chester | A MVC framework for Titanium Developer | Model View Controller library

by twilson63 Ruby Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | chester Summary

chester is a Ruby library typically used in Architecture, Model View Controller applications. chester has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A MVC framework for Titanium Developer. The purpose of this framework is to organize your Titanium Developer projects in a Model-View-Controller (MVC) pattern.

Support

Quality

Security

License

Reuse

Support

chester has a low active ecosystem.

It has 25 star(s) with 2 fork(s). There are 6 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 3 have been closed. On average issues are closed in 0 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of chester is current.

Quality

chester has 0 bugs and 0 code smells.

Security

chester has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

chester code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

chester is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

chester releases are not available. You will need to build from source code and install.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed chester and discovered the below as its top functions. This is intended to give you an instant insight into chester implemented functionality, and help decide if they suit your requirements.

Renders the current page
Returns the file for a specific file
Renders the current page .
Create a folder
display the current page
Returns the current user s home directory

Get all kandi verified functions for this library.

chester Key Features

No Key Features are available at this moment for chester.

chester Examples and Code Snippets

No Code Snippets are available at this moment for chester.

Community Discussions

Trending Discussions on chester

Is there an R function to help turn State abbreviations into full names? Or Vice Versa?

Why does python print memory location rather than class.name in some cases but not others in my code?

Fandom-py: Unable to get image by using page.images[0]

R Shiny: How to change title of plot based on number of inputs selected in selectizeInput

Cannot read property 'startLine' of undefined : conversion from Pine Script vs4 to vs5

Receiving PHP contact form error (Please complete the form and try again. )

ValueError: All arrays must be of the same length append data in data frame

How to unnest multiple columns while including nulls

Why is array.map nested within array.forEach so much faster (in this case) than the other way around?

How to I get the innerHTML of the closest H3 from the clicked element?

QUESTION

Is there an R function to help turn State abbreviations into full names? Or Vice Versa?

Asked 2022-Apr-18 at 03:52

I have two large-ish data frames I am trying to append...

In df1, I have state codes, county codes, state names (Alabama, Alaska, etc.), county names, and years from 2010:2020.

In df2, I have county names, state abbreviations (AL, AK), and data for the year 2010 (which I am trying to merge into df1. The issue lies in that without specifying the state name and simply merging df1 and df2, some of the data which I am trying to get into df1 is duplicated due to there being some counties with the same name...hence, I am trying to also join by state to prevent this, but I have state abbreviations, and state names.

Is there any way in which I can make either the state names in df1 abbreviations, or the state names in df2 full names? Please let me know! Thank you for the help.

Edit: dput(df2)

...

ANSWER

Answered 2022-Apr-18 at 03:52

Here's one way you could turn state abbreviations into state names using R's built in state vectors:

Source https://stackoverflow.com/questions/71907258

QUESTION

Why does python print memory location rather than class.name in some cases but not others in my code?

Asked 2022-Feb-11 at 14:18

My code has a mathematical function that iterates over a list of county class objects and returns the county with the max voter turnout along with that turnout in a tuple.

Code here:

...

ANSWER

Answered 2022-Feb-11 at 14:05

There is bug in your code. In first line, you are assigning whole County object to the max_county_variable

Source https://stackoverflow.com/questions/71081293

QUESTION

Fandom-py: Unable to get image by using page.images[0]

Asked 2022-Feb-01 at 09:46

I'm using fandom module in python for my discord bot. I get this error when I request data by using page.images[0]. It should be an image url. This is the page I want to get.

...

ANSWER

Answered 2022-Feb-01 at 09:46

I fixed it by using pymediawiki module.

This code that use mediawiki can replace fandom module by changing the api of wiki.

Source https://stackoverflow.com/questions/70863772

QUESTION

R Shiny: How to change title of plot based on number of inputs selected in selectizeInput

Asked 2021-Dec-08 at 15:49

I have an app that I'd like to be able to have the title change once there is more than 1 input selected in a selectizeInput. I know this is a simple thing but I can't seem to figure it out!

Sample of data:

...

ANSWER

Answered 2021-Dec-08 at 15:49

Made slight changes in sample data and code:

Source https://stackoverflow.com/questions/70263437

QUESTION

Cannot read property 'startLine' of undefined : conversion from Pine Script vs4 to vs5

Asked 2021-Dec-06 at 15:14

I am trying to convert the indicator below from Pine Script vs4 to vs5. The error message is the following: "Conversion failed, reason: line 324: Cannot read property 'startLine' of undefined". It seems that there is something wrong with the plot function.

Does anybody have an idea of how this error could be fixed?

Thank you

...

ANSWER

Answered 2021-Dec-06 at 15:14

Seems to be related to color=na. Replace it with color=color(na) (Pine has a built-in mass Find and Replace via Ctrl+F) and the script should convert correctly.

Source https://stackoverflow.com/questions/70247522

QUESTION

Receiving PHP contact form error (Please complete the form and try again. )

Asked 2021-Nov-11 at 22:37

I am creating a contact form with 5 fields which will email the input details to a set e-mail but when the form is submitted i,m receiving error! Please complete the form and try again. here is php code, js and htm form. Any help would be much appreciated.

html Form:

...

