CC | first Android componentized open source framework | Architecture library

 by   luckybilly Java Version: v2.1.6 License: Apache-2.0

kandi X-RAY | CC Summary

kandi X-RAY | CC Summary

CC is a Java library typically used in Architecture applications. CC has no vulnerabilities, it has build file available, it has a Permissive License and it has medium support. However CC has 6 bugs. You can download it from GitHub.

The industry's first Android componentized open source framework that supports gradual componentized transformation, and supports cross-process calls. Componentize your android project gradually.
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            kandi-support Support

              CC has a medium active ecosystem.
              It has 3976 star(s) with 621 fork(s). There are 113 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 22 open issues and 140 have been closed. On average issues are closed in 27 days. There are 3 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of CC is v2.1.6

            kandi-Quality Quality

              CC has 6 bugs (0 blocker, 0 critical, 5 major, 1 minor) and 116 code smells.

            kandi-Security Security

              CC has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              CC code analysis shows 0 unresolved vulnerabilities.
              There are 5 security hotspots that need review.

            kandi-License License

              CC is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              CC releases are not available. You will need to build from source code and install.
              Build file is available. You can build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              CC saves you 2369 person hours of effort in developing the same functionality from scratch.
              It has 5168 lines of code, 416 functions and 118 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed CC and discovered the below as its top functions. This is intended to give you an instant insight into CC implemented functionality, and help decide if they suit your requirements.
            • Format JSON string .
            • Send login result .
            • convert parameter to java
            • Invokes a callback .
            • Create bridge web view .
            • Proceed the interceptor .
            • Get the process name for a component
            • Gets the process name .
            • Intercept the CC
            • Gets the text view .
            Get all kandi verified functions for this library.

            CC Key Features

            No Key Features are available at this moment for CC.

            CC Examples and Code Snippets

            Convert bytes to CC source code .
            pythondot img1Lines of Code : 118dot img1License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _convert_bytes_to_cc_source(data,
                                            array_name,
                                            max_line_width=80,
                                            include_guard=None,
                                            include_path=None,
                            

            Community Discussions

            QUESTION

            Debunking outlook email features with library win32com
            Asked 2021-Jun-16 at 03:53

            I found ways to check with python using library win32com for outlook the following attributes for any given email.

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:53
            1. Use MailItem.Recipients collection.
            2. See #1 and check for each recipient's Recipient.Type property equal olCC ( =2)
            3. Of course - set the MailItem.Categpries property. Don't forget to call MailItem.Save
            4. Use the MailItem.SenderEmailAddress. For the sent on behalf of address, read the PR_SENT_REPRESENTING_EMAIL_ADDRESS MAPI property. Access it using MailItem.PropertyAccessor.GetProperty("http://schemas.microsoft.com/mapi/proptag/0x0065001F")

            In general, take a look at various Outlook object using OutlookSpy to familiarize yourself with the Outlook Object Model.

            Also keep in mind that to access a subfolder of the Inbox folder, it is better to use something like

            Source https://stackoverflow.com/questions/67978213

            QUESTION

            Does Comparison Function specified with lambda function in std::sort return bool type?
            Asked 2021-Jun-16 at 03:09

            I was reading this code (source):

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:16

            The n2 - n1 in the case of a negative number as a result when converted to bool will yield true. So n1 turns out to be less than n2. That's why it is a bad practice to use ints in such Boolean context.

            Yes, as stated in the documentation:

            ...comparison function object which returns ​true if the first argument is less than the second

            But the implementation of the comparison here leads to failure. Try this and see for yourself:

            Source https://stackoverflow.com/questions/67995381

            QUESTION

            What is simplest way to prevent frame drop in flutter application on heavy task?
            Asked 2021-Jun-16 at 00:29

            I've ran into problem getting UI lags when this line is running:

            ...

            ANSWER

            Answered 2021-Jun-16 at 00:29

            I don't believe you can use SharedPreferences within an Isolate without support for MethodChannel / accessing platform-specific underlying OS frameworks on iOS / Android.

            You would need to use FlutterIsolate or a similar package to provide that support.

            chunhunghan has a good answer detailing this.

            Alternatively, you could run the crypt.generateKeys() by itself in your Isolate.spawn() call and use the results after in a separate method accessing SharedPreferences. (Assuming that crypt package is also not relying on platform-specific code.)

            Source https://stackoverflow.com/questions/67993518

            QUESTION

            How can I find to access to GPUs via Tensorflow in PyCharm?
            Asked 2021-Jun-15 at 14:43

            I have a problem about not accessing GPU in PyCharm and I use NVIDIA as GPU.

            I installed tensorflow-gpu in Python Interpreter of Setting part in Pycharm and then I run the code but I still cannot access it.

            I wonder if I should use CUDA library? How can I fix it?

            Here is my code snippet which is shown below.

            ...

            ANSWER

            Answered 2021-Jun-14 at 11:14

            I fixed my issue.

            Here are the steps of solving that issue.

