stdev | Computes the standard deviation | Architecture library

 by   compute-io JavaScript Version: Current License: MIT

kandi X-RAY | stdev Summary

kandi X-RAY | stdev Summary

stdev is a JavaScript library typically used in Architecture applications. stdev has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i compute-stdev' or download it from GitHub, npm.

stdev === [NPM version][npm-image]][npm-url] [Build Status][travis-image]][travis-url] [Coverage Status][coveralls-image]][coveralls-url] [Dependencies][dependencies-image]][dependencies-url].
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              stdev has a low active ecosystem.
              It has 9 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              stdev has no issues reported. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of stdev is current.

            kandi-Quality Quality

              stdev has no bugs reported.

            kandi-Security Security

              stdev has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              stdev is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              stdev releases are not available. You will need to build from source code and install.
              Deployable package is available in npm.
              Installation instructions, examples and code snippets are available.

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            stdev Key Features

            No Key Features are available at this moment for stdev.

            stdev Examples and Code Snippets

            No Code Snippets are available at this moment for stdev.

            Community Discussions

            QUESTION

            How can I create a horizontal bar chart in R that is split in the middle based off an additional variable on the x-axis?
            Asked 2021-Jun-06 at 09:45

            I'm trying to create a horizontal bar chart that visualizes abundance at specified depth intervals at both day and night. Essentially for those who are familiar with diel vertical migration (dvm), I'm trying to visualize that.

            Here's a link to an example of what I'm talking about, specifically the bottom part of the figure. And another one.

            I've been able to get this so far

            but I'd like to make the duplicates go side by side instead with the middle divider indicating the change in day vs. night. So instead of it going 5, 4, 3, 2, 1, 5, 4, 3, 2, 1 on the y-axis it will have one set of 5-1 on the left and another set on the right, with the columns being directly side-by-side. Having one side shaded and another white would be super useful also! I'm also wondering how to add the error bars for the standard deviation too.

            Here's the code that I have so far:

            ...

            ANSWER

            Answered 2021-Jun-06 at 09:45

            I think this is what you're looking for :-)

            The ggplot2 and dplyr libraries would be useful to you! You can use dplyr::filter to extract all the Fish data instead of manually doing so for each variable.

            Then, you can use ggplot to make the graph. I plotted Day with correct Average values, and the Night data with negative Average values. Then, flipped the coordinates (so the graph is verticle). Then, relabeled the y-axis since you won't want to show negative values.

            Source https://stackoverflow.com/questions/67846217

            QUESTION

            Trying to replace a manual counter with barssince
            Asked 2021-Jun-03 at 17:31

            I have two questions:

            1. I wanna replace redCandlesCounter with barssince, because it looks better. The thing is when I do that: if (barssince(not isCandleGreen and close > middleBand and open < upperBand) > 2 and isLong) kinda breaks the logic by selling on the next candle, which is not what I want. By the way, the tests were done on GTO/USDT (Binance) 30m interval, pictures are at 30 Mar '21 18:30.
            Not expected:

            Expected:

            1. A sexier way to replace isCandleGreen = close > open?
            Code ...

            ANSWER

            Answered 2021-Apr-15 at 14:15

            I guess, you can try to use barssince like this:

            Source https://stackoverflow.com/questions/67107448

            QUESTION

            Statistical Calculus In Big Data Set Wrong Values
            Asked 2021-May-28 at 20:33

            I am using the following code to make a small example of a function I intend to use on a big data set. I calculate statistical features incrementally for each ID in which the unit is month.

            ...

            ANSWER

            Answered 2021-May-28 at 20:33

            Here's the same logic implemented in a vectorized form (which is generally more efficient on large datasets):

            Source https://stackoverflow.com/questions/67744517

            QUESTION

            Draw scatterplots on different plots
            Asked 2021-May-17 at 12:59

            I have a custom function that creates a scatterplot:

            ...

            ANSWER

            Answered 2021-May-17 at 12:59

            The documentation highlights why this behavior happens.

