Files | A nicer way to handle files & folders in Swift | iOS library

 by   JohnSundell Swift Version: 4.2.0 License: MIT

kandi X-RAY | Files Summary

kandi X-RAY | Files Summary

Files is a Swift library typically used in Mobile, iOS, Xcode applications. Files has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

Welcome to Files, a compact library that provides a nicer way to handle files and folders in Swift. It’s primarily aimed at Swift scripting and tooling, but can also be embedded in applications that need to access the file system. It's essentially a thin wrapper around the FileManager APIs that Foundation provides.
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            kandi-support Support

              Files has a medium active ecosystem.
              It has 2408 star(s) with 183 fork(s). There are 47 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 17 open issues and 47 have been closed. On average issues are closed in 184 days. There are 6 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of Files is 4.2.0

            kandi-Quality Quality

              Files has no bugs reported.

            kandi-Security Security

              Files has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Files is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Files releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.

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            Files Key Features

            No Key Features are available at this moment for Files.

            Files Examples and Code Snippets

            Create API files .
            pythondot img1Lines of Code : 113dot img1License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def create_api_files(output_files,
                                 packages,
                                 packages_to_ignore,
                                 root_init_template,
                                 output_dir,
                                 output_package,
                                 api_name,
               
            Return a list of source files that match the given dump .
            pythondot img2Lines of Code : 99dot img2License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def list_source_files_against_dump(dump,
                                               path_regex_allowlist=None,
                                               node_name_regex_allowlist=None):
              """Generate a list of source files with information regarding ops and tensors  
            Load metadata files .
            pythondot img3Lines of Code : 60dot img3License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _load_metadata_files(self):
                """Load and parse metadata files in the dump root.
            
                Check that all metadata files have a common tfdbg_run_id, and raise
                a ValueError if their tfdbg_run_ids differ.
            
                Returns:
                  A list of metadata fil  

            Community Discussions

            QUESTION

            Google App Script Import CSV to Google Sheets
            Asked 2021-Jun-16 at 03:50

            I have a Google Sheet which i want to import a CSV File stored in my drive.

            this is my code:

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:50

            I think that when I saw your script, sheet of sheet.getSheetByName('TEST') is not declared. If the sheet of sheet name of TEST is existing in the Spreadsheet, how about the following modification?

            From:

            Source https://stackoverflow.com/questions/67995997

            QUESTION

            How to update another file if a match is found in python
            Asked 2021-Jun-16 at 03:13

            Here is my problem. I need to compare mainfile.txt and transactionfile.txt which contains numbers without comma. I need to Update/Replace the mainfile.txt contents (4th and 5th column) with what is found as a match in the transactionfile.txt

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:59

            You can use .zip() method. This will not overwrite the file. If you want to overwrite the file,

            Source https://stackoverflow.com/questions/67995659

            QUESTION

            How to sort google drive files by size in a spreadsheet?
            Asked 2021-Jun-16 at 02:55

            I am using a script to recursively list all the files in a Google drive folder to a spreadsheet. It is working fine but i need to sort the file listing by size ( highest size on top ). Also drive api returns value of size in bytes but i need them in GB's . I haven't found any way to do it through api directly ,so i want to divide the size value of each file by 1073741824 upto 1 decimal rounding it off ( 1 GB = 1073741824 bytes )

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:55
            Modification points:
            • In your script, the values are put to the Spreadsheet using appendRow in the loops. In this case, the process cost will be high. Ref And also, in this case, after the values were put to the Spreadsheet, it is required to sort the sheet.
            • So, in this answer, I would like to propose the following flow.
              1. Retrieve the file list and put to an array.
              2. Sort the array by the file size.
              3. Put the array to the Spreadsheet.

            When above points are reflected to your script, it becomes as follows.

            Modified script:

            Source https://stackoverflow.com/questions/67995533

            QUESTION

            How to Config Javascript ' script in Django?
            Asked 2021-Jun-16 at 02:47

            I built an app using Django 3.2.3., but when I try to settup my javascript code for the HTML, it doesn't work. I have read this post Django Static Files Development and follow the instructions, but it doesn't resolve my issue.

