ServiceFramework | Java MVC framework , agile , fast , rich domain model | Model View Controller library

by allwefantasy Java Version: 1.0 License: No License

X-Ray Key Features Code Snippets Community Discussions(6)Vulnerabilities Install Support

kandi X-RAY | ServiceFramework Summary

ServiceFramework is a Java library typically used in Architecture, Model View Controller applications. ServiceFramework has no bugs, it has no vulnerabilities, it has build file available and it has low support. You can download it from GitHub, Maven.

ServcieFramework 定位在移动互联网后端领域,强调开发的高效性，其开发效率可以比肩Rails.

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Quality

Security

License

Reuse

Support

ServiceFramework has a low active ecosystem.

It has 548 star(s) with 271 fork(s). There are 164 watchers for this library.

It had no major release in the last 12 months.

There are 49 open issues and 9 have been closed. On average issues are closed in 110 days. There are 8 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of ServiceFramework is 1.0

Quality

ServiceFramework has 0 bugs and 0 code smells.

Security

ServiceFramework has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

ServiceFramework code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

ServiceFramework does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

ServiceFramework releases are not available. You will need to build from source code and install.

Deployable package is available in Maven.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

ServiceFramework saves you 12579 person hours of effort in developing the same functionality from scratch.

It has 25346 lines of code, 2495 functions and 350 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed ServiceFramework and discovered the below as its top functions. This is intended to give you an instant insight into ServiceFramework implemented functionality, and help decide if they suit your requirements.

Load all controllers
Register a handler
Bind an action to a controller
Connect to the database
Retrieve information about a connection
Find all CLASSP paths that match the given paths
Validates the target field
Parse the target field
Find all class paths
Load services
Translate a Map to a DBObject
Gets setting groups
Writes an array of bytes to the output stream
Main entry point
Convert server to server
Invokes an endpoint
Execute a single SQL query
Called after a result set has been closed
Splits a space into a list of strings
Decode a query string
Borrow an object from the pool
Splits a string using a separator
Converts a UTF8 byte array into a UTF8 character sequence
Get information about database
Loads the modules
Returns a string representation of this duration

Get all kandi verified functions for this library.

ServiceFramework Key Features

No Key Features are available at this moment for ServiceFramework.

ServiceFramework Examples and Code Snippets

No Code Snippets are available at this moment for ServiceFramework.

Community Discussions

Trending Discussions on ServiceFramework

Python :Unable to start installed windows service

Run Python script as a windows service

Service can't start on boot but can start on manual

import win32service, win32api, win32con, winerror ImportError: DLL load failed: The specified module could not be found

Detecting USB Device Insertion on Windows 10

How to exit cleanly from flask and waitress running as a windows pywin32 service

QUESTION

Python :Unable to start installed windows service

Asked 2021-Oct-20 at 05:58

I have created a windows service in python and then convert it into an exe file and install that exe file as a windows service using this command :

...

ANSWER

Answered 2021-Oct-20 at 05:58

I have made some changes to your code I hope after that it will start working.

Source https://stackoverflow.com/questions/69491050

QUESTION

Run Python script as a windows service

Asked 2021-Oct-12 at 10:05

I know this question was asked so many times. I read all those questions but i didn't find out my problem's solution. My issue is that i have created below window service with help of this link. How do you run a Python script as a service in Windows? and I am running this service from command prompt. Here is my python script that i need to run as a service.

...

ANSWER

Answered 2021-Oct-12 at 10:05

Just a few days back I have successfully sorted out my issue I just made some changes to my code and it started working properly. I am only posting these answers for someone like me who got this issue in the future he can easily sort it out. This is the new code:

Source https://stackoverflow.com/questions/69008155

QUESTION

Service can't start on boot but can start on manual

Asked 2020-May-22 at 08:51

I have python project using servicemanager and I use pyinstaller to build it as exe. Everything work fine and I have install it as window service.

I have set services startupType: Automatic(Delayed start).

But when I reboot computer the services is not start and I have to go to services and start it manual.

I check event viewer and it say:

...

ANSWER

Answered 2020-May-22 at 08:51

Sorry for wrong information. Error above is old error when i test service.

Error is:

A timeout was reached (30000 milliseconds) while waiting for the TestService service to connect.

