Puzzle | A simple puzzle game for 3-4 year olds | Game Engine library

by Troll-Olav JavaScript Version: Current License: No License

X-Ray Key Features Code Snippets(4)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | Puzzle Summary

Puzzle is a JavaScript library typically used in Gaming, Game Engine, Pygame applications. Puzzle has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

A simple puzzle game for 3-4 year olds.

Support

Quality

Security

License

Reuse

Support

Puzzle has a low active ecosystem.

It has 7 star(s) with 2 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

Puzzle has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of Puzzle is current.

Quality

Puzzle has 0 bugs and 0 code smells.

Security

Puzzle has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Puzzle code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Puzzle does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

Puzzle releases are not available. You will need to build from source code and install.

Top functions reviewed by kandi - BETA

kandi has reviewed Puzzle and discovered the below as its top functions. This is intended to give you an instant insight into Puzzle implemented functionality, and help decide if they suit your requirements.

Traverse the children tree .
Mixin for the component class
Injects the event listeners .
Instantiate native React component .
Determines if react element has changed .
Calculate the intersection of a list
Determine the composition event .
Computes the summary of a list of identifiers .
Determines selection offsets .
Extracts characters from fallback characters .

Get all kandi verified functions for this library.

Puzzle Key Features

No Key Features are available at this moment for Puzzle.

Puzzle Examples and Code Snippets

Step 12: Programming Puzzle Set PP_02

Java

Lines of Code : 27

License : No License

Copy


	try {	
			AmountAdder.addAmounts(new Amount("RUPEE", 5), new Amount("RUPEE", 5);
			String str = null;
			str.toString();
		} catch(CurrenciesDoNotMatchException ex) {
			ex.printStackTrace();
		}




	try {
			AmountAdder.addAmounts(new Amount("RU

Prints the top of the puzzle .

java

Lines of Code : 13

License : No License

Copy

public static void main(String[] args) {
        List terms = Arrays.asList(
                "Coding is great",
                "Search Engine are great",
                "Google is a nice search engine",
                "Bing is also a nice engine")

Prints the puzzle 1 . 0

java

Lines of Code : 13

License : Permissive (MIT License)

Copy

private static void puzzle1() {
		int k = 15;
		if (k > 20) {
			System.out.println(1);
		} else if (k > 10) {
			System.out.println(2);
		} else if (k < 20) {
			System.out.println(3);
		} else {
			System.out.println(4);
		}
		
	}

Print a puzzle 5 .

java

Lines of Code : 7

License : Permissive (MIT License)

Copy

private static void puzzle5() {
		int number = 5;
		if(number < 0) 
		    number = number + 10; 
		number++; 
		System.out.println(number);
	}

Community Discussions

Trending Discussions on Puzzle

Is there a concept in the standard library that tests for usability in ranged for loops

Why does float('inf') == float('inf') return True, but float('inf') - float('inf') == float('inf') returns False?

How to calculate when one's 10000 day after his or her birthday will be?

Why MOV instruction is replaced by ADD instruction

Count nodes within k distance of marked nodes in grid

Lenses, the State monad, and Maps with known keys

What is the correct way to install Android Studio Bumblebee 2021.1.1 Patch 1

Overloading operator () instead of [] for indexing

Why can't we use compile-time 'variables' in consteval functions as template parameters?

filtering a stream changes its wildcard bounds?

QUESTION

Is there a concept in the standard library that tests for usability in ranged for loops

Asked 2022-Apr-14 at 09:51

There are a number of different ways, that make a type/class usable in a ranged for loop. An overview is for example given on cppreference:

range-expression is evaluated to determine the sequence or range to iterate. Each element of the sequence, in turn, is dereferenced and is used to initialize the variable with the type and name given in range-declaration.

begin_expr and end_expr are defined as follows:

If range-expression is an expression of array type, then begin_expr is __range and end_expr is (__range + __bound), where __bound is the number of elements in the array (if the array has unknown size or is of an incomplete type, the program is ill-formed)

If range-expression is an expression of a class type C that has both a member named begin and a member named end (regardless of the type or accessibility of such member), then begin_expr is __range.begin() and end_expr is __range.end()

Otherwise, begin_expr is begin(__range) and end_expr is end(__range), which are found via argument-dependent lookup (non-ADL lookup is not performed).