            Also I couldn't find TEMPLATE_CONTEXT_PROCESSORS, according to this post no TEMPLATE_CONTEXT_PROCESSORS in django, from 1.7 Django and later, TEMPLATE_CONTEXT_PROCESSORS is the same as TEMPLATE to config django.core.context_processors.static but when I paste that code, turns in error saying django.core.context_processors.static doesn't exist.

            I don't have idea why my javascript' script isn't working.

            The configurations are the followings

            Settings.py

            ...

            ANSWER

            Answered 2021-Jun-15 at 18:56

            Run ‘python manage.py collectstatic’ and try again.

            The way you handle static wrong, remove the static dirs in your INSTALLED_APPS out of STATIC_DIRS and set a STATIC_ROOT then collectstatic again.

            Add the following as django documentation to your urls.py

            Source https://stackoverflow.com/questions/67990678

            QUESTION

            There was a problem saving the text in EditText to a file
            Asked 2021-Jun-16 at 01:47

            This code receives information from an acquaintance you want to register in editText, and then clicks finButton to save the information you receive as a file called friendlist.txt. However, the Toast message is outputted from the try-catch statement that is currently performed when finButton is pressed. Also, the checkpermission does not work, which is wrapped in a try~catch statement, but does not have output on the logcat.

            And manifest.

            uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE"

            uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"

            is written.

            Please let me know the solution. And this content is written with a translator, so the sentence can be strange.

            when you press finButton, the logcat is shown below.

            The code corresponding to the 116th line is this.

            FileOutputStream outstream = openFileOutput("friendList.txt", Activity.MODE_WORLD_WRITEABLE);

            logcat

            ...

            ANSWER

            Answered 2021-Jun-16 at 01:47

            Try with Context.MODE_APPEND or Context.MODE_PRIVATE instead of Activity.MODE_WORLD_WRITEABLE

            Source https://stackoverflow.com/questions/67995297

            QUESTION

            How can I avoid bundling Vuetify and use from CDN?
            Asked 2021-Jun-16 at 01:31

            I'm trying to decrease the bundle size of my Vue project, which scaffolded by the vue-cli, by using CDN of firebase, Vue, and Vuetify.

            So, I've added links of these CDN in public/index.html as follow:

            ...

            ANSWER

            Answered 2021-Jun-16 at 01:31

            If you are using vuetify from vue-cli-plugin-vuetify (vue add vuetify), treeshaking and auto component import is enabled by default, by using vuetify-loader.

            If you look into the source code of vue-cli-plugin-vuetify, it only uses vuetify-loader if it is present in your package.json. So removing vuetify-loader from package.json should disable this behavior.

            Source https://stackoverflow.com/questions/67995021

            QUESTION

            How strict is the mvc pattern with model and view interactions?
            Asked 2021-Jun-16 at 01:01
            I am confused about how model and view can interact

            I was making a simple to do app with mvc pattern and I saw an article which said you shouldn't pass the model values directly to the view, which made the project more complex than I thought (I am relatively new to programming and this is the first time I am trying out a design pattern).

            But then later on I talked to someone who said that that is not true and you can send the model data directly to view, he didn't even use classes or some kind of grouping to separate the function he just put them in separate files.

            I was wondering if there is a guideline that I couldn't find or we can do whatever we want as long as they are kind of separated. I would love an article or a guide to read up on as well.

            ...

            ANSWER

            Answered 2021-Jun-16 at 01:01

            Since, I am not 100% sure the context in which you are trying to apply the MVC pattern, a good generic explanation of MVC can be found in GoF's 1995 book, Design Patterns: Elements of Reusable Object Oriented Software.

            In the book, they state the following.

            The Model is the application object, the View is its screen presentation, and the Controller defines the way the user interface reacts to user input.

            A more robust explanation can be found from Martin Fowler where he also makes the case for a variation of Model View Controller that uses a Presentation Model.

            If you are referring to Spring MVC then there is some magic that blurs the lines a bit. But in general, you have a controller that represents some screen or an encapsulated piece of functionality that the user (web requests) interact with. The controller serves up responses that are derived from the domain, usually via a Spring Service (i.e. @Service). The domain (Model) doesn't know anything about the View and the View may or may not know anything about the domain.

