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kandi has reviewed COLA and discovered the below as its top functions. This is intended to give you an instant insight into COLA implemented functionality, and help decide if they suit your requirements.
🥤 COLA: Clean Object-oriented & Layered Architecture
1. 创建应用
mvn archetype:generate \
-DgroupId=com.alibaba.cola.demo.web \
-DartifactId=demo-web \
-Dversion=1.0.0-SNAPSHOT \
-Dpackage=com.alibaba.demo \
-DarchetypeArtifactId=cola-framework-archetype-web \
-DarchetypeGroupId=com.alibaba.cola \
-DarchetypeVersion=4.0.1
2. 运行应用
mvn archetype:generate \
-DgroupId=com.alibaba.cola.demo.service \
-DartifactId=demo-service \
-Dversion=1.0.0-SNAPSHOT \
-Dpackage=com.alibaba.demo \
-DarchetypeArtifactId=cola-framework-archetype-service \
-DarchetypeGroupId=com.alibaba.cola \
-DarchetypeVersion=4.0.1
How to use a cell value to set a target sheet as a variable
function onEdit(event) {
const sourceSheet = "sheet1";
const eventRange = event.range;
const eventSheet = eventRange.getSheet();
if (eventSheet.getSheetName() == sourceSheet && eventRange.columnStart == 1 && eventRange.isChecked()) {
const ui = SpreadsheetApp.getUi();
const result = ui.alert('Are you sure you this student is ready to export? This will delete this row', ui.ButtonSet.YES_NO);
if (result == ui.Button.YES) {
const [name, ...value] = eventRange.offset(0, 1, 1, 4).getValues()[0];
const targetSheet = event.source.getSheetByName(name);
if (targetSheet) {
targetSheet.appendRow(value);
eventSheet.deleteRow(eventRange.rowStart);
} else {
throw new Error("No sheet.");
}
} else {
eventRange.uncheck();
}
}
}
How do I look up values in a dataframe and return matching values using python/pandas?
# take the smallest value if A->B mapping is not unique
df_AtoB = df1.groupby("colA", as_index=False).agg(colB_=("colB", "min"))
df = df2.merge(df_AtoB, on="colA", how="left")
df.colB = df.colB.fillna(df.colB_)
df = df.drop(columns="colB_")
-----------------------
# take the smallest value if A->B mapping is not unique
df_AtoB = df1.groupby("colA", as_index=False).agg(colB_=("colB", "min"))
df = df2.merge(df_AtoB, on="colA", how="left")
df.colB = df.colB.fillna(df.colB_)
df = df.drop(columns="colB_")
Return list of columns with string match in multiple DataFrames
def find_char(list_of_df , char):
result = []
for df in list_of_df:
for c in df.columns:
if char in c:
result.append(c)
return result
res = find_char([df,df2,df3] , 'A')
print(res)
['colA', 'colA', 'colA']
-----------------------
def find_char(list_of_df , char):
result = []
for df in list_of_df:
for c in df.columns:
if char in c:
result.append(c)
return result
res = find_char([df,df2,df3] , 'A')
print(res)
['colA', 'colA', 'colA']
-----------------------
l = [','.join(i.columns[i.columns.str.contains('A')]) for i in [df,df2,df3]]
SQL syntax to achieve the "opposite" of LIKE
WHERE 'Coca Cola' LIKE column2
How to convert this tibble?
