Dads | *BA DUM TSSS* - | Model View Controller library

You can manage Time-driven triggers manually, e.g. run a particular function everyHour(). See here

As a heap data structure is a tree with specific properties (specifically, it is a rooted, complete, binary tree, whose values obey the heap property), the definition of the height of a heap is the same as the definition of the height of a rooted tree.

Wikipedia defines it as follows:

The height of a node is the length of the longest downward path to a leaf from that node. The height of the root is the height of the tree. [...] a tree with only a single node (hence both a root and leaf) has depth and height zero. Conventionally, an empty tree (tree with no nodes, if such are allowed) has height −1.

With this definition the height of a tree is one less than the number of levels in a tree.

Almost always this is the definition used. But in rare cases you'll find a definition where the height is the number of levels. For instance here. But this is a less popular definition.

Here is an argument in defence of the more popular definition:

Imagine the tree to be a pieced together set of ropes, each piece of rope having the same size (e.g. 10cm), and the places where the ends are tied together, are the vertices. Now pick up the "root" and hold it high up in the air. The ropes all hang vertically, all forming one vertical column. Now measure the distance from the root to the lowest point of this hanging structure: that is physically what we would call the height of that structure. It is the sum of lengths of the little connected ropes that form the longest path. This corresponds with the popular definition (as on Wikipedia) of a tree's height. It depends on the number of edges of the longest path, not on the number of nodes on that path.

As to your other question: yes, if a parent should sift down the heap, and both children have the same value, then it is safe to swap it by either.

The problem that you have is that each of the struct A through D all are composited in memory. Honestly, the real problem here is, how on earth do you come up with that pointer you are feeding to superfoo to begin with? If it came from one of your objects, then can you not tag it as such.

That's really a design problem. In general, C++ simply isn't designed to determine if an object is in a particular graph, but if you must, then:

To do this correctly, you would need to define something like so:

(Warning, this is off the top of my head)

A few things. I don't know exactly what you are doing, but you have to know that Javascript is an asynchronous programming language. That means that stuff doesn't happen in order. If a function takes time, Javascript will go onto the next function. It won't wait for the first function to finish to then go to the second function. This makes Javascript very efficient but adds a little more difficulties to the user. There are a few ways to go around this. I have linked articles to three methods.

Callbacks: https://www.w3schools.com/js/js_callback.asp

Promises: https://www.w3schools.com/js/js_promise.asp

Async/Await: https://www.w3schools.com/js/js_async.asp

You can choose whichever you like depending on your circumstances. Also there is something wrong with your code on the last line. Lockr.set('timeStamp', timeStamp()); You are passing in the timestamp function. When you do this remove the () from the timestamp. Anyways, I hope this helped.

If you need a long-lived connection between client and server you could look into using WebSockets through something like Pusher, which has a .NET lib available: https://github.com/pusher/pusher-http-dotnet

Alternatively you could use long-polling, although that is much less efficient because you're intermittently querying the server for updates. You'd basically setup an Interval observable to make a request every N seconds to check for updates on the server.

It seems your regex is removing the email address from the from property, rather than preserving it. Here's a sample with a different regex that pulls out the email during comparison and ignores the rest.

So, if I understand what you are trying to accomplish correctly, it looks like you are trying to overwrite a list in a JSON file with a new list created from user input. For easiest data manipulation, set up your JSON file in dictionary form:

I'd suggest to change spider architecture since scrapy isn't supposed to chain spiders(it's possible of course but it's bad practice in general), it's supposed to chain requests within the same spider.

Your problem is caused by the fact that scrapy disigned to grab flat list of items, while you need nested one like book = {'title': ..., 'chapters': [{some chapter data}, ...]}

I'd suggest next architecture for your spider:

I’ve changed from grid to inline-block to make this still display horizontally. But I think the below worked for me... Width: max-content;