BlackJack | Javascript BlackJack game | Game Engine library
kandi X-RAY | BlackJack Summary
kandi X-RAY | BlackJack Summary
Javascript (some jQuery) BlackJack game. Started in this fiddle:
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of BlackJack
BlackJack Key Features
BlackJack Examples and Code Snippets
public ArrayList getBlackJacks() {
ArrayList winners = new ArrayList();
for (int i = 0; i < hands.length; i++) {
if (hands[i].isBlackJack()) {
winners.add(i);
}
}
return winners;
}
Community Discussions
Trending Discussions on BlackJack
QUESTION
I'm making blackjack in C++ and I'm nearing the end! I'm making my winning and loss statements. But my issue is that I need my if statements to determine not only whether or not the dealer's/players hand is greater or less than one another it needs to check if either has gone over 21.
So having the if statements determine that isn't the problem I just need it to not go through one if statement if the other is over 21
...ANSWER
Answered 2021-Jun-14 at 13:53In Blackjack, if both the player and the dealer get more than 21 (which is called "busting"), then the player loses and the dealer wins. Therefore, you must design the logic accordingly:
QUESTION
I'm trying to code a blackjack game and everything is going smoothly so far but for this bit. No matter what I input into hitStand
it always goes to the first if statement and "hits". I would like for if "h" is inputted it "Hits" and if "s" is inputted it "Stands" and, if there is an invalid input, it will tell the user to try again.
I'm still fairly new to C++, so some help would be appreciated.
...ANSWER
Answered 2021-Jun-12 at 16:51That is because your condition in if statement is always true. Since "h" is in or (||).
Instead use:
QUESTION
I am new to Swift, but I am trying to make a simple blackjack game. I have a HIT button that adds a card to the player's hand and increases the player's total score each time. But I also want to add a condition to the HIT button that if the player's total is over 21 a new screen appears with the text "You lose". However, I cannot get the button to open another view.
I at first thought to change the HIT button to a NavigationView but then I couldn't figure out where to add the ifBust condition, so I thought it would better solution to make a new .swift file and call the file name in the if statement, that does not seem to work either.
I have a isBust function that returns true if the player's score is over 21:
...ANSWER
Answered 2021-May-27 at 20:47I think I figured out the answer to my own question. First I need to add a selection variable with nil (also meaning null?) as its value within the file.
QUESTION
Info in advance:
There is a similar question dealing with the same issue.
However, this one doesn't work for me (or I just don't know enough to include it properly).
I have only recently started working with pywebview.
The goal:
I want to close the window / end the programme with a link (or button) in HTML
.
The problem:
The code used does not work for me.
The function can be reached (the print statement fills up the console,
unfortunately I have no idea why), but the window is not closed.
I am just starting with pywebview
, so I don't really know what to do.
Used pages for problem solving:
PyWebView Website
StackOverflow Question
The Code (Python & HTML):
...ANSWER
Answered 2021-May-20 at 08:57In the meantime I have found a solution that closes the window and exits the program.
However, I get an error, unfortunately I do not know why.
The HTML / JS code is correct so far and needs no adjustment.
In the Python script, only def destroy(self)
must be specified instead of def destroy(window)
.
Pretty simple actually, but still took me almost a month to solve.
QUESTION
So Im trying to write code for an online blackjack program and I am having trouble with programming hitting, as I need to calculate using up to 11 variables that are drawn from a list randomly. Right now, my code for that section is:
...ANSWER
Answered 2021-May-10 at 21:10I believe you want to use the iterator in the naming of a key within a dictionary? how's this look?
QUESTION
My show result function for blackjack isn't working properly despite passing the correct argument in it which computes the winner of the game. I nested the function in the function for the deal button to test if it was working.
The specific computeWinner function:
...ANSWER
Answered 2021-May-08 at 03:04Just eyeballing the code here but you seem to be not returning anything from your computeWinner()
. I added a return like so: return winner;
. See if this is your expected output.
QUESTION
Very early stages of learning Python, and trying to complete 100 days of code challenge. Am building a crude blackjack game, but am stuck on what I am sure is probably a very simple fix that I don't recognise!
This is my code so far:
...ANSWER
Answered 2021-May-06 at 12:11You should check that you are using at least Python 3.6, which f-strings were introduced in, but also...
You are using double quotes to access the dictionary, which is conflicting with using double quotes for the string. Try changing to either
QUESTION
I have some code for choosing two casino games. I'm having an issue with the first game choice, blackjack (it's just a very simple version). I have an array of card numbers. I randomly generate an index number and set the player or dealer's card as the number the index number represents.
I have an option to choose a third card. If the player says yes, a third card is randomly generated for both the player and the dealer (to keep things even). At first, the third card would only equal zero, no matter what I did.
I now have a number generating for card three, except, the third card number is always way too large and is not any of the numbers in the array. Even when I select no, the third number becomes the weird, overly large value. I've tried changing things around, working on the if statement, and other methods but so far nothing works.
also I apologize for the mess of code, I don't intend to really change it unless it causes an issue/error.
Code
...ANSWER
Answered 2021-May-05 at 02:55if(third == 'y' && third == 'Y')
This is always false because third
cannot simultaneously equal 'y'
and 'Y'
. I think you meant ||
instead of &&
. You have several other bugs like this, e.g. if(pCard1 == 1 && pCard1 == 11)
.
QUESTION
So me and my friend are making a blackjack game and I have trouble with making the game multiple rounds long, so after the round has ended the next round starts. I don't know how to do it. This is my code:
...ANSWER
Answered 2021-Apr-25 at 21:55You basically want to wrap your existing code for a hand with a while
loop that asks if the play would like to continue playing. Using your code as a starting point you might do:
QUESTION
I'm currently working on creating a Blackjack game using Ruby on Rails (Ruby version 2.7.2, Rails version 6.1.3) for a class. My teammates and I are hoping to soon convert the game from the current single-player mode (1 player vs an automated dealer) to multi-player. I haven't used Ruby on Rails before this class, and have very limited knowledge on supporting multi-player. I've found some posts on stack overflow from years ago in which WebSockets are commonly recommended as a solution, and Action Cable was specifically recommended.
Given that the majority of information that I've found on this topic is older and possibly out-dated, I was hoping to know if WebSockets are still the best solution for multi-player capabilities, and if so, is Action Cable the best available option for beginners?
...ANSWER
Answered 2021-Apr-15 at 19:59We wouldn't normally accept questions that ask for a general opinion - as you get a lot of conflicting opinions!
I would encourage you to take a look at Hotwire which is recently released from the guys at Basecamp and works very nicely with Rails.
In essence, you need functionality that will update the state of the various objects without needing a full page reload/refresh e.g. if player A doubles down, all other players should see that reflected on their screen without reloading. Hotwire and the associated Stimulus and Turbo libraries enables this.
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