library(dplyr)
library(tidyr)
mydf %>%
pivot_longer(cols = everything(), names_to = 'carac')
# A tibble: 4 x 2
carac value
<chr> <chr>
1 colA a
2 colB 1
3 colC X
4 colD 2
stack(mydf)[2:1]
-----------------------
library(dplyr)
library(tidyr)
mydf %>%
pivot_longer(cols = everything(), names_to = 'carac')
# A tibble: 4 x 2
carac value
<chr> <chr>
1 colA a
2 colB 1
3 colC X
4 colD 2
stack(mydf)[2:1]
-----------------------
library(dplyr)
library(tidyr)
mydf %>%
pivot_longer(cols = everything(), names_to = 'carac')
# A tibble: 4 x 2
carac value
<chr> <chr>
1 colA a
2 colB 1
3 colC X
4 colD 2
stack(mydf)[2:1]
Pandas melt with n columns and order control (counter)
out = pd.wide_to_long(df,['x','y'],i=['idx','colA','n'],j='cnt').dropna().reset_index()
Out[8]:
idx colA n cnt x y
0 1 10 3 1 0.0 4.0
1 1 10 3 2 3.0 5.0
2 1 10 3 3 4.0 3.0
3 2 5 2 1 1.0 0.0
4 2 5 2 2 2.0 1.0
5 3 12 4 1 7.0 4.0
6 3 12 4 2 8.0 5.0
7 3 12 4 3 10.0 3.0
8 3 12 4 4 11.0 3.0
-----------------------
# pip install pyjanitor
import janitor
import pandas as pd
df.pivot_longer(index = ['idx', 'colA', 'n'],
names_to = (".value", "counter"),
names_pattern=r"(.)(.)",
sort_by_appearance = True).dropna()
idx colA n counter x y
0 1 10 3 1 0.0 4.0
1 1 10 3 2 3.0 5.0
2 1 10 3 3 4.0 3.0
4 2 5 2 1 1.0 0.0
5 2 5 2 2 2.0 1.0
8 3 12 4 1 7.0 4.0
9 3 12 4 2 8.0 5.0
10 3 12 4 3 10.0 3.0
11 3 12 4 4 11.0 3.0
Splitting data separated by a | in a cell to new rows
=arrayformula({"Email","Members";
query(
array_constrain(
{
flatten(split(rept("|"&Input!A2:A,len(regexreplace(Input!B2:B&" | "&Input!C2:C,"[^\|]",))+1),"|")),
trim(flatten(split(Input!B2:B&"|"&Input!C2:C,"|")))
},
max(if(Input!B2:B<>"",len(regexreplace(Input!B2:B&" | "&Input!C2:C,"[^\|]",))+1,))*counta(Input!B2:B),2),
"where Col1 is not null",0)
})
=arrayformula({"Email","Manager";
query(
array_constrain(
{
flatten(split(rept("|"&Input!A2:A,len(regexreplace(Input!B2:B,"[^\|]",))+1),"|")),
trim(flatten(split(Input!B2:B,"|")))
},
max(if(Input!B2:B<>"",len(regexreplace(Input!B2:B,"[^\|]",))+1,))*counta(Input!B2:B),2),
"where Col1 is not null",0)
})
-----------------------
=arrayformula({"Email","Members";
query(
array_constrain(
{
flatten(split(rept("|"&Input!A2:A,len(regexreplace(Input!B2:B&" | "&Input!C2:C,"[^\|]",))+1),"|")),
trim(flatten(split(Input!B2:B&"|"&Input!C2:C,"|")))
},
max(if(Input!B2:B<>"",len(regexreplace(Input!B2:B&" | "&Input!C2:C,"[^\|]",))+1,))*counta(Input!B2:B),2),
"where Col1 is not null",0)
})
=arrayformula({"Email","Manager";
query(
array_constrain(
{
flatten(split(rept("|"&Input!A2:A,len(regexreplace(Input!B2:B,"[^\|]",))+1),"|")),
trim(flatten(split(Input!B2:B,"|")))
},
max(if(Input!B2:B<>"",len(regexreplace(Input!B2:B,"[^\|]",))+1,))*counta(Input!B2:B),2),
"where Col1 is not null",0)
})
php display array results by first letter from select option
<form method="get" action="browse-store-1.php">
<label for="letter-start">Store names start with letter </label>
<select id="letter-start" name="letter-start">
<option id="all">All</option>
<option id="#" value="#">#</option>
<option id="a" value="A">A</option>
<option id="b" value="B">B</option>
<option id="c" value="C">C</option>
...
<option id="z" value="Z">Z</option>
</select>
<input type="submit" name="submit">
</form>
<?php
if(isset($_GET['submit'])) {
echo "<div class=\"flex-container\">";
$selected = $_GET['letter-start'];
foreach ($stores as $s) {
if ($selected === $s['name'][0]) {
$id = $s['id'];
$name = $s['name'];
//display the stores
echo "<div class=\"item\"><a href=\"store-home.php?id=$id\"><div class=\"image\"><img src=\"images/store.png\" alt=\"a store\"></div><h3 class=\"name\">$name</h3></a></div>";
}
}
}
-----------------------
<form method="get" action="browse-store-1.php">
<label for="letter-start">Store names start with letter </label>
<select id="letter-start" name="letter-start">
<option id="all">All</option>
<option id="#" value="#">#</option>
<option id="a" value="A">A</option>
<option id="b" value="B">B</option>
<option id="c" value="C">C</option>
...
