flipping | Flipping awesome animations | Animation library
kandi X-RAY | flipping Summary
kandi X-RAY | flipping Summary
A library (and collection of adapters) for implementing FLIP transitions.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of flipping
flipping Key Features
flipping Examples and Code Snippets
public static int addByFlip(int n) {
int mask = 1;
// flip all bits in n until rightmost 0 bit
while ((n & mask) != 0) {
n ^= mask;
mask <<= 1;
}
// flip the rightmost 0 bit
public static int getNumberByFlippingBits(int n) {
return n ^ 0xffffffff; // equivalent to 11....1 (32 times) in binary
}
Community Discussions
Trending Discussions on flipping
QUESTION
I am trying to flip a card on space bar. It flips once but does not flip back. I'm flipping the card through a true, false useState and JS keydown event handler. I have an example below that recreates the same problem without all of the other jargon in my original code. It changes to "true" from false after I press space as intended. However, it does not switch back.
Should I be doing this differently? How would you go about this?
...ANSWER
Answered 2022-Apr-16 at 06:53Why its not working is because you are trying to get the updated state inside the function which is called from document.addEventListener. the function that gets called from document.addEventListener never gets the updated state so every time value of isOn is false inside onFlip function. You can use the useRef functionality to achieve your requirement.
QUESTION
I have a sprite that scales to 1 or -1 when moving right or left, if I move fast the finger it works fine, if I drag it slowly it doesn't stay in the left position and keeps flipping left and right. How can I solve it? This is how I handle the character movement:
...ANSWER
Answered 2022-Apr-09 at 19:04//set x flip based on delta
if deltaX < 0 {
player.xScale = -1
} else if deltaX > 0 {
player.xScale = 1
}
QUESTION
I am trying to set a minimum brush size but without the "flipping" as shown in the gif below. I find the data "jump" which results with the flipping visually confusing and would prefer that nothing happen if the user continues to drag a brush handle.
I've seen a few examples for setting minimum brush size (e.g. the answer to this question: Restricting minimum and maximum width of brush box) but they all allow this "flipping" or "mirroring".
Here's the updated "Brush and Zoom" example referenced in the answer. I understand that the code is calculating the percentage of the brush selection relative to the overall width but I am not seeing where the values are being normalized to enable the mirroring (if that makes sense).
How can I prevent this 'flip' when the user is brushing?
...ANSWER
Answered 2022-Mar-29 at 13:10d3.event.selection
for a brush
handler is returning the current brush selection:
Returns the current brush selection for the specified node. ... For a two-dimensional brush, it is [[x0, y0], [x1, y1]], where x0 is the minimum x-value, y0 is the minimum y-value, x1 is the maximum x-value, and y1 is the maximum y-value. For an x-brush, it is [x0, x1]; ...
So, in your animation - when the 'right' hand side becomes the 'left' the underlying array returned for the brushX selection adjusts such that the minimum value is always index 0 and the maximum value is always index 1.
You can detect this with e.g.:
QUESTION
Could anyone help me by adding a simple play/pause button to my text scrolling animation?. I need the button to work as an icon only using and
but display only one icon at a time according to the animation state.
I'm using the js code for flipping from @guradio
...ANSWER
Answered 2022-Mar-25 at 14:44I updated your code.
QUESTION
I need to create a python program that will use various functions to simulate flipping a coin 100 times and finding the largest streak of "H"'s out of 10,000 tries. I am stuck on how to finish the def main() function, specifically the counter. I also don't know if my program is calculating the streaks correctly.
def flipCoin() - returns 'H' or 'T' with the same probability as a coin.
def simulate(numFlips) - simulates flipping a coin numFlips(100) times. This function returns a list of length numFlips containing H's and T's.
def countStreak(flips_list) - iterates through the flips list passed to it and counts streaks of 'H's and returns the largest streak it finds. Keep track of the current number of heads and the current largest streak of heads in two separate variables. As you iterate through the list, keep track of the current number of heads you've seen in a row. If you see a tail, check if the current streak of heads is larger than your current longest streak. If so, save the current streak. Then reset your heads counter.