If I want to use a ranged for loop say in a function template, I want to constrain the type to be usable in a ranged for loop, to trigger a compiler error with a nice "constraint not satisfied" message. Consider the following example:

...

ANSWER

Answered 2022-Apr-14 at 09:51

It seems like what you need is std::ranges::range which requires the expressions ranges::begin(t) and ranges::end(t) to be well-formed.

Where ranges::begin is defined in [range.access.begin]:

The name ranges::begin denotes a customization point object. Given a subexpression E with type T, let t be an lvalue that denotes the reified object for E. Then:

If E is an rvalue and enable_borrowed_range> is false, ranges::begin(E) is ill-formed.

Otherwise, if T is an array type and remove_all_extents_t is an incomplete type, ranges::begin(E) is ill-formed with no diagnostic required.

Otherwise, if T is an array type, ranges::begin(E) is expression-equivalent to t + 0.

Otherwise, if auto(t.begin()) is a valid expression whose type models input_or_output_iterator, ranges::begin(E) is expression-equivalent to auto(t.begin()).

Otherwise, if T is a class or enumeration type and auto(begin(t)) is a valid expression whose type models input_or_output_iterator with overload resolution performed in a context in which unqualified lookup for begin finds only the declarations

Source https://stackoverflow.com/questions/71868477

QUESTION

Why does float('inf') == float('inf') return True, but float('inf') - float('inf') == float('inf') returns False?

Asked 2022-Mar-09 at 18:42

Why does this happen in Python?

float('inf') == float('inf') returns True,
float('inf') + float('inf') == float('inf') returns True,
float('inf') * float('inf') == float('inf') returns True,
float('inf') - float('inf') == float('inf') returns False,
float('inf') / float('inf') == float('inf') returns False.

My best guess, if I think about limits, is related with the result of this operation:

lim_x→+∞(f(x) ▢ g(x)) where lim_x→+∞ f(x) = +∞ and lim_x→+∞ g(x) = +∞, which returns +∞ if ▢ is + or *, but it is not defined (it could return every value) if ▢ is - or /.

I am very puzzled, though.

...

ANSWER

Answered 2022-Mar-09 at 17:54

Before the comparison of

Source https://stackoverflow.com/questions/71413435

QUESTION

How to calculate when one's 10000 day after his or her birthday will be?

Asked 2022-Mar-08 at 02:48

I am wondering how to solve this problem with basic Python (no libraries to be used): How to calculate when one's 10000 day after their birthday will be (/would be). For instance, given Monday 19/05/2008 the desired day is Friday 05/10/2035 (according to https://www.durrans.com/projects/calc/10000/index.html?dob=19%2F5%2F2008&e=mc2)

What I have done so far is the following script:

...

ANSWER

Answered 2022-Mar-06 at 18:02

Using base python packages only

On the basis that "no special packages" means you can only use base python packages, you can use datetime.timedelta for this type of problem:

Source https://stackoverflow.com/questions/71371909

QUESTION

Why MOV instruction is replaced by ADD instruction

Asked 2022-Mar-06 at 23:49

I have the following instruction: mov r1, r7 in my assembly code but after looking into disassembly, I've found that actual generated code was adds r1, r7, #0

I checked with ARMv6-M Architecture Reference Manual and I found out that there's MOVS , instruction (A6.7.40) which is different from ADDS.

While that's not a big issue, I'm still puzzled why assembler replaces code that I wrote by different op-codes. According to the book that I'm reading, all non-jump instructions take 1 cycle (and I'd prefer for assembler to be dumb rather than trying to optimize something for me).

I'm using Raspberry Pi Pico SDK which uses GNU Assembler, AFAIK.

All my code is written in helloworld.S, full source code is:

...

ANSWER

Answered 2022-Mar-06 at 21:36

Can I suggest that you add:

Source https://stackoverflow.com/questions/71374202

QUESTION

Count nodes within k distance of marked nodes in grid

Asked 2022-Feb-25 at 09:45

I am attempting to solve a coding challenge however my solution is not very performant, I'm looking for advice or suggestions on how I can improve my algorithm.