            1 ) Download CUDA from https://developer.nvidia.com/cuda-downloads

            2 ) Download CUDNN from https://developer.nvidia.com/rdp/cudnn-download

            3 ) Copy bin,include and lastly lib from CUDNN zip file and paste it C:\Program Files\NVIDIA GPU Computing Toolkit\CUDA{version}

            4 ) Then run the .py code in PyCharm and it perceives GPU at last.

            Source https://stackoverflow.com/questions/67952801

            QUESTION

            JSF - Validation error in 1 component, leads all others in the form to fail
            Asked 2021-Jun-15 at 14:11

            Hey to all in the forum

            I use JSF Mojarra implementation, version JSF 2.2

            I need desperately a help on this.

            1. I have a snippet of my page.
            2. I have a custom component "example_result.xhtml" used in the page.
            3. I have my BackingBean.java Be aware please that this code is not the real code I made. If you run it, it will be very ugly maybe because I deleted all the css classes and I kept only the hot stuff I need to show you my problem.

            Everything is inside 1 form.

            The 5 "h:selectManyCheckbox" (in my code I have 8 or 9)

            In the form I have 5 "h:selectManyCheckbox" which are using values in the "value" attribute for different cases (javaFrameworks2Values, javaFrameworks3Values,...), and the "f:selectItems" use arrays of "SelectItem" (javaFrameworksSelectItems2, javaFrameworksSelectItems3...) created for these different cases, just to make some examples for me to understand how all the selectOne and selectMany components work. The ideas for this, about different cases were taken from these links: "https://stackoverflow.com/tags/selectonemenu/info" and "https://mkyong.com/jsf2/jsf-2-checkboxes-example".

            After I have 2 commandButtons

            1 for submit, and 1 for reset the values.

            Display the values

            After I display the results of the values of the "h:selectManyCheckbox" via the "example_result.xhtml".

            You can see the 4th "h:selectManyCheckbox" that is the only one different, because it has the attribute "required" with the attribute "requiredMessage". With it there is a "h:message" to display the validation error.

            In the BackingBean (which is Spring Bean, but it works perfectly good - sorry I don't want ejbs 3.x), I have initialized:

            1. The values of the SelectItems and
            2. The values of the "value" attribute, where the values of the "h:selectManyCheckbox" will be stored to be displayed later. [The code is completely castrated, to make it readable snippet].

            When the page is rendered, I select checkBoxes (e.g. the 2 last, because the 2 first are initials) from all the "h:selectManyCheckbox". When I say that select from all, I mean it. And from the 4th with the "required" attribute. I try in the buttons (see in the code) the "Effort 1", or "Effort 2", or "Effort 3" (in the "f:ajax" in the buttons) and the result outputs in the last part are displayed and updated like a candy. Without any problem. To achive this with the composite component I googled and tried a lot. But I made it.

            Then it comes the time to try the 4th to see the validation error of the "required" attribute.

            I select again from all as before, but not from all. NOT from the 4th "h:selectManyCheckbox" this time. I select nothing from the 4th "h:selectManyCheckbox" to ckeck the validator error message ("requiredMessage"). The result is: It displays the message of error (GOOD until now), BUT this time it does not update anything from the others "h:selectManyCheckbox" to the output results at the end, and it does not reset the values as well as it was doing before (when I selected from all and from the 4th as well).

            I understand that it says: as long as in the form the 4th failed with validation error, all the other "h:selectManyCheckbox" will not update the output results (something like wanting to fail all the others too).

            But what really happes here?

            1. It does not give the values to the "h:selectManyCheckbox", to be updated to the output?
            2. It gives the vales to the "h:selectManyCheckbox" normally, BUT it just not updates the output?

            The other efforts in the "f:ajax" in the buttons, are just efforts maybe to solve the problem but in these cases they don't even display the error message in the 4th case and of cource they don't update the other output results as well (again). But no message error as well.

            I don't know if the problem is clear to you. I can explain in the discussion better so I can clarify the situation better. [To be honnet it took me 1 and half hour to write all this thing]

            Thanks a lot in advance

            ========== Snippet from my page ==========

            ...

            ANSWER

            Answered 2021-Jun-15 at 14:11

            After a lot of discussing with the only person who wanted to help to my issue here (and I thank him @WoAiNii for this a lot), I decided to post my solution:

            I will make 5 different forms with 5 set of buttons (submit/reset), to make escalate this problem, for 5 so much related components in the form.

            But my question is open: Why this is happening, what rule in JSF in this case is taking place and makes this situation. Anyone, comes with an explanation:

            • Thomas: this is a rule in JSF, or
            • is a JSF bug, or
            • this happens in these cases, or... whatever...,

            I will be glad to read it here so I will learn better, and others to will learn from these ideas of yours. Thanks a lot

            Source https://stackoverflow.com/questions/67750994

            QUESTION

            Problem with FULLY_CONNECTED op in TF Lite
            Asked 2021-Jun-15 at 13:22

            I'd like to run a simple neural network model which uses Keras on a Rasperry microcontroller. I get a problem when I use a layer. The code is defined like this:

            ...