And increase timeout for window service will solve the problem

Source https://stackoverflow.com/questions/61929700

QUESTION

import win32service, win32api, win32con, winerror ImportError: DLL load failed: The specified module could not be found

Asked 2020-Mar-19 at 19:23

I'm trying to create a Microsoft Service, but this error appears, the complete name error:

"File "PythonCornerExample.py", line 1, in import win32serviceutil File "C:\Users\User\AppData\Local\Packages\PythonSoftwareFoundation.Python.3.7_qbz5n2kfra8p0\LocalCache\local-packages\Python37\site-packages\win32\lib\win32serviceutil.py", line 9, in import win32service, win32api, win32con, winerror

ImportError: DLL load failed: The specified module could not be found.".

I've already tried to install Visual C++ redistributable 2015, but the error still exist.

This is the code:

...

ANSWER

Answered 2020-Mar-19 at 19:23

You just need to reinstall python in 64bit

link: https://www.python.org

Source https://stackoverflow.com/questions/60762346

QUESTION

Detecting USB Device Insertion on Windows 10

Asked 2020-Mar-12 at 19:36

I can't get the following code for Detecting USB Device Insertion to work on my Windows 10 (64 bit) computer with Python 3.7.

...

ANSWER

Answered 2020-Mar-12 at 19:36

I tested with Python 3.8.2 x64.

Install pywin32 (pip install pywin32)
Install the current/last version (1.5) of the WMI module from https://github.com/tjguk/wmi (pip install -e git+https://github.com/tjguk/wmi.git#egg=wmi)
run a script (test.py in my case), like:

Source https://stackoverflow.com/questions/59868022

QUESTION

How to exit cleanly from flask and waitress running as a windows pywin32 service

Asked 2020-Jan-28 at 10:11

I have managed to cobble together a working demo of a pywin32 windows service running flask inside the pylons waitress wsgi server (below). A niece self contained solution is the idea..

I have spent hours reviewing and testing ways of making waitress exit cleanly (like this and this) but the best I can do so far is a kind of suicidal SIGINT which makes Windows complain "the pipe has been ended" when stopping through the Services control panel, but at least it stops :-/ I guess the pythonservice.exe which pywin32 starts, should not terminate, just the waitress treads?

To be honest I'm still uncertain if this is a question about waitress, pywin32, or maybe its just plain python. I do have the feeling the answer is right in front of me but right now I'm completely stumped.

Any suggestions welcome!

...

ANSWER

Answered 2020-Jan-28 at 10:11

I have found a solution using a sub-thread that seems to work. Not quite sure if this may have possible unintended consequences yet..

update:

I believe the updated version below, "injecting" a SystemExit into the waitress thread is as good as it gets. I think thee original kills the thread hard, but this one prints "thread done" indicating a graceful shutdown.

Corrections or improvements welcome!

Source https://stackoverflow.com/questions/59893782

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install ServiceFramework

Step 1 > 克隆项目. Step 2 > 导入到IDE. Step 3 > 根据你自己的数据库信息编辑修改 config/application.yaml .注意如果你使用mysql,需要disable 调 mongodb.反之亦然. Step4 > 在Mysql中导入 sql/wow.sql. Step5 > 新建 com.example.model.Tag 类. Step6 > 新建 com.example.controller.http.TagController. Step7 > 新建 template/tag/hello.vm. Step9 > 运行 ExampleApplication. Step10 > 浏览器中输入 http://127.0.0.1:9002/hello .同时查看数据库，你会发现tag表已经有数据了。. Step11 > 写个Action单元测试编辑 runner.DynamicSuite 在 initEnv方法第一行处添加. Step12 > 创建测试类 test.com.example.TagControllerTest. Step13 > 运行 DynamicSuiteRunner 跑起测试.
application 文件数据连接配置错误。单元测试一定需要单独配置test的配置。因为单元测试一般可能会会有数据清理等，系统强制使用 test的配置。
ServiceFramework 是使用配置文件来找类并且加载的，所以你需要正确配置contorller等所在位置。在上述测试中，包名和类名必须保证和示例一致。如果你需要使用不同的package,那么你需要修改application.yml中的application 配置。如下: application: controller: com.example.controller.http model: com.example.model document: com.example.document service: com.example.service util: com.example.util test: test.com.example
ActiveORM
MongoMongo