BlackJack | Javascript BlackJack game | Game Engine library

 by   scottux JavaScript Version: Current License: No License

kandi X-RAY | BlackJack Summary

kandi X-RAY | BlackJack Summary

BlackJack is a JavaScript library typically used in Gaming, Game Engine, jQuery applications. BlackJack has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Javascript (some jQuery) BlackJack game. Started in this fiddle:
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            kandi-support Support

              BlackJack has a low active ecosystem.
              It has 4 star(s) with 5 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              BlackJack has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of BlackJack is current.

            kandi-Quality Quality

              BlackJack has no bugs reported.

            kandi-Security Security

              BlackJack has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              BlackJack does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              BlackJack releases are not available. You will need to build from source code and install.

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            BlackJack Key Features

            No Key Features are available at this moment for BlackJack.

            BlackJack Examples and Code Snippets

            Returns a list of blackjack coefficients .
            javadot img1Lines of Code : 9dot img1no licencesLicense : No License
            copy iconCopy
            public ArrayList getBlackJacks() {
            		ArrayList winners = new ArrayList();
            		for (int i = 0; i < hands.length; i++) {
            			if (hands[i].isBlackJack()) {
            				winners.add(i);
            			}
            		}
            		return winners;
            	}  

            Community Discussions

            QUESTION

            How can I make an "Unless condition" in an IF statement c++
            Asked 2021-Jun-14 at 13:53

            I'm making blackjack in C++ and I'm nearing the end! I'm making my winning and loss statements. But my issue is that I need my if statements to determine not only whether or not the dealer's/players hand is greater or less than one another it needs to check if either has gone over 21.

            So having the if statements determine that isn't the problem I just need it to not go through one if statement if the other is over 21

            ...

            ANSWER

            Answered 2021-Jun-14 at 13:53

            In Blackjack, if both the player and the dealer get more than 21 (which is called "busting"), then the player loses and the dealer wins. Therefore, you must design the logic accordingly:

            Source https://stackoverflow.com/questions/67963794

            QUESTION

            C++ Blackjack code only going to first if statement
            Asked 2021-Jun-12 at 16:56

            I'm trying to code a blackjack game and everything is going smoothly so far but for this bit. No matter what I input into hitStand it always goes to the first if statement and "hits". I would like for if "h" is inputted it "Hits" and if "s" is inputted it "Stands" and, if there is an invalid input, it will tell the user to try again.

            I'm still fairly new to C++, so some help would be appreciated.

            ...

            ANSWER

            Answered 2021-Jun-12 at 16:51

            That is because your condition in if statement is always true. Since "h" is in or (||).

            Instead use:

            Source https://stackoverflow.com/questions/67950930

            QUESTION

            How to make a conditional button that changes the screen view?
            Asked 2021-May-27 at 20:47

            I am new to Swift, but I am trying to make a simple blackjack game. I have a HIT button that adds a card to the player's hand and increases the player's total score each time. But I also want to add a condition to the HIT button that if the player's total is over 21 a new screen appears with the text "You lose". However, I cannot get the button to open another view.

            I at first thought to change the HIT button to a NavigationView but then I couldn't figure out where to add the ifBust condition, so I thought it would better solution to make a new .swift file and call the file name in the if statement, that does not seem to work either.

            I have a isBust function that returns true if the player's score is over 21:

            ...

            ANSWER

            Answered 2021-May-27 at 20:47

            I think I figured out the answer to my own question. First I need to add a selection variable with nil (also meaning null?) as its value within the file.

            Source https://stackoverflow.com/questions/67728962

            QUESTION

            Close PyWebView Window with HTML Button click
            Asked 2021-May-20 at 08:57

            Info in advance:
            There is a similar question dealing with the same issue.
            However, this one doesn't work for me (or I just don't know enough to include it properly).
            I have only recently started working with pywebview.

            The goal:
            I want to close the window / end the programme with a link (or button) in HTML.

            The problem:
            The code used does not work for me.
            The function can be reached (the print statement fills up the console,
            unfortunately I have no idea why), but the window is not closed.
            I am just starting with pywebview, so I don't really know what to do.


            Used pages for problem solving:
            PyWebView Website
            StackOverflow Question


            The Code (Python & HTML):

            ...

            ANSWER

            Answered 2021-May-20 at 08:57

            In the meantime I have found a solution that closes the window and exits the program.
            However, I get an error, unfortunately I do not know why.

            The HTML / JS code is correct so far and needs no adjustment.

            In the Python script, only def destroy(self) must be specified instead of def destroy(window).


            Pretty simple actually, but still took me almost a month to solve.