            ANSWER

            Answered 2021-May-25 at 01:08

            I had the same problem, man. I want to transplant tflite to the development board of CEVA. There is no problem in compiling. In the process of running, there is also an error in AddBuiltin(full_connect). At present, the only possible situation I guess is that some devices can not support tflite.

            Source https://stackoverflow.com/questions/67677228

            QUESTION

            Using TensorFlow with GPU taking a long time for loading library related to CUDA
            Asked 2021-Jun-15 at 13:04

            Machine Setting:

            • GPU: GeForce RTX 3060

            • Driver Version: 460.73.01

            • CUDA Driver Veresion: 11.2

            • Tensorflow: tensorflow-gpu 1.14.0

            • CUDA Runtime Version: 10.0

            • cudnn: 7.4.1

            Note:

            1. CUDA Runtime and cudnn version fits the guide from Tensorflow official documentation.
            2. I've also tried for TensorFlow-gpu = 2.0, still the same problem.

            Problem:

            I am using Tensorflow for an objection detection task. My situation is that the program will stuck at

            2021-06-05 12:16:54.099778: I tensorflow/stream_executor/platform/default/dso_loader.cc:42] Successfully opened dynamic library libcublas.so.10

            for several minutes.

            And then stuck at next loading process

            2021-06-05 12:21:22.212818: I tensorflow/stream_executor/platform/default/dso_loader.cc:42] Successfully opened dynamic library libcudnn.so.7

            for even longer time. You may check log.txt for log details.

            After waiting for around 30 mins, the program will start to running and WORK WELL.

            However, whenever program invoke self.session.run(...), it will load the same two library related to cuda (libcublas and libcudnn) again, which is time-wasted and annoying.

            I am confused that where the problem comes from and how to resolve it. Anyone could help?

            Discussion Issue on Github

            ===================================

            Update

            After @talonmies 's help, the problem was resolved by resetting the environment with correct version matching among GPU, CUDA, cudnn and tensorflow. Now it works smoothly.

            ...

            ANSWER

            Answered 2021-Jun-15 at 13:04

            Generally, if there are any incompatibility between TF, CUDA and cuDNN version you can observed this behavior.

            For GeForce RTX 3060, support starts from CUDA 11.x. Once you upgrade to TF2.4 or TF2.5 your issue will be resolved.

            For the benefit of community providing tested built configuration

            CUDA Support Matrix

            Source https://stackoverflow.com/questions/67847219

            QUESTION

            Dynamic Library error while using Tensorflow with GPU
            Asked 2021-Jun-15 at 10:13

            I am programming in Python 3.8 with Tensorflow installed along with my natural language processing project. When I want to begin the training phase, I get this message right before I begin...

            ...

            ANSWER

            Answered 2021-Mar-10 at 14:44

            I would suggest you to use conda (Ananconda/Miniconda) to create a separate environment and install tensorflow-gpu, cudnn and cudatoolkit. Miniconda has a much smaller footprint than Anaconda. I would suggest you to install Miniconda if you do not have conda already.

            Quick Installtion

            Source https://stackoverflow.com/questions/66553987

            QUESTION

            postfix and openJDK 11: "No appropriate protocol (protocol is disabled or cipher suites are inappropriate)"
            Asked 2021-Jun-15 at 08:30

            I know there are some other questions (with answers) to this topic. But no of these was helpful for me.

            I have a postfix server (postfix 3.4.14 on debian 10) with following configuration (only the interesting section):

            ...

            ANSWER

            Answered 2021-Jun-15 at 08:30

            Here I'm wondering about the line [in s_client]
            New, TLSv1/SSLv3, Cipher is ECDHE-RSA-AES256-GCM-SHA384

            You're apparently using OpenSSL 1.0.2, where that's a basically useless relic. Back in the days when OpenSSL supported SSLv2 (mostly until 2010, although almost no one used it much after 2000), the ciphersuite values used for SSLv3 and up (including all TLS, but before 2014 OpenSSL didn't implement higher than TLS1.0) were structured differently than those used for SSLv2, so it was important to qualify the ciphersuite by the 'universe' it existed in. It has almost nothing to do with the protocol version actually used, which appears later in the session-param decode:

            Source https://stackoverflow.com/questions/67899129

            QUESTION

            how to sort a map by key when the values are the same?
            Asked 2021-Jun-14 at 21:54

            I'm currently sorting the map by value, but I couldn't think on how I would have it sorted by key for the cases that I have the same value.

            Currently it works like this:

            ...

            ANSWER

            Answered 2021-Jun-14 at 21:54

            You could check in your Comparator if the values are the same and if so compare the keys. Here is your adapted method:

            Source https://stackoverflow.com/questions/67977488

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install CC

            You can download it from GitHub.
            You can use CC like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the CC component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone luckybilly/CC

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