            Given that, the View should be derived from the Model. But that's not always the case since sometimes how we present things to a screen is not the best logical way to model things in our domain - not to mention, the domain should be presentation agnostic. This leads into Fowler's argument for a Presentation Model, which is a model that belongs to the Presentation.

            I call this a Presentation Model because it's a model that is really designed for and thus part of the presentation layer.

            Microsoft took that idea and ran with it in a variant of MVC called MVVM (Model View ViewModel).

            You can read more about that in Microsoft's documentation on ASP.Net Core.

            So, back to your original question of "Should you pass the model directly to the view?" If you are using MVC then the controller is what provides the interaction. But if you're really asking, "Can you bind your view directly to the model?" If your model has all the stuff you need organized how your view needs it, then sure. And if it's simple enough, maybe that's the way to go. Otherwise, you could go with something like a Presentation Model or MVVM.

            Source https://stackoverflow.com/questions/67993373

            QUESTION

            typescript throws configure not a function error with dotenv and jest
            Asked 2021-Jun-16 at 00:40

            I am trying to use dotenv and jest together, and run into an error immediately.

            A single test file, tests/authenticationt.test.ts with only

            ...

            ANSWER

            Answered 2021-Jun-16 at 00:40

            try require('dotenv').config()

            Source https://stackoverflow.com/questions/67994907

            QUESTION

            Does opening a file in a child process create a separate entry in the system open file table in the kernel?
            Asked 2021-Jun-15 at 23:17

            I understand that after calling fork() the child process inherits the per-process file descriptor table of its parent (pointing to the same system-wide open file tables). Hence, when opening a file in a parent process and then calling fork(), both the child and parent can write to that file without overwriting one another's output (due to a shared offset in the open-file table entry).

            However, suppose that, we call open() on some file after a fork (in both the parent and the child). Will this create a separate entries in the system-wide open file table, with a separate set of offsets and read-write permission flags for the child (despite the fact that it's technically the same file)? I've tried looking this up and I don't seem to be able to find a clear answer.

            I'm asking this mainly since I was playing around with writing to files, and it seems like only one the outputs of the parent and child ends up in the file in the aforementioned situation. This seemed to imply that there are separate entries in the open file table for the two separate open calls, and hence separate offsets, so the slower process overwrites the output of the other process.

            To illustrate this, consider the following code:

            ...

            ANSWER

            Answered 2021-May-03 at 20:22

            There is a difference between a file and a file descriptor (FD).

            All processes share the same files. They don't necessarily have access to the same files, and a file is not its name, either; two different processes which open the same name might not actually open the same file, for example if the first file were renamed or unlinked and a new file were associated with the name. But if they do open the same file, it's necessarily shared, and changes will be mutually visible.

            But a file descriptor is not a file. It refers to a file (not a filename, see above), but it also contains other information, including a file position used for and updated by calls to read and write. (You can use "positioned" read and write, pread and pwrite, if you don't want to use the position in the FD.) File descriptors are shared between parent and child processes, and so the file position in the FD is also shared.

            Another thing stored in the file descriptor (in the kernel, where user processes can't get at it) is the list of permitted actions (on Unix, read, write, and/or execute, and possibly others). Permissions are stored in the file directory, not in the file itself, and the requested permissions are copied into the file descriptor when the file is opened (if the permissions are available.) It's possible for a child process to have a different user or group than the parent, particularly if the parent is started with augmented permissions but drops them before spawning the child. A file descriptor for a file opened in this manner still has the same permissions uf it is shared with a child, even if the child would itself be able to open the file.

            Source https://stackoverflow.com/questions/67375028

            QUESTION

            Loading external CSS files in AMP
            Asked 2021-Jun-15 at 22:09

            How can I load external CSS files like bootstrap.css and other external stylesheets to an html file having AMP? I checked AMP documentation. but didn't got a solution. I have to do SEO for a PHP static site and I am new to AMP and SEO.

            ...

            ANSWER

            Answered 2021-Jun-15 at 10:05

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Files

            Files can be easily used in either a Swift script, a command line tool, or in an app for iOS, macOS, tvOS or Linux.

            Support

            Feel free to open an issue, or find me @johnsundell on Twitter.
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