piper | JavaScript pipe-maneuvering game inspired by Pipe Dream | Game Engine library

Just create a new empty str variable and concatenate it.

1. use zip with the same string shifted by 1 to get pairs of current and the next character
2. use collections.Counter to get counts. It could also simplify your code to a single line.

You subset the empty dataframe. If the dataframe with headers is called df to create 18000 rows with NA values you can do -

You could use a search object, for example { patientName: 'John', technician: 'Jasmin' } and supply it to a findResults function.

We'd use Array.filter and Array.every to ensure all search criteria are met.

If you want results to show for any search criteron, you could use Array.some instead of Array.every.

Something like:

The MTL loads the texture as a TIFF image which can't be used as an image data source. Use JPG or PNG instead.

Sidenote: You will notice that the object's material has a texture assigned to the map property but with an undefined image value. In such a case, the texture appears black.

You need to join to the Employee_T table twice, once to fetch the doctor's name, and once to fetch the receptionist's name:

You have defined var2 as a tuple rather than str. To see this for yourself, print the type of var2: print(type(var2)), you'll see that it is a tuple.

Python allows tuples to be defined three ways:

1. tuple(sequence)
2. (a, b, c)
3. a, b, c

I avoid using the third syntax because it's very easy to edit unintentionally.

You need to replace the ,s in var2's declaration with +s in order to perform concatenation:

It happens because there are many nested row inside another row. So bootstrap divides nested row to 12 columns.

What we want is to create just four columns and then put content there:

The Flow pups is producing updated values as you can see in my logcat

Not exactly.

The Flow is emitting the same List of the same Puppy objects. I believe that Compose sees that the List is the same List object as before and assumes that there are no changes.

My suggested changes:

• Make Puppy be an immutable data class (i.e., no var properties)

• Get rid of changeFlow and have getPuppies() return a stable MutableStateFlow> (or make that just be a public property)

• In toggleAdoption(), create a fresh list of Puppy objects and use that to update the MutableStateFlow>: