Illuminant | Realtime 2D lighting and particle system | Augmented Reality library

 by   sq C# Version: Current License: No License

kandi X-RAY | Illuminant Summary

kandi X-RAY | Illuminant Summary

Illuminant is a C# library typically used in Virtual Reality, Augmented Reality, WebGL applications. Illuminant has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Realtime 2D lighting and particle system library. Depends on Squared.Render from
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              Illuminant has a low active ecosystem.
              It has 42 star(s) with 4 fork(s). There are 8 watchers for this library.
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              It had no major release in the last 6 months.
              Illuminant has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Illuminant is current.

            kandi-Quality Quality

              Illuminant has 0 bugs and 0 code smells.

            kandi-Security Security

              Illuminant has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Illuminant code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Illuminant does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              Illuminant releases are not available. You will need to build from source code and install.

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            Illuminant Key Features

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            Illuminant Examples and Code Snippets

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            Community Discussions

            QUESTION

            kwargs don't do anything
            Asked 2021-Apr-15 at 08:48

            Could you help me to understand why these keywords arguments do not do anything on the diagram plotting ? My code does not return any error but it does not take into account these arguments.

            ...

            ANSWER

            Answered 2021-Apr-15 at 08:48

            Assuming you are working with Colour, you are not supposed to use dict unpacking to pass plot_kwargs and annotate_kwargs.

            From the documentation:

            Source https://stackoverflow.com/questions/67105082

            QUESTION

            Do you need to divide with white point, for emissive sources, when converting from XYZ to CIELAB?
            Asked 2020-Jun-12 at 09:10

            When converting from XYZ (CIE 1931 color space) to L*a*b* (CIELAB) the formulas, that you'll find e.g. here https://en.wikipedia.org/wiki/CIELAB_color_space, specify you should divide by the XYZ values of the white point of the "reference illuminant" (of the lamp that illuminates the scene?).

            The formula

            My XYZ coordinate comes from an emissive source, so there's no illuminant of the scene. So I can understand this for when an illuminant is involved, because then the sum/integral for producing the XYZ values contains the illuminant. But I just can't find any other formulas than these ones, they all assume an illuminant.

            ...

            ANSWER

            Answered 2020-Jun-10 at 22:17

            The reference illuminant is not the lamp that illuminates the scene. The reference illuminant is basically just the definition of white. While "pure black" is an unambiguous color (no intensity), "pure white" is not. E.g. if you look at the chromaticity diagram, there are infinitely many points near the middle you could call "white." Therefore, you have to pick one to be "white", and then you can construct the CIELAB space around that. That is, CIELAB is not a completely defined color space until you define what "white" you want to use. Different choices of "white" will give you different CIELAB coordinates. (Of course, as long as you keep track of the white point, the color can still be unambiguously converted back to XYZ.)

            A very common definition of "white" is "Illuminant D65," or "statistically ideal European noontime sun," which has tristumulus coordinates (taken from the Wikipedia link) X = 95.047, Y = 100.00, Z = 108.883 for the standard 2º observer. Also according to Wikipedia, CIELAB is often implicitly understood to use Illuminant D50 as its white point. Turning the given xy coordinates back into XYZ coordinates (fixing Y = 100), I get X = 96.421, Y = 100, Z = 82.519. Pick either one, or even something else, to define your color space. If you're going to output a file or something with data in this color space, you should look into things like "embedded color profiles" for the relevant format, where you can store your choice of "white" for future programs to consume. If that's not possible, you should still document it somehow if it's going to be "user-facing."

            Source https://stackoverflow.com/questions/62312828

            QUESTION

            Parallelization of a reverse-lookup with OpenMP
            Asked 2020-May-15 at 17:55

            I'm trying to find the closest correlated color temperature to any arbitrary chromaticity. That is, for any (x, y) point in the following graph, I want the closest point that belong to the Planckian locus, and from that point, I want the correlated black body temperature :

            The parametric function of the black body curve is a polynomial :

            ...

            ANSWER

            Answered 2020-May-15 at 17:55

            Your current code has a nasty race condition in

            Source https://stackoverflow.com/questions/61821090

            QUESTION

            Color profile conversion - image not correct
            Asked 2020-May-14 at 12:07

            I have jpg image with embeded ICC profile. I have extracted ICC profile from the file and now I need to convert decompressed image to sRGB.

