gaylord | C Orleans - Distributed Virtual Actor Model | Architecture library

by IronsDu C++ Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(3)Vulnerabilities Install Support

kandi X-RAY | gaylord Summary

gaylord is a C++ library typically used in Architecture applications. gaylord has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

C++ Orleans - Distributed Virtual Actor Model

Support

Quality

Security

License

Reuse

Support

gaylord has a low active ecosystem.

It has 15 star(s) with 3 fork(s). There are 5 watchers for this library.

It had no major release in the last 6 months.

gaylord has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of gaylord is current.

Quality

gaylord has 0 bugs and 0 code smells.

Security

gaylord has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

gaylord code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

gaylord does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

gaylord releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

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gaylord Key Features

No Key Features are available at this moment for gaylord.

gaylord Examples and Code Snippets

No Code Snippets are available at this moment for gaylord.

Community Discussions

Trending Discussions on gaylord

How can I get regular expressions to select appropriate street names using stringr in R?

Trying to get selenium to work property with drop down menu (select element)

QUESTION

How can I get regular expressions to select appropriate street names using stringr in R?

Asked 2022-Jan-04 at 17:35

I am just getting started with regular expressions (working with the stringr package), and I have written some code that does not do exactly what I want it to do. I am working with a dataset with some very messy string data and am trying to clean it up to be used with a google maps API.

I've attached a sample of the data below.

Basically, I want to select every row where loc_01 is a simple street name. By this, I mean I want it to take on the following formats:

A numbered street, such as 10th Ave; A named street, such as MAIN ST, and any directional modification of such street names (such as 10TH AVE NW, W MAIN ST, or W 10TH AVE.)

I have tried the following expression:

...

ANSWER

Answered 2022-Jan-04 at 17:35

One way could be to add an additional filter statement (though I'm sure there's a better way to do it).

Source https://stackoverflow.com/questions/70570587

QUESTION

Get related ID collections from a json array react native

Asked 2020-May-30 at 21:05

I have a array of objects as a json file, I used the objects to display them on the list, When getting to details of that item it has a related items also. I want to show related items for this item Heres the json file

...

ANSWER

Answered 2020-May-30 at 19:36

You can use such function to get element with all related

Source https://stackoverflow.com/questions/62107377

QUESTION

Trying to get selenium to work property with drop down menu (select element)

Asked 2020-Feb-20 at 15:29

I am trying to get selenium to select a specific value from a dropdown menu.

Here is a picture of the elements.

Heres is a code of the element.

...

ANSWER

Answered 2020-Feb-19 at 23:45

You must use Select method like this:

Source https://stackoverflow.com/questions/60310664

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install gaylord

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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