Shelly | oriented programming , providing a novel pattern | Architecture library
kandi X-RAY | Shelly Summary
kandi X-RAY | Shelly Summary
A library for business-logic-oriented programming, providing a novel pattern which uses a method chain to illustrate how each component varies with a business object.
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Top functions reviewed by kandi - BETA
- Perform an action on failure
- Perform the given action2
- Perform an action on all registered players
- On failure
- Perform the given action2
- Perform an action on all registered players
- Convenience function to execute adomino failure
- Perform the given action2
- Perform an action on all registered players
- Simplified action
- Completes a domino result
- Executes an action on a successful response
- Performs an action on successful response
- Simplified method for accepting a task
- Completes a domino response
- Executes action on success result
- Performs a successful response
- Creates an anonymous Domino task
- Simplifies the action to execute in the future
- Creates a new TaskDomino accepting the provided target
- Must be called before Executor
- Schedules the runnable
- Completes a domino function
- Creates a new RetrofitDomino 2
- On response failure
- Synchronously wait for the input
- Resume runnable
- Play a domino
- Creates a Domino with the specified window duration
- Gets a copy - on - write - write - write operation list
Shelly Key Features
Shelly Examples and Code Snippets
Lines of Code : 38License : Non-SPDX (NOASSERTION)
CopyShelly.createDomino("Print file names")
.background()
.flatMap((Function1) (input) -> {
File[] files = new File(input).listFiles();
List result = new ArrayList();
for (File file : fil
xiaofei.library
shelly
0.2.8
pom
compile 'xiaofei.library:shelly:0.2.8'
Community Discussions
Trending Discussions on Shelly
QUESTION
I have data in a column that looks like this in a pandas dataframe:
...ANSWER
Answered 2021-May-12 at 19:05def tolist(x):
if isinstance(x, dict):
return [x]
else:
return x
df['Column name'] = df['Column name'].apply(literal_eval).apply(tolist)
df = df.explode('Column name')
QUESTION
First time poster and new to R as a whole, let alone Shiny, so any help is appreciated.
I am wanting to take values from selected rows in one datatable, perform some operations on those numbers (in this example's case that is finding the mean of the two numbers) and then rendering these to a second datatable which will now have a new number but the first column (the 'names' in this case) stays the same. I hope the MRE below illustrates what I am trying to do.
...ANSWER
Answered 2021-May-09 at 05:45Try this -
QUESTION
I am trying to figure out a way to group accounts together which have the same people as joint account holders. There is 1 primary person on an account and up to 4 additional joint account holders. Consider the following example:
Account Primary Joint1 Joint2 Joint3 Joint4 123 Mark Tim Jim Brian John 124 Mark Jim Tim Brian John 134 Jim Mark Tim Brian John 324 Ann Shelly Helen 168 Shelly Ann HelenSo in the above:
- Mark, Tim, Jim, Brian and John are all on accounts 123, 124, 134 and I would want that to be one group
- Ann, Shelly and Helen are all on accounts 324 and 168 and would form another group
I was thinking of going about this by just ordering the Primary and the Joint%s by using case statements and then concatenating the order into one string that I could then group on. So in the case of Ann, Shelly and Helen - ordering them alphabetically would give me Ann, Helen and Shelly and I would concatenate these names together to get "AnnHelenShelly" and group by this string. I have started on this but I am finding it to be a bit messy when I get to situations of 3 or 4 Joint holders on an account. For the case of just a primary and one joint, I just do something like:
case when num_joints = 1 then least(primary, joint1) || greatest(primary, joint1) when num_joints = 2 then least(primary, joint1, joint2) || (case when joint1 > least(primary, joint1, joint2) and joint1 < greatest(primary, joint1, joint2) then joint1 when joint2 > least(primary, joint1, joint2) and joint2 < greatest(primary, joint1, joint2) then joint2 else primary end || greatest(primary, joint1, joint2)
But I am wondering if there is a simpler more scalable way to do this so when I get to num_joints = 3 or 4 it isn't too messy. Or perhaps there's another way to group this without having to create string that is composed of the the primary and joint holders in order.
A couple other notes:
- The primary and joint entries have IDs that are numbers and are unique - so I can order by this ID number
- The Joint entries fill up sequentially based on the number of joints on the account - i.e. if there are 3 joints and a primary on the account, primary has a value as well as joint1, joint2 and joint3 and joint4 would be blank.
ANSWER
Answered 2021-Apr-29 at 05:59Use UNPIVOT to convert the columns into rows, then use LISTAGG to aggregate the names alphabetically per account, and then use LISTAGG again to aggregate the accounts per unique list of names.
This solution is still a bit complicated, and isn't significantly simpler than your CASE version, but it does scale well and it would be trivial to add another column to the solution. The example uses LISTAGG, which is nice for displaying the results, but your final production version probably shouldn't use LISTAGG if you're going to process the results in the database.
QUESTION
I ended up on a mission to document/solve zparseopts this afternoon. I think I found a bug with the -K option - or as I call it -KillYourself.
I think -K is not handling a flag option correctly. The output skews previously existing key/value pairs one-half pair to the left as shown below.
Can a BASH / ZSH guru make sure that I am doing this correctly?