            Source https://stackoverflow.com/questions/67208598

            QUESTION

            Is there a way to create variables with iteration?
            Asked 2021-May-10 at 21:55

            So Im trying to write code for an online blackjack program and I am having trouble with programming hitting, as I need to calculate using up to 11 variables that are drawn from a list randomly. Right now, my code for that section is:

            ...

            ANSWER

            Answered 2021-May-10 at 21:10

            I believe you want to use the iterator in the naming of a key within a dictionary? how's this look?

            Source https://stackoverflow.com/questions/67477605

            QUESTION

            showResult function in blackjack not working
            Asked 2021-May-08 at 03:04

            My show result function for blackjack isn't working properly despite passing the correct argument in it which computes the winner of the game. I nested the function in the function for the deal button to test if it was working.

            As you can see in this screenshot, when I console log the computeWinner function it works perfectly but it won't show up on the screen.

            The specific computeWinner function:

            ...

            ANSWER

            Answered 2021-May-08 at 03:04

            Just eyeballing the code here but you seem to be not returning anything from your computeWinner(). I added a return like so: return winner;. See if this is your expected output.

            Source https://stackoverflow.com/questions/67443602

            QUESTION

            Why does my basic print statement work, but my f-string version produces a syntax error?
            Asked 2021-May-06 at 12:11

            Very early stages of learning Python, and trying to complete 100 days of code challenge. Am building a crude blackjack game, but am stuck on what I am sure is probably a very simple fix that I don't recognise!

            This is my code so far:

            ...

            ANSWER

            Answered 2021-May-06 at 12:11

            You should check that you are using at least Python 3.6, which f-strings were introduced in, but also...

            You are using double quotes to access the dictionary, which is conflicting with using double quotes for the string. Try changing to either

            Source https://stackoverflow.com/questions/67417803

            QUESTION

            Issue with getting random number from Array in C
            Asked 2021-May-05 at 02:55

            I have some code for choosing two casino games. I'm having an issue with the first game choice, blackjack (it's just a very simple version). I have an array of card numbers. I randomly generate an index number and set the player or dealer's card as the number the index number represents.

            I have an option to choose a third card. If the player says yes, a third card is randomly generated for both the player and the dealer (to keep things even). At first, the third card would only equal zero, no matter what I did.

            I now have a number generating for card three, except, the third card number is always way too large and is not any of the numbers in the array. Even when I select no, the third number becomes the weird, overly large value. I've tried changing things around, working on the if statement, and other methods but so far nothing works.

            also I apologize for the mess of code, I don't intend to really change it unless it causes an issue/error.

            Code

            ...

            ANSWER

            Answered 2021-May-05 at 02:55

            if(third == 'y' && third == 'Y')

            This is always false because third cannot simultaneously equal 'y' and 'Y'. I think you meant || instead of &&. You have several other bugs like this, e.g. if(pCard1 == 1 && pCard1 == 11).

            Source https://stackoverflow.com/questions/67394390

            QUESTION

            Black Jack game multiple round system
            Asked 2021-Apr-25 at 21:55

            So me and my friend are making a blackjack game and I have trouble with making the game multiple rounds long, so after the round has ended the next round starts. I don't know how to do it. This is my code:

            ...

            ANSWER

            Answered 2021-Apr-25 at 21:55

            You basically want to wrap your existing code for a hand with a while loop that asks if the play would like to continue playing. Using your code as a starting point you might do:

            Source https://stackoverflow.com/questions/67257584

            QUESTION

            Creating a multi-player card game in Ruby on Rails
            Asked 2021-Apr-15 at 19:59

            I'm currently working on creating a Blackjack game using Ruby on Rails (Ruby version 2.7.2, Rails version 6.1.3) for a class. My teammates and I are hoping to soon convert the game from the current single-player mode (1 player vs an automated dealer) to multi-player. I haven't used Ruby on Rails before this class, and have very limited knowledge on supporting multi-player. I've found some posts on stack overflow from years ago in which WebSockets are commonly recommended as a solution, and Action Cable was specifically recommended.

            Given that the majority of information that I've found on this topic is older and possibly out-dated, I was hoping to know if WebSockets are still the best solution for multi-player capabilities, and if so, is Action Cable the best available option for beginners?

            ...

            ANSWER

            Answered 2021-Apr-15 at 19:59

            We wouldn't normally accept questions that ask for a general opinion - as you get a lot of conflicting opinions!

            I would encourage you to take a look at Hotwire which is recently released from the guys at Basecamp and works very nicely with Rails.

            In essence, you need functionality that will update the state of the various objects without needing a full page reload/refresh e.g. if player A doubles down, all other players should see that reflected on their screen without reloading. Hotwire and the associated Stimulus and Turbo libraries enables this.

            Source https://stackoverflow.com/questions/67038934

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

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            No vulnerabilities reported

            Install BlackJack

            You can download it from GitHub.

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