falcon | A high-performance web server for Ruby, supporting HTTP/1, HTTP/2 and TLS | HTTP library
kandi X-RAY | falcon Summary
kandi X-RAY | falcon Summary
Falcon is a multi-process, multi-fiber rack-compatible HTTP server built on top of async, async-io, async-container and async-http. Each request is executed within a lightweight fiber and can block on up-stream requests without stalling the entire server process. Falcon supports HTTP/1 and HTTP/2 natively.
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Top functions reviewed by kandi - BETA
- Builds SSL connection .
- Stop all services .
- Add an environment to the environment .
- Iterates over the environment .
- Setup the container
- Iterate over the endpoint
- Get the authority authority .
- Returns the SSL proxy configuration .
- Get the scheme scheme
- Loads the contents of the specified file .
falcon Key Features
falcon Examples and Code Snippets
Community Discussions
Trending Discussions on falcon
QUESTION
I can't find a solution online and I know this should be easy but I can't figure out what is wrong with my regex:
here is my code:
...ANSWER
Answered 2022-Mar-17 at 17:34You can use .str.extract
, convert each row of results to a list, and then use .str.join
(and of course concatenate a +
at the beginning):
QUESTION
I am trying to get the first value of the the list in each row of df['Emails'] but in real life (this is a sample df) I don't know what the length of the list will be so I am just assuming that the longest will be length of 5 and then trying to whittle it down until I find the right length and selecting that index position but I am getting IndexError: index 5 is out of bounds for axis 0 with size 2
and I can't figure out what to do about it. Any help appreciated. Thanks.
my current code:
...ANSWER
Answered 2022-Mar-15 at 23:36Whenever you have a column containing lists, explode
will often be your friend, and this is the case here.
Use explode
, groupby(level=0)
(to group on the 0th (first) level of the index), and first
(which selects the first non-null value (including None, NaN, etc.))
QUESTION
Background
I have a complex nested JSON object, which I am trying to unpack into a pandas df
in a very specific way.
JSON Object
this is an extract, containing randomized data of the JSON object, which shows examples of the hierarchy (inc. children) for 1x family (i.e. 'Falconer Family'), however there is 100s of them in total and this extract just has 1x family, however the full JSON object has multiple -
ANSWER
Answered 2022-Feb-16 at 06:41I think this gets you pretty close; might just need to adjust the various name
columns and drop the extra data (I kept the grouping
column).
The main idea is to recursively use pd.json_normalize with pd.concat for all availalable children
levels.
EDIT: Put everything into a single function and added section to collapse the name
columns like the expected output.
QUESTION
I have a large list of models that I built using lapply with the following code (these lists are too long to show the whole data but I used the corresponding code to set the models up):
...ANSWER
Answered 2022-Feb-16 at 01:07You need an iterator to move through both the models and the new data. Instead of moving through the models, make it an iterator.
QUESTION
[
0: {_id: '61de38eb6ea1563609e1d0a7', title: 'FALCON SR SUNTOUR', price: '59', description: ' Alloy.., …}
1: {_id: '61d7a8b885c68311be8dd1b3', title: 'Lifelong LLBC2702 Falcon', price: '59', description: 'Low Maintenance: High.., …}
]
...ANSWER
Answered 2022-Jan-21 at 04:38You cannot call map
on each order item as it is an object
. To iterate over them use Object.entries
method.
Try like below
QUESTION
I have the following Pandas DataFrame and I am trying to group animals according to their class. I know I can use groupby to get a faster result. However, I was thinking if there was a way to replicate the groupby function by iterating over the rows.
...ANSWER
Answered 2021-Dec-24 at 20:33You don't really need a loop for any of this. First get a list of the unique elements:
QUESTION
Can I get the value of grouped column in apply in pandas groupby? For example,
...ANSWER
Answered 2021-Nov-25 at 14:44IIUC use x.name
:
QUESTION
I have a spreadsheet of fantasy players and their individual game stats. What I would like to add is a column that lists the Vegas Line of that individual game.
I'm merging from the below spreadsheet:
...ANSWER
Answered 2021-Nov-24 at 20:43Try changing x.lstrip('at')
to x.lstrip('at ')
QUESTION
I have downloaded a list of all the towns and cities etc in the US from the census bureau. Here is a random sample:
...ANSWER
Answered 2021-Nov-12 at 22:48I have such a solution. And I'm surprised myself that I used two loops for
!! Incredibly, I did it. First things first.
My proposal is based on a simplification. However, the mistake you will make at short distances will be relatively small. But the time gain is huge!
Well, I propose to count the distance in Cartesian coordinates, not spherical.
So we're going to need a simple function that computes the Cartesian coordinates based on the two arguments latitude
and longitude
.
Here is our LatLong2Cart
feature.
QUESTION
I have the following working code. I need to add a percentage column to monitor changes. I dont know much on how to do it in pandas. I need ideas on what part needs to be modified.
...ANSWER
Answered 2021-Nov-09 at 18:18Setup:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install falcon
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.
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