In the main function, write a testing loop that simulates the process 10000 times. Keep track of the current largest streak of heads and display this result after the test loop completes.
...ANSWER
Answered 2022-Mar-22 at 16:36So there was a flaw in your code, you were running simulate()
function 10000 times. But actually, you had to run it once, but return a list of 10000 items. Also, you need not check the streak every time so the check_streak()
need to be out of the loop and we need to pass the result obtained from simulate(10000)
into it.
Correct Code:
QUESTION
When I try to make an inverse polar transformation to my image, the output is outside of the output image. There are also some weird white patterns on the top. I tried to make the output image larger but the circle is on the left side so it didn't help.
I am trying to make a line circle using warpPolar function, for that first I'm flipping the line and giving it a black area as shown on the image, then using the cv2.warpPolar function with WARP_INVERSE_MAP flag.
How can I fully draw the circle, and get its bounding box is my question.
...ANSWER
Answered 2022-Mar-21 at 18:47Note: I am not getting the same result as you showed above when I tried the same code. You may miss some code lines to add ?
If I didn't misunderstand your problem,you are trying to get this result: (If I am wrong, I will update the answer accordingly)
The only point you are missing is that defining the center and radius. You are making inverse transform here, the input is created by you not warpPolar
. Since you are defining size as (1500,1500), you need to update center and radius accordingly. Here is my code giving this result:
QUESTION
I have a particle emitter which emits multiple duplicates of the same image, as usual. However I'd like some of the particles to be flipped, either completely at a random amount, or sort of in the middle, so that particles falling to the left would be flipped and particles falling to the right won't be.
However I couldn't find anything regarding flipping particles without flipping ALL of them. I'd only like some to be flipped. Is this possible in any way?
...ANSWER
Answered 2022-Mar-18 at 15:55There are serveral way's, I think the "fastest" would be just to use the scaleX
property of the emiter.
this code flips about 10% of the particles
( 0.9 > Math.random() )
, through multiplying it with-1
, when it should be flipped.
Example Code:
QUESTION
Let's say I have a n x m numpy array. For example:
...ANSWER
Answered 2022-Mar-17 at 14:38You can use np.eye
to create a diagnal line of 1's, and use that as a mask:
QUESTION
I'm trying to make a basic coin flipping simulator. And ask the user for their name and greet them. Then ask if they want to play the game. But when they enter something other than "Y"
, it gives this error message: UnboundLocalError: local variable 'time_flip' referenced before assignment
how can I fix that and instead it prints a goodbye message. And ask them again if they want to keep playing.
ANSWER
Answered 2022-Mar-08 at 03:35The assignment of time_flip
may not complete if there is an error transforming the input to an integer.
To resolve, assign to time_flip
before the try
block:
QUESTION
I am working with the R programming language. I created the following "game" in R which involves two players flipping coins (the result of each coin is associated with a "score") to see who gets the highest score:
...ANSWER
Answered 2022-Mar-03 at 17:05Not sure exactly how you want the payoffs you calculate to translate into the payoff matrix, but here's a way you could do it with ggplot2
. Note that the input is a list that has elements ll
, lr
, ul
, ur
for the payoffs that apply to win, lose and tie in the lower-left, lower-right, upper-left and upper-right quadrants. If the vector of payoffs has only two values, the Tie label will not be printed. Here's an example:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install flipping
https://unpkg.com/flipping@latest/dist/flipping.js (core)
https://unpkg.com/flipping@latest/dist/flipping.web.js (WAAPI adapter)
🔜 https://unpkg.com/flipping@latest/dist/flipping.css.js (CSS adapter - WIP!)
In your HTML, add the data-flip-key="..." attribute to shared elements (see HTML example below).
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