kandi X-RAY | StringSearch Summary
kandi X-RAY | StringSearch Summary
High-performance pattern matching algorithms in Java
Top functions reviewed by kandi - BETA
- Returns serializable object
- Compute the minimum number of x
- Returns a charMap of the specified pattern indices
- Search for a pattern in the pattern
- Calls the super method
- Returns a hashCode of this Object
- Returns true if this object equals another object
- Returns the skip index of a pattern
- Performs a regex search
- Performs a search
- Search for bytes in pattern
- Translate a byte array into a byte array
- Search for a pattern in the specified pattern
- Returns a subset of characters
- Search for matches in the pattern
- Returns serializable object serializable
- Processes a single character
- Process the byte pattern
- Returns a map of characters for the specified pattern
StringSearch Key Features
StringSearch Examples and Code Snippets
Trending Discussions on StringSearch
I would to install this program
What is the simple way to do so ?
If I try to build it locally with...
ANSWERAnswered 2022-Feb-15 at 00:22
A solution is below. Alternatively, you can clone from:
I'm trying to find the substring in string using O(N) complexity. The following is the code I have written. It returns undefined and I don't know why. Please let me know what is going wrong in my code....
ANSWERAnswered 2021-Dec-21 at 05:27
I see a couple of issues. First, the code doesn't have a return statement for every logical branch. I mean that, for every condition in an if, then, else statement, the code should have a return statement or some sort of control-flow statement (e.g. a recursive call or a continue) that will eventually lead to a return statement.
The second issue is the
while loop. Supposedly,
right should be greater than
left from the beginning of the function (unless the length of
smallString is 0) because
right is the length of
smallerString minus 1. The
while condition is
left > right, so nothing inside of the while will be executed unless
smallString has a negative length (which it doesn't).
By the way, if you want to check the entire
bigString, you will need to iterate over
smallString. If you are only checking
smallString.length characters, you won't be checking the entire
bigString. Figuring out how to write this function is a good exercise, so I will leave the writing of it to you and refrain from providing an implementation myself. Keep up the good work!
line2=input("What starting line number do you need? ")
line1=input("What closing line number do you need? ")
string = input("What string do you like to search in this test case: ")
with open('texfile') as f:
lines = f.readlines()
for line in lines:
print ("String found")
ANSWERAnswered 2021-Apr-07 at 08:34
- Variable naming
Why line2 followed by line1? Better to name in successive order i.e. line1, line2.
Or even better relate variable name to its purpose and use Python naming convention thus:
I'm trying to release an especific invoice from Invoices and Memos screen (AR301000) using the SOAP API as documented in the I210 Contract Based Web Services guide.
Debugging my code, When I release the especific invoice I get this error:...
ANSWERAnswered 2020-Nov-13 at 03:19
The first thing you need to make sure that your invoice is not on hold - if it is on hold then the entity returned by the Get will be empty. That could be a problem.
Also, can you please try using ReleaseInvoice() instead of Release() in the invoke?
InvokeResult invokeResult = client.Invoke(invoice, new ReleaseInvoice());
That has worked for me in the past.
In iOS I am using two strings to combine and to form a single string. But the combined string must be of 16 characters . So if two strings are small and if we combine both and if it is less than 16 characters I must add few more characters to make it to 16 characters. How to achieve this?...
ANSWERAnswered 2020-Nov-04 at 07:03
Something like below
This lab is trying to show the use of coder-defined functions to execute the code, but I'm trying to do it alternatively so when we actually are tested on it I won't be freaking out that I just copied the source code....
ANSWERAnswered 2020-Mar-09 at 09:54
Apart from the issues pointed out in the comments there is some things you should improve:
char * string = (char *) malloc(WordSize * sizeof(char));is the same as
char * string = malloc(WordSize), but for a 20 word string we will need
char * string = malloc(WordSize + 1)
This part of the code:
I'm trying to use Microsoft Graph to make a file search. I use this entry point : https://graph.microsoft.com/beta/search/query My application do not use a user account but a daemon with an application key (see auth method). And i send a built object.
My java code is rather simple :...
ANSWERAnswered 2020-Mar-04 at 08:24
I am currently stuck with a problem. I am supposed to write a programm that is able to search for a string in a .txt file given as argument. The programm must return the row and the column of the found string. I am struggling to find a way to achieve that and have no idea how to go on. I would be very happy to hear from you.
Here is my attempt in tackling with my task: - I thought about saving the content of a file via a buffered reader in a string array, but that does not seem to work since I cannot define the length of the array from the beginning - I also thought about saving the content of the file via a buffered reader in a string and then split this string in characters. However I am not sure how I will be able to retreieve the rows in the original file then.
This is the non-functional code that I have at the moment:...
ANSWERAnswered 2020-Feb-01 at 13:09
Here's one approach -
- Let's consider a counter which holds a counter for all the
readLine()method invocations - representing the "row" in the .txt file. So, increment the counter after every readLine call in the while loop.
- Next, split the line on " " (space) to get an array of each word in the line. Then, you could iterate over this array and match the word to the search string. The position of array index at the time the match was found will represent the "column".
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