The puzzle is as follows:

You are given a grid of cells that represents an orchard, each cell can be either an empty spot (0) or a fruit tree (1). A farmer wishes to know how many empty spots there are within the orchard that are within k distance from all fruit trees.

Distance is counted using taxicab geometry, for example:

...

ANSWER

Answered 2021-Sep-07 at 01:11

This wouldn't be easy to implement but could be sublinear for many cases, and at most linear. Consider representing the perimeter of each tree as four corners (they mark a square rotated 45 degrees). For each tree compute it's perimeter intersection with the current intersection. The difficulty comes with managing the corners of the intersection, which could include more than one point because of the diagonal alignments. Run inside the final intersection to count how many empty spots are within it.

Source https://stackoverflow.com/questions/69075779

QUESTION

Lenses, the State monad, and Maps with known keys

Asked 2022-Feb-11 at 18:14

here is a puzzle that I keep on bumping into and that, I believe, no previous SO question has been addressing: How can I best use the lens library to set or get values within a State monad managing a nested data structure that involves Maps when I know for a fact that certain keys are present in the maps involved?

Here is the puzzle ...

ANSWER

Answered 2022-Feb-09 at 11:43

If you are sure that the key is present then you can use fromJust to turn the Maybe User into a User:

Source https://stackoverflow.com/questions/71046129

QUESTION

What is the correct way to install Android Studio Bumblebee 2021.1.1 Patch 1

Asked 2022-Feb-10 at 11:10

I am sorry but I am really confused and leery now, so I am resorting to SO to get some clarity.

I am running Android Studio Bumblebee and saw a notification about a major new release wit the following text:

...

ANSWER

Answered 2022-Feb-10 at 11:10

This issue was fixed by Google (10 February 2022).

You can now update Android Studio normally.

Source https://stackoverflow.com/questions/70999801

QUESTION

Overloading operator () instead of [] for indexing

Asked 2022-Feb-07 at 11:10

An old code base I'm refactoring has a rather unorthodox way to access n dimensional vectors by overloading the () operator instead of the [] operator.

To illustrate, suppose Vec is a class that overloads both operators for indexing purpose of an internal list of doubles.

...

ANSWER

Answered 2022-Feb-04 at 15:52

One "problem" with [] is when you have multiple dimensions. With an array you can do arr[val1][val2], and arr[val1] will give you an array you can index with [val2]. With a class type this isn't as simple. There is no [][] operator so the [val1] needs to return an object that [val2] can be applied to. This means you need to create another type and provide all the functionality you want. With (), you can do data(val1, val2) and no intermediate object is needed.

Source https://stackoverflow.com/questions/70989133

QUESTION

Why can't we use compile-time 'variables' in consteval functions as template parameters?

Asked 2022-Jan-29 at 14:32

I was testing this code (https://godbolt.org/z/fe6hhbeqW)...

...

ANSWER

Answered 2022-Jan-29 at 13:14

It doesn't matter that i is guaranteed to be evaluated only at compile-time when its value is known in an abstract sense.

It also doesn't matter whether the function is consteval or constexpr or none of these.

The language is still statically typed and nth_type_t; must in any given instantiation of the function refer to exactly one type. If i can change in the for loop, that is not possible to guarantee.

The language requires that the expression i when used as template argument is by itself a constant expression, independently of whether the whole function body can only be evaluated as part of a larger constant expression. But i is neither declared constexpr, nor declared const with constant initializer.

Source https://stackoverflow.com/questions/70905720

QUESTION

filtering a stream changes its wildcard bounds?

Asked 2022-Jan-07 at 12:58

the below method compiles without problems:

...

ANSWER

Answered 2021-Dec-21 at 14:14

Compatibility with the return type Stream> in the first case is not obtained by virtue of numbers.map(Optional::of) returning a Stream> on its own; it's the compiler inferring the return type of numbers.map(...) due to it being a generic method:

Source https://stackoverflow.com/questions/70433519

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Puzzle

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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