove/update the browser code that tries to call that injected JavaScript.
So users who are watching the browser's error logs see an error message saying "Hey, there's no such function."
This is normally harmless, but if you have "Sentry" code that watches for error messages and complains about them to the website developers, it starts complaining about this error message we're causing.
QUESTION
I've scrolled and searched through the standard and cppreference for hours to no avail, would really appreciate if someone could explain this occurance for me:
I am looking at the standard concept std::convertibe_to
. Here's a simple example that I do understand
ANSWER
Answered 2021-Aug-23 at 15:55void foo( constraint auto x );
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install someone
You can use someone like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page