            My formulas are based on http://www.brucelindbloom.com/index.html?Math.html

            I use this algorithm:

            1. Convert image from RGB -> XYZ
            2. Do chromatic adaptation on XYZ
            3. Convert XYZ -> sRGB

            For the tasks, I have this code:

            ...

            ANSWER

            Answered 2020-May-14 at 12:07

            I have found the problem.

            I was using wrong reference white for chromatic adaptation. I was using value from wtpt, but Illuminant should be used instead as an input white.

            Output white is still set to D65.

            Source https://stackoverflow.com/questions/61778407

            QUESTION

            Inaccurate values when converting from RGB to L*ab colours
            Asked 2020-Mar-26 at 15:45

            I'm trying to convert sRGB values (in Photoshop) to L*ab values (also for use in Photoshop) I'm in the ballpark, but not getting the same results as EasyRGB which is where I got the conversion formulas from. I expect there's rounding errors (not at the end, where I round to three places). Only I can't see them.

            • Input: sRGB 255, 0, 255
            • Output:L*ab: 60.32 , 98.254, -60.843
            • Expected Output L*ab: 60.324 98.234 -60.825

            To make it easier I've lifted out any Photoshop code, so it's just JavaScript

            ...

            ANSWER

            Answered 2020-Mar-25 at 08:54

            Obviously the EasyRBG RGB to XYZ conversion is flawed. It doesn't obey it's own rules. Let's do this step by step:

            The input data is

            R: 255 G: 0 B: 255

            The first step is to map those to the zero to one range by dividing by 255. yielding this

            var_R: 1 var_G: 0 var_B: 1

            The next step is some manipulations, which seem to be some Gamut adjustments. But those manipulations have fix points at the extremes, meaning input values 1 or 0 don't change in this manipulation. So we are still at

            var_R: 1 var_G: 0 var_B: 1

            Next step is scale everything by 100

            var_R: 100 var_G: 0 var_B: 100

            Then there is a matrix multiplication of the vector (R,G,B) to (X,Y,Z) which is a weighted linear combination of RGB vector

            X = 42.24 + 18.05 = 60.29
            Y = 21.26 + 7.22 = 28.48
            Y = 1.93 + 95.05 = 96.98

            EasyRGB has some different result for this conversion from RGB to XYZ

            X: 59.289, Y: 28.485, Z: 96.964

            Source https://stackoverflow.com/questions/60844996

            QUESTION

            "TypeError" when importing colour-science module in python
            Asked 2020-Jan-25 at 08:30

            Sorry if it might be question that is easy to answer, but I'm new to python and can't find the answer anywhere.

            I'm trying to use the colour-science module and have installed it via pip (Windows 10 64bit with python 3.8.1). But as soon as I try to import the modul I get this error:

            ...

            ANSWER

            Answered 2020-Jan-25 at 08:30

            Those are known issues and should be fixed in a new package release soon.

            Edit: 0.3.15 is up on Pypi and should be soon on Conda.

            Source https://stackoverflow.com/questions/59767917

            QUESTION

            How do I convert SRM to L*a*b* using E-308 as an algorithm?
            Asked 2019-Nov-08 at 04:24

            I'm trying to wrap my head around how to apply ASTM E-308 to SRM measurements for beer. The problem domain in which I am working requires that we have a decent conversion from SRM to RGB (or sRGB) via conversion to Lab* first. It seems that every site I use to create a beer recipe has their own conversion from SRM to RGB, which makes sense, given that it's a sticky problem. That said, I'm looking to write an open source js library that will handle the problem.

            Basically, I'm using the algorithm as described here: https://www.homebrewtalk.com/forum/threads/on-the-calculation-of-srm-rgb-values-in-the-srgb-color-space.413581/#post-5232912

            Which I believe is a simplification of the E-308 algorithm. Where I'm having difficulty is that the spreadsheet mentioned in that post (http://wetnewf.org/pdfs/Brewing_articles/MOAWorkbook.xls) doesn't make a ton of sense to me. The post says to choose a XYZ vector based on the observer angle from the spreadsheet. If I choose a 10 degree observer angle, then I would expect that the XYZ vector should be: (82.82, 3.48, 61.86). Is this correct?

            Now, choosing an illuminant spectrum is also somewhat confusing. If I want illuminant C (which I believe to be 6774K), what values do I pull from that spreadsheet to add as components for the spectrum? Moreover, how do I calculate these components?