ANSWER

Answered 2021-Nov-11 at 22:35

Source https://stackoverflow.com/questions/69906502

QUESTION

ValueError: All arrays must be of the same length append data in data frame

Asked 2021-Oct-07 at 12:22

import requests
from bs4 import BeautifulSoup
import pandas as pd
headers ={
    'User-Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.114 Safari/537.36'
}
productlink=[]
n=[]
a=[]
re=[]
ra=[]
w=[]

r =requests.get('https://www.houzz.com/professionals/general-contractor')
soup=BeautifulSoup(r.content, 'html.parser')
tra = soup.find_all('div',class_='hz-pro-search-result__info')
for pro in tra:
    name=pro.find('span',class_='mlm header-5 text-unbold').text
    n.append(name)
    address=pro.find('span',class_='hz-pro-search-result__location-info__text').text
    a.append(address)
    reviews=pro.find('span',class_='hz-star-rate__review-string').text
    re.append(reviews)
    rating=pro.find('span',class_='hz-star-rate__rating-number').text
    ra.append(rating)
for links in tra:
    for link in links.find_all('a',href=True)[2:]:
            if link['href'].startswith('https://www.houzz.com/professionals/general-contractors'):
                productlink.append(link['href'])

for link in productlink:
    r =requests.get(link,headers=headers)
    soup=BeautifulSoup(r.content, 'html.parser')
    for web in soup.find_all('a',attrs={'class':'sc-62xgu6-0 jxCcwv mwxddt-0 bSdLOV hui-link trackMe'}):
        w.append(web['href'])
df = pd.DataFrame({'name':n,'address':a,'reviews':re,'rating':ra,'web':w})
print(df)

...

ANSWER

Answered 2021-Oct-07 at 12:22

Make it as simple as possible and do not store the information from different loops in these bunch of lists, try to store them in one dict:

possible solution

Source https://stackoverflow.com/questions/69480501

QUESTION

How to unnest multiple columns while including nulls

Asked 2021-Sep-24 at 20:47

I have a table that looks like:

id site_names site_addresses industries feis 30 Borden Incorporated 198 Saluda St , Chester , SC , 29706-1579 , United States|198 Saluda St, Chester, SC 29706, USA|198 Saluda St Chester SC 29706-1579 United States Food and Cosmetics 12345|45678 31 Butterkrust Bakeries, Inc.|Flowers Baking Co. of Lakeland, LLC|Southern Bakeries, Inc. dba Butterkrust Bakeries null Food|Food and Cosmetics 12345 33 Church & Dwight Canada Corp. 5485 RUE FERRIER , , MONTREAL, QUEBEC Quebec , , -- , CA null null

I want to split the table into a materialized view where each row is one of the combinations possible when you split site_names, site_addresses, industries, and feis up. So for example, a few rows from this data would be:

id site_name site_address industry fei 30 Borden Incorporated 198 Saluda St , Chester , SC Food and Cosmetics 12345 30 Borden Incorporated 198 Saluda St , Chester , SC Food and Cosmetics 45678 30 Borden Incorporated 198 Saluda St, Chester, SC 29706, USA Food and Cosmetics 12345 30 Borden Incorporated 198 Saluda St, Chester, SC 29706, USA Food and Cosmetics 45678 ... 31 Butterkrust Bakeries, Inc. null Food 12345 31 Flowers Baking Co. of Lakeland, LLC null Food 12345

I have tried several ways to accomplish this. The closest I got was with this code:

...

ANSWER

Answered 2021-Sep-24 at 20:47

If you want all combinations, you can use a single query:

Source https://stackoverflow.com/questions/69317331

QUESTION

Why is array.map nested within array.forEach so much faster (in this case) than the other way around?

Asked 2021-Aug-07 at 14:09

I have a page that gives the user the ability to filter store locations by clicking on links for Region and Individual Shops nested within those Regions. Every click updates an object containing which filters have been applied, hides all the elements and then shows only the filtered set of elements.

My code in this post takes the data from the filters object and creates a CSS selector string to which the jQuery .show() method can applied.

I tried doing it 2 different ways thinking there wouldn't be much of a difference in performance, but to my surprise, jsbench.me showed Solution #2 (below) to be ~90% slower, and I'm baffled as to why.

Here is the code that creates the CSS selector string for each solution. They both use the same object representing the current active filters. They can be found in this Codepen as well (variables are named slightly differently, but the code is the same as below).

Example Active Filters Object ...

ANSWER

Answered 2021-Aug-07 at 13:21

The difference between forEach and map won't really be significant, forEach will likely have a slight edge since it doesn't have to create a new array but that's just a guess. The reason why your code is slower in solution 2 with forEach is because 1. you're using a join which will execute an array join on every iteration (essentially creating a factorial loop) and also 2. you're using string concatenation which will be slower than interpolation, as the comment on your question have already mentioned. Solution 1 is just linear with a bit extra for adding new items to an array, which is negligible.

Source https://stackoverflow.com/questions/68692649

QUESTION

How to I get the innerHTML of the closest H3 from the clicked element?

Asked 2021-Jul-15 at 14:40


  Bob Chester
  Janitor
  
    Click Here For Bio

...

ANSWER

Answered 2021-Jul-15 at 14:40

Like this

closest is the keyword

Here I delegate from the nearest static container. Your container will be different, so change document.getElementById("container") to a relevant container

Source https://stackoverflow.com/questions/68395810

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install chester

You can download it from GitHub.
On a UNIX-like operating system, using your system’s package manager is easiest. However, the packaged Ruby version may not be the newest one. There is also an installer for Windows. Managers help you to switch between multiple Ruby versions on your system. Installers can be used to install a specific or multiple Ruby versions. Please refer ruby-lang.org for more information.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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