Expected Behavior with -K and additional options and flags:
...ANSWER
Answered 2021-Apr-03 at 01:11The issue is the printout of the values in the associative array. Try replacing the paargs for loop with this:
QUESTION
I was trying to help out some realtor friends by scraping some data off of realtor.com with beautifulsoup.
I am trying to get a list of the names and phone numbers of the realtors but am getting each as a separate item and there are duplicates for every realtor on the page.
This is what I currently have:
...ANSWER
Answered 2020-Nov-30 at 02:40Well you could use selectors in this way
QUESTION
I did a timing experiment and I don't believe I'm using dask.delayed correctly. Here is the code:
ANSWER
Answered 2020-Sep-23 at 17:20The time it takes for my_operation to run is minuscule per row. Even with the "threaded" scheduler, Dask adds overhead per task, and indeed python's GIL means that non-vectorised operations like this cannot actually run in parallel.
Just as you should avoid iterating a pandas dataframe, you should really avoid iterating it, and dispatching every row for dask to work on.
Did you know that Dask had a pandas-like dataframe API? You could do:
QUESTION
#include
#include
using namespace std;
struct studentInfo {
string studentFname, studentLname;
int testScore;
char grade;
}student[20];
void inputs(studentInfo(&student)[20]) {
ifstream openFile;
openFile.open("Students.txt");
if (!openFile.is_open())
cerr << "ERROR! failed to open file\n";
for (int i = 0; i < 20; i++) {
openFile >> student[i].studentFname;
openFile >> student[i].studentLname;
openFile >> student[i].testScore;
}
openFile.close();
}
void grade(studentInfo(&student)[20]) {
for (int i = 0; i < 20; i++) {
if (student[i].testScore >= 90)
student[i].grade = 'A';
if (student[i].testScore >= 80 && student[i].testScore < 90)
student[i].grade = 'B';
if (student[i].testScore >= 70 && student[i].testScore < 80)
student[i].grade = 'C';
if (student[i].testScore >= 60 && student[i].testScore < 70)
student[i].grade = 'D';
else
student[i].grade = 'F';
}
}
void best(studentInfo(&student)[20], int index) {
int largest;
largest = 0;
for (int n = 0; n < 20; n++) {
if (largest < student[n].testScore) {
largest = student[n].testScore;
index = n;
}
}
}
void output(studentInfo(&student)[20], int n) {
ofstream outfile;
outfile.open("StudentGrade.txt");
for (int i = 0; i < 20; i++)
outfile << student[i].studentLname << ", " << student[i].studentFname << " " << student[i].testScore << " " << student[i].grade << endl;
outfile << student[n].studentFname << " " << student[n].studentLname << " has the best grade!";
outfile.close();
}
int main()
{
studentInfo Istudent[20];
int tests[20];
int large = 0;
inputs(Istudent);
for (int i = 0; i< 20; i++)
Istudent[i].testScore= tests[i];
grade(Istudent);
best(Istudent, large);
output(Istudent, large);
return 0;
}
Duckey Donald 85
Goof Goofy 89
Brave Balto 93
Snow Smitn 93
Alice Wonderful 89
Samina Akthar 85
Simba Green 95
Donald Egger 90
Brown Deer 86
Johny Jackson 95
Greg Gupta 75
Samuel Happy 80
Danny Arora 80
Sleepy June 70
Amy Cheng 83
Shelly Malik 95
Chelsea Tomek 95
Angela Clodfelter 95
Allison Nields 95
Lance Norman 88
ANSWER
Answered 2020-Jul-29 at 23:14If student[i] is 87, it will fulfill the second conditional and get a grade of 'B', but then it will also fail the fourth conditional and go into else, getting a grade of 'F' which overwrites the 'B'.
Only your fourth if is associated with the else. The above three are independent so the checks will occur unnecessarily.
QUESTION
I am currently trying to install stack to utilise the software Taiji. I have been able to run 'stack setup', but get an error when I run stack install:
...ANSWER
Answered 2020-Jul-29 at 05:49When you see this error, you will need to open stack.yaml (the error message contains the full path), find the line saying # extra-deps: [], and replace it with the line shown in the error message:
QUESTION
I have following two tables
...ANSWER
Answered 2020-Jun-15 at 06:36The UNION operator allows you to combine two or more result sets of queries into a single result set.
For more : Reference
QUESTION
I've researched and tried some of the suggestions on stack overflow, but the code doesn't seem to be working. I've been trying to move a node, by copying and then deleting the node, but everything ends up getting deleted in firebase (original and copied post).
Goal: move the data from under the child "pending" to child "post" after the user hits a button.
I want to move Shelly A. pending post under post.
Firebase database:
...ANSWER
Answered 2020-Mar-31 at 03:29If you see a change being made briefly before being rolled back, most commonly this happens because you have a security rule that rejects the change.
In that case, the client first fires the local events for the change, then sends the change to the server. Then when it hears back from the server that the change was rejected, it fires local events to get the state correct again.
So it sounds like in your case you are allowed to delete the node from pending, but not allowed to add the data under posts.
A good way to prevent this type of partial operation is to include both the delete and the write in a single, multi-location update operation.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Shelly
You can use Shelly like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the Shelly component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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