Consus | Consus is a geo-replicated transactional key-value store | Architecture library

 by   rescrv C++ Version: Current License: BSD-3-Clause

kandi X-RAY | Consus Summary

kandi X-RAY | Consus Summary

Consus is a C++ library typically used in Architecture, Kafka applications. Consus has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Consus was the capstone of my Ph.D. thesis. I have since graduated and have other commitments that take me away from maintaining the project. Anyone trying to use the code should beware the following:.
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              Consus has a low active ecosystem.
              It has 222 star(s) with 13 fork(s). There are 18 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 0 open issues and 5 have been closed. On average issues are closed in 0 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Consus is current.

            kandi-Quality Quality

              Consus has no bugs reported.

            kandi-Security Security

              Consus has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Consus is licensed under the BSD-3-Clause License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Consus releases are not available. You will need to build from source code and install.

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            Consus Key Features

            No Key Features are available at this moment for Consus.

            Consus Examples and Code Snippets

            No Code Snippets are available at this moment for Consus.

            Community Discussions

            QUESTION

            How can I change align columns vertically in python?
            Asked 2019-Jul-23 at 04:23

            I have two Lists:

            ...

            ANSWER

            Answered 2019-Jul-23 at 04:09

            QUESTION

            x86 interrupt handler gets blocked when using infinite loop
            Asked 2017-Dec-20 at 17:18

            I'm trying to learn x86 assembly and c language. And now I've finished a simple timer and keyboard interrupts. The firs one can print a line every several ticks and the second can print what you've pressed on keyboard.The code is just like:

            Timer.c:

            ...

            ANSWER

            Answered 2017-Dec-20 at 17:18

            By enabling interrupts inside interrupt handler you don't enable only "others" interrupts, but all interrupts. Including the timer interrupt. (this is too general, payne points out in comment, on x86 there may be different sources of IRQ signals, and particular PIC/APIC chips can be configured to prioritize one over other ... doesn't change anything about the principle of re-entrant IRQ handling, but you can fine-tune which IRQs have priority, which may mean you don't need re-entry lock at all in the end, if your configuration prevents it)

            Your code doesn't look like re-entrant-aware handler, so if that is how your handler code is done, then your timer keeps firing up new timer interrupts as configured, and because you have sti there, they keep re-entering the handler code, filling up slowly stack space until it will overflow (or wrap around, I'm not sure if you are in real or protected mode, and how your stack is set up). Only the last one is of course running, rest is dormant (forever, if the last one doesn't return).

            A long-duration interrupt handlers are usually sign of bad code architecture (aim for shortest + fastest possible interrupt handlers, often just filling up some queue with data, which is processed in async way outside of interrupt handler). But if you really need one, and you can't leave other interrupts disabled, you must write the handler as re-entrant one.

            Source https://stackoverflow.com/questions/47910824

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Consus

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
          • HTTPS

            https://github.com/rescrv/Consus.git

          • CLI

            gh repo clone rescrv/Consus

          • sshUrl

            git@github.com:rescrv/Consus.git

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