            By calling fig=plt.figure(1) you create a new figure if there is no other figure with the same identifier. In your case, this means the 1. In your case, the figure with the identifier with the 1 is always restored and no new figure is created.

            https://matplotlib.org/stable/api/_as_gen/matplotlib.pyplot.figure.html#matplotlib.pyplot.figure

            From the documentation:

            Source https://stackoverflow.com/questions/67570005

            QUESTION

            Generate random samples for each sample length for a distribution
            Asked 2021-May-16 at 16:37

            My goal is to have draw 500 sample points, take its mean, and then do 6000 times from a distribution. Basically:

            Take sample lengths ranging from N = 1 to 500. For each sample length, draw 6000 samples and estimate the mean from each of the samples. Calculate the standard deviation from these means for each sample length, and show graphically that the decrease in standard deviation corresponds to a square root reduction.

            I am trying to do this on a gamma distribution, but all of my standard deviations are coming out as zero... and I'm not sure why.

            This is the program so far:

            ...

            ANSWER

            Answered 2021-May-13 at 09:49

            The problem is with the line stdevs.append(np.std(sample.mean(axis=0)))

            This takes the standard deviation of a single value i.e. the mean of your sample array, so it will always be 0.

            You need to pass np.std() all the values in your sample not just its mean.

            stdevs.append(np.std(sample)) will give you your array of standard deviations for each sampling.

            Source https://stackoverflow.com/questions/67516566

            QUESTION

            I want my code to check multiple conditions and pick the one that has been met and execute it. Unfortunately my code is not returning anything
            Asked 2021-May-16 at 14:22

            corr is the correlation coeficient value, meaning I have 3 correlation values and std_mev are standard deviation value meaning I also have 3 standard deviation values. I want my code to check if the conditions in the code below are met and if they are met it should execute the statement that is true and compute the induc values as shown in the code. Unfortunately no error or even an execution is being performed to produce the induc values please assist, I have a attached a picture to show this. the code is below:

            ...

            ANSWER

            Answered 2021-May-16 at 12:32

            Everything seems correct, but the print in the last few lines are inside the else condition which is not executed. that's why your code doesn't print anything. Try to indent them back to be outside the condition like this:

            Source https://stackoverflow.com/questions/67556493

            QUESTION

            Is this VB script potentially dangerous?
            Asked 2021-May-10 at 13:47

            this morning I received a mal containing, among other things, a file with the extension .wsf, on which I inadvertently clicked.

            I immediately realized that I had made a mistake ... but too late :( Can you tell me if it is malicious code?

            Here is the code:

            ...

            ANSWER

            Answered 2021-May-10 at 13:47

            The fact it obfuscates itself is a good indicator it maybe malicious, if you want to see what it's attempting to run you can;

            Comment out this line (like below);

            Source https://stackoverflow.com/questions/67468072

            QUESTION

            PowerBI ZSCORE from a measure
            Asked 2021-May-04 at 07:21

            I'm trying to calculate ZSCORE basen on a measure created in DAX.

            Measure would be:

            ...

            ANSWER

            Answered 2021-May-04 at 07:21

            I've found a solution by creating a calculate table using DAX:

            Source https://stackoverflow.com/questions/67313092

            QUESTION

            train_test_split exception with 2D labels as stratify array
            Asked 2021-May-03 at 22:12

            I'm trying to use the train_test_split function by providing the labels array that is a 2-d array for stratifying, with only 0 or 1 values (i.e. [0,0], [0,1], [1,0] or [1,1] are the four possible labels). I cannot rename labels (e.g. to 1,2,3,4 for instance) for code compatibility reasons.

            Hereafter the code of the function where train_test_split is used

            ...

            ANSWER

            Answered 2021-May-03 at 15:34

            This is caused by conflicting types, and how pandas internally handles lists. Case 3 reproduces the error, and then shows how to fix it in.

            Case 1: train_test_split can handle stratified 2D labels:

            Source https://stackoverflow.com/questions/67368402

            QUESTION

            Trying to Implement Naive Bayes algorithm on dataset
            Asked 2021-May-02 at 01:19

            I have a dataset upon which I would like to implement the Naïve Bayes algorithm but it is triggering an error on line 107; str_column_to_float(dataset, i) as follows; "could not convert string to float:''" I thought it was because of the headers for the various columns but even after I removed them and run the code, it is still giving me the same error. Any help will very much be appreciated. The link to the dataset is as follows; [Dataset][1] The code is below

            ...

            ANSWER

            Answered 2021-May-02 at 01:19

            The ValueError is being raised because float() is trying to cast a word to a string.

            Source https://stackoverflow.com/questions/67352126

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install stdev

            For use in the browser, use [browserify](https://github.com/substack/node-browserify).

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