typescript-ddd-skeleton | 🔷✨ TypeScript DDD Skeleton : Bootstrap your new TypeScript | Architecture library

by CodelyTV TypeScript Version: Current License: No License

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kandi X-RAY | typescript-ddd-skeleton Summary

typescript-ddd-skeleton is a TypeScript library typically used in Architecture applications. typescript-ddd-skeleton has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

🔷✨ TypeScript DDD Skeleton: Bootstrap your new TypeScript applying following Hexagonal Architecture and Domain-Driven Design patterns

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typescript-ddd-skeleton has a low active ecosystem.

It has 360 star(s) with 47 fork(s). There are 15 watchers for this library.

It had no major release in the last 6 months.

There are 1 open issues and 2 have been closed. On average issues are closed in 14 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of typescript-ddd-skeleton is current.

Quality

typescript-ddd-skeleton has 0 bugs and 0 code smells.

Security

typescript-ddd-skeleton has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

typescript-ddd-skeleton code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

typescript-ddd-skeleton does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

typescript-ddd-skeleton releases are not available. You will need to build from source code and install.

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typescript-ddd-skeleton Key Features

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Community Discussions

Trending Discussions on typescript-ddd-skeleton

What that this line means in a make file `DOCKER := $(shell command -v docker)`

QUESTION

What that this line means in a make file `DOCKER := $(shell command -v docker)`

Asked 2020-Jul-03 at 22:45

$(shell command -v docker) What command means? it's being used in a Makefile.

I saw this in a github repository that I'm trying to understand.

It looks like it's setting a variable with a command to test if docker is installed, and stop the build if its not, the problem is this that I don't have a command installed and I tryed to install command in ubuntu but it can't find it, looking on internet how to install this commad command seems realy difficult because of its name, how to install command in linux/ubuntu didn't bring anything useful, also search for this being using on Makefiles trying to get some clue but nothing so far.

Running the build command seems to work becuse it build the image and yes I have docker installed, but still getting that message in the terminal make: command: Command not found

Any idea?

make build output (trucated):

...

ANSWER

Answered 2020-Jul-03 at 22:45

What it means is that the person who wrote this makefile wasn't careful enough to write it in a portable way.

The command command is part of the shell (which is why you won't see it if you look for it in the GNU make manual). Not only that, it's part of the bash shell specifically: it is not a POSIX sh standard command. The bash man page says:

Source https://stackoverflow.com/questions/62721593

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

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