            I have some limited background in color theory, but what I'd really like is to be able to have some set of input criteria, say, observer angle and illuminant color temperature, along with the SRM value, and compute an Lab* value.

            ...

            ANSWER

            Answered 2019-Nov-08 at 04:24

            This is a question that does warrant an answer that is probably not suitable for Stack Overflow format.

            ASTM E308 by itself is a 50 pages complex standard whose main body is about conversion from spectral distribution to CIE XYZ tristimulus values. It also touches conversion to CIE Lab and CIE Luv.

            The spreadsheet you linked does not fully implement ASTM E308 and conveniently use the integration method for 5 nm measurement intervals without a table of tristimulus weighting factors which you technically need if the spectral data is bandpass corrected. It is fine for practical purposes but if precision is required it is important to know that ASTM E308 is very strict.

            The spreadsheet is quite complex because it seems to use the Augmented SRM computation with the eigen-vectors for the hundred or so of beers.

            Assuming that you want to use the ASBC method, the process should be as follows:

            • Compute the beer transmission spectral distribution for given SRM and path length using the following equation:

            • Convert the spectral distribution to CIE XYZ tristimulus values using the integration method for the CIE 1964 10 Degree Standard Observer and Illuminant C
            • Convert the CIE XYZ tristimulus values to CIE Lab
            • To go further, convert them also to sRGB
            • Drink beer :)

            If you don't mind reading Python, I made a Colab notebook that uses Colour and computes beer colour for a grid of SRM and path lengths:

            Source https://stackoverflow.com/questions/58722583

            QUESTION

            Iterate in dictionary for value that matches the first 5 numbers in a filename
            Asked 2019-Oct-20 at 18:30

            I am trying to rename some files based on information about them stored in a json dictionary. The filenames are currently like "00016_930831_fa.png". I have information about all of the files stored in a dictionary, including the 'facts' such as the name (which would be '00016_930831_fa_a') and 'personal facts' such as the gender (which would be 'male' or 'female').

            The json file looks like so, where it contains facts about a file:

            ...

            ANSWER

            Answered 2019-Oct-20 at 16:54

            I have updated your json input in your question, but what you want looks like this

            Source https://stackoverflow.com/questions/58473174

            QUESTION

            plt.legend() blocks matplotlib to display plot
            Asked 2019-Aug-20 at 16:34

            Without plt.legend() called, the plot gets displayed. With it, I just get:

            ...

            ANSWER

            Answered 2019-Aug-20 at 15:08

            You need to call the magic function %matplotlib notebook or %matplotlib inline after your imports in jupyter.

            Source https://stackoverflow.com/questions/57576382

            QUESTION

            Where exactly is the DPI information of an image stored (other than Exif)?
            Asked 2018-Sep-01 at 20:58

            We have been using a program called Onyx RIPCenter to manage poster printing for few years now. The images were generated using Photoshop and loaded onto the Onyx application on Windows.

            Recently we dedcied to automate the workflow by eliminating Photoshop and automatically processing the images through a custom application built in python (using pillow python - https://pillow.readthedocs.io/en/latest/)

            Now the problem I have is that when I open the images created through the custom application in RIPCenter, I get wrong sizes in millimetre.

            The actual size of the image is, 924mm x 2108mm instead I get, 2309.99mm x 5269.79mm

            The reason for this is the wrong DPI read by the application, instead of 180, it reads 72 (actual size in pixels - 6548 x 14938).

            The custom application does set all relevant information to the Exif data including DPI. This can be verified by checking the property of the image file in Windows. But somehow when opening the image in RIPCenter, it shows the wrong DPI value.

            Here is the code that saves the image.

            ...

            ANSWER

            Answered 2018-Sep-01 at 20:58

            I would suspect that Onyx RIPCenter is using 72 as a default (which is a common default) and that it normally reads Photoshop:X/YResolution to get the DPI. Try copying the IFD0:X/YResolution to Photoshop:X/YResolution or simply setting the Photoshop:X/YResolution to 180.

            In exiftool, you could use
            exiftool -Photoshop:*Resolution=180 FILEorDIR

            The asterisk is a wildcard which will allow both XResolution and YResolution to be set at the same time. Replace FILEorDIR with the files/directories to be processed. This command creates backup files. Add -overwrite_original to suppress the creation of backup files. Add -r to recurse into subdirectories.

            Source https://stackoverflow.com/questions/52131657

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