<option id="z" value="Z">Z</option>
</select>
<input type="submit" name="submit">
</form>
<?php
if(isset($_GET['submit'])) {
echo "<div class=\"flex-container\">";
$selected = $_GET['letter-start'];
foreach ($stores as $s) {
if ($selected === $s['name'][0]) {
$id = $s['id'];
$name = $s['name'];
//display the stores
echo "<div class=\"item\"><a href=\"store-home.php?id=$id\"><div class=\"image\"><img src=\"images/store.png\" alt=\"a store\"></div><h3 class=\"name\">$name</h3></a></div>";
}
}
}
separate columns on condition in dataframe in R
library(dplyr)
library(tidyr)
df %>%
extract(ColA, c('A1', 'A2'), '(.*)/(.*)', remove = FALSE) %>%
mutate(across(A1:A2, ~replace(., ColB != 'sep', NA)))
# ColA A1 A2 ColB
#1 abc/def abc def sep
#2 bcd/efg <NA> <NA> no
#3 def/ghj/yes def/ghj yes sep
#4 fet/hjk/yes <NA> <NA> no
-----------------------
df[paste0('A', 1:2)] <- read.csv(text = sub("/(\\w+)$",
",\\1", df$ColA), header = FALSE)
df[paste0("A", 1:2)] <- replace(df[paste0("A", 1:2)], df$Col1B != 'sep', NA)
library(dplyr)
library(tidyr)
df %>%
separate(ColA, into = c("A1", "A2"), remove = FALSE, sep="/(?=[^/]+$)") %>%
mutate(across(A1:A2, ~ case_when(ColB == 'sep' ~ .)))
# ColA A1 A2 ColB
#1 abc/def abc def sep
#2 bcd/efg <NA> <NA> no
#3 def/ghj/yes def/ghj yes sep
#4 fet/hjk/yes <NA> <NA> no
df %>%
mutate(new = str_split(case_when(ColB == 'sep' ~ ColA), "/(?=[^/]+$)")) %>%
unnest_wider(c(new))
-----------------------
df[paste0('A', 1:2)] <- read.csv(text = sub("/(\\w+)$",
",\\1", df$ColA), header = FALSE)
df[paste0("A", 1:2)] <- replace(df[paste0("A", 1:2)], df$Col1B != 'sep', NA)
library(dplyr)
library(tidyr)
df %>%
separate(ColA, into = c("A1", "A2"), remove = FALSE, sep="/(?=[^/]+$)") %>%
mutate(across(A1:A2, ~ case_when(ColB == 'sep' ~ .)))
# ColA A1 A2 ColB
#1 abc/def abc def sep
#2 bcd/efg <NA> <NA> no
#3 def/ghj/yes def/ghj yes sep
#4 fet/hjk/yes <NA> <NA> no
df %>%
mutate(new = str_split(case_when(ColB == 'sep' ~ ColA), "/(?=[^/]+$)")) %>%
unnest_wider(c(new))
-----------------------
df[paste0('A', 1:2)] <- read.csv(text = sub("/(\\w+)$",
",\\1", df$ColA), header = FALSE)
df[paste0("A", 1:2)] <- replace(df[paste0("A", 1:2)], df$Col1B != 'sep', NA)
library(dplyr)
library(tidyr)
df %>%
separate(ColA, into = c("A1", "A2"), remove = FALSE, sep="/(?=[^/]+$)") %>%
mutate(across(A1:A2, ~ case_when(ColB == 'sep' ~ .)))
# ColA A1 A2 ColB
#1 abc/def abc def sep
#2 bcd/efg <NA> <NA> no
#3 def/ghj/yes def/ghj yes sep
#4 fet/hjk/yes <NA> <NA> no
df %>%
mutate(new = str_split(case_when(ColB == 'sep' ~ ColA), "/(?=[^/]+$)")) %>%
unnest_wider(c(new))
group and join two tables based on id?
SELECT C.costumer,REF.NAME,REF2.NAME
FROM OTHER_TABLE AS C
JOIN TABLE_SOMETHING_LIKE_THIS AS REF ON C.BUY1=REF.ID
JOIN TABLE_SOMETHING_LIKE_THIS AS REF2 ON C.BUY2=REF2.ID
-----------------------
select costumer,
(select name from tbl1 where id=buy1) buy1,
(select name from tbl1 where id=buy2) buy2
from tbl2;
QUESTION
Check if player has a duplicate of a tool in roblox
Asked 2021-Jun-15 at 06:09I am trying to check if a player has 2 Bloxy Colas in their backpack and if there is 2 destroy the other one
I tried this code in a script but it didn't work
local tmpTable = {} -- store items names
for I,v in pairs(player.Backpack:GetChildren()) do -- loop through all items found
if tmpTable [v.Name] ~= nil then -- checks if item exists in the list
print("a duplicate has been found") -- found item e.g. a duplicate
v:Destroy() -- deletes tool
else
tmpTable [v.Name] = "BloxyCola" -- we don't need to use the value we are only using the key
print("item added to list")
end
end
ANSWER
Answered 2021-Jun-15 at 06:09The duplicate not being removed. Nothing prints
You print something in both branches of your conditional statement. If there is nothing printed that means the loop does not run a single time. That means that player.Backpack:GetChildren()
returns an empty table.
As Instance:GetChildren()
will always return a table, seeing an empty table means that Backpack
does not have any children.
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