coke | full stack MVC framework that speeds up your web development | Model View Controller library
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kandi X-RAY | coke Summary
A full stack MVC framework that speeds up your web development.
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QUESTION
I have a json file:
...ANSWER
Answered 2021-Jun-06 at 20:06for each data in the array (map) you want the ingredient part (.ingredients), extract the keys (Object.keys) and flatten the array (.flat())
QUESTION
How to split a list into sublist based on element types?
In short, given:
...ANSWER
Answered 2021-Jun-02 at 16:40drinks.foldRight(List.empty[List[Drink]]){
case (c:Coke.type, ((hd:Coke.type)::tl)::acc) => (c::hd::tl)::acc
case (p:Pepsi.type,((hd:Pepsi.type)::tl)::acc) => (p::hd::tl)::acc
case (d, acc) => List(d)::acc
}
QUESTION
Let's say I have a class with a method calculatePrice
that returns a value. It also has another method which uses calculatePrice
:
ANSWER
Answered 2021-Jun-01 at 19:37With the get syntax, the result of
this.price
is attached to the instance.
No it isn't. The getter just makes it look like the value is a property, but it isn't really. Every time you read this.price
it calls the getter function and returns the value, just like the calculatePrice()
method. The value is not attached anywhere.
So if the caller doesn't save the price anywhere, it will become garbage.
QUESTION
i've tried a lot to find a way to split a string into an array and i found that regex can help me. What is most near the result i need is this regex: \d+^[ a-zA-Z]
, but it is incomplete.
My string is something like that:
...ANSWER
Answered 2021-Jun-01 at 12:24You can use preg_split
:
QUESTION
In My project, to customize the buttons, I added image to it...All other buttons are working well with the images, but when i am trying to add image in another screen that is Toplevel of root, the images on the buttons are not visible and not even clickable, here is the code:
...ANSWER
Answered 2021-May-31 at 06:40What you can do is use another library called PIL
.
For example:
QUESTION
For example, my txt file looks like this:
...ANSWER
Answered 2021-May-25 at 23:06You can use the str.split()
method:
QUESTION
I am trying to make a form to register the number of drinks that are taken from the fridge by a certain person.
Currently I have three drinks in my db, meaning that I create 3 select tags and 3 input fields for the number of drinks per drink (e.g. coke, coke zero or coke light). In the code (somewhere earlier), $aantalDrink is set to 3.
This page is entered from selecting a person and a drink (the person is registered in $_POST['teacherId'] and the following JS arrays are defined: arr_drinks (all drink names) arr_drinkIds (corresponding drink Ids) arr_initSelectedDrinkId (the id of the initially selected drink).
I want a user to be able to select multiple types of drinks in case he gets multiple drinks for the whole group.
The front end works perfectly. However, when I submit my form, the select (i.e. the chosen drink) is not passed through to the 'submitted.php' page. The number of drinks, the hidden variable and submit are posted correctly however.
Note, in "submitted.php" I display all values of $_POST, with: foreach ($_POST as $key => $value) { }.
I am clueless...
HTML [EDIT: HTML instead of PHP creating HTML];
...ANSWER
Answered 2021-May-23 at 13:19You are seeing this behaviour because you have made option disabled and disabled value do not get submitted to server . i.e :
QUESTION
Hi i have had trouble trying to make this menu chat bot kind of thing into a gui, i have mismatched a bit of code and i can print the total cost of all items once clicked 'Finish Order' in line 108
All Code:
...ANSWER
Answered 2021-May-20 at 03:20I can't really explain it so here's an example:
QUESTION
The HTML create two drop-down menu and one delete button. One JavaScript, I made a code to fill those drop-down box with arrays. And, every time I change the item on the first drop-down menu, a new set of options appears on the second drop-down menu. The goal is, whenever I clicked the delete button, I should be able to delete an item on the second drop-down and when I changed the item on the first drop-down menu, hence another set of option will appear on the second drop-down menu, I should be able to delete an item from there as well.
The problem is, once the set of items on the second drop-down menu has been changed, a bunch of unwanted results occurs, such as deleting more than one items or deleting on another set of items. For example, if I delete something from "meal", it'll delete one item. Then if I go over to "dessert" and delete something from there, it'll delete one item. But if I go back to "meal" again, a bunch of items are now deleted. Just try it out yourself to see what I mean
...ANSWER
Answered 2021-May-19 at 13:28What were you doing wrong?
In practice your code stored in the variable menuOption
the first menu, doing so every time you tried to delete something it was removed from the first menu
Solution
- Call up the menu variable as often as needed
- Store index before remove it
- Extra:
- Use
menuList.selectedIndex
instead ofdrinkListArr.indexOf(subMenuOption)
- Use
menuType.value
instead ofmenuType.options[menuType.selectedIndex].text
- Use
QUESTION
Consider a BQ table with the following schema
...ANSWER
Answered 2021-May-17 at 18:13For the described data model, you would just use:
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