Ruler | An AR ruler app can measure length & area | Augmented Reality library

 by   TBXark Swift Version: 1.1.0 License: MIT

kandi X-RAY | Ruler Summary

kandi X-RAY | Ruler Summary

Ruler is a Swift library typically used in Virtual Reality, Augmented Reality, React Native applications. Ruler has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A simple AR ruler app can measure length & area.
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              Ruler has a low active ecosystem.
              It has 197 star(s) with 52 fork(s). There are 11 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 3 open issues and 3 have been closed. On average issues are closed in 268 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Ruler is 1.1.0

            kandi-Quality Quality

              Ruler has 0 bugs and 0 code smells.

            kandi-Security Security

              Ruler has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              Ruler code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              Ruler is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              Ruler releases are available to install and integrate.
              Installation instructions are available. Examples and code snippets are not available.

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            Ruler Key Features

            No Key Features are available at this moment for Ruler.

            Ruler Examples and Code Snippets

            No Code Snippets are available at this moment for Ruler.

            Community Discussions

            QUESTION

            Combine graphs from two different datasets
            Asked 2022-Mar-09 at 20:44

            I am trying to see how word frequency correlates with phonotactic probability using R, but there are a few issues. First, and most generally, I don't know merge these two graphs together (i want them to appear on the same axis).

            This leads to a second problem because the first graph's y values are in probabilities, and the second is a count, so the scales are not the same. Should I combine data frames first, or is there a simpler way to merge two graphs?

            Here is the reproducible sample, and the code for my graphs:

            ...

            ANSWER

            Answered 2022-Mar-09 at 20:44

            One way could be to use a second y axis. Although this method is to be used critically, in this situation I think it is appropriate:

            Source https://stackoverflow.com/questions/71415367

            QUESTION

            python: how to use dictionary and for loop to work out total cost for a list of (item, quantity) tuples?
            Asked 2022-Mar-04 at 04:25

            this is my first time using stack overflow as I am just starting to learn python so apologies if I don't phrase things as clearly as I should!

            I am working on a problem which asks me to set up a stationery shop. There is a dictionary with prices:

            ...

            ANSWER

            Answered 2022-Mar-04 at 04:25

            Iterate over each element, unpacking the tuple:

            Source https://stackoverflow.com/questions/71346400

            QUESTION

            Why is my Wordle solver failing when there are repeated characters?
            Asked 2022-Feb-04 at 18:13

            For context Wordle is game where you have to decipher a 5 letter word in 6 or less guesses based on certain hints. The hints you get are as follows:

            1. If a character is coloured black there are no characters that match that character in the target word.
            2. If a character is coloured orange there is a character that matches that character in the target word but it is in a different position.
            3. If a character is coloured green the position and the character are a match.

            I am making a wordle solver program that takes in an array of word attempts and eliminates them from a list of the possible words.

            I feel that the best algorithm to solve this problem is a black list where a word that breaks one of the rules is eliminated from the array. But if there is a better alternative I am open to suggestion.

            ...

            ANSWER

            Answered 2022-Feb-04 at 18:13

            You are building a list of candidates, what is a good start I think. It doesn't really matter whether you white- or blacklist the result is the list of candidates. The only concern is that you could get the solution faster or more reliably by guessing words that are not on the candidates list. Why? Because that way you can introduce more new letters at once to check if the word contains them. Maybe a mix between the two strategies is best, hard to tell without testing it first.

            • "green" is OK.
            • "black" needs to count the number of non-black appearances of the letter in the guess and all words that not contain that exact amount of that letter can be eliminated (and also those that have the letter at a black position).
            • "orange" is OK but can be improved: you can count the number of non-black appearances of the letter in the guess and eliminate all words that contain the letter fewer times (checking for minimal appearance and not just at least once) and also what you already have applies: the letter cannot be at an orange position.

            There are a lot of ideas for improvements. First I would create the filter before going through the words. Using similar logic as above you would get a collection of four different rule types: A letter has to be or cannot be at a specific position or a letter has to appear exactly (possibly 0) or at least a specific number of times. Then you go through the words and filter using those rules. Otherwise some work might be done multiple times. It is easiest to create such a filter by collecting the same letters in the guess first. If there is an exact number of appearence rule then you can obviously drop a minimal number of appearance rule for the same letter.

            To guess the word fast I would create an evaluation function to find the most promising next guess among the candidates. Possible values to score:

            • How many new letters are introduced (letters that were not guessed yet).
            • Also the probabilites of the new letters could be taken into account. E.g. how likely is it that a word contains a specific letter. Or even look at correlations between letters: like if I have a Q then I probably also have a U or if the last letter is D then the likelyhood of the 2nd last being E is very high.
            • You could even go through all the possible answers for every candidate and see which guess eliminates the most words on average or something similar. Although this probably takes too long unless somehow approximated.

            Source https://stackoverflow.com/questions/70982118

            QUESTION

            Python Ruler Sequence Generator
            Asked 2022-Jan-29 at 16:12

            I have been struggling for a long time to figure how to define a generator function of a ruler sequence in Python, that follows the rules that the first number of the sequence (starting with 1) shows up once, the next two numbers will show up twice, next three numbers will show up three times, etc.

            So what I am trying to get is 1, 2, 2, 3, 3, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7, 7, 7, 7 etc.

            I understand that the way to do this is to have two separate count generators (itertools.count(1)) and then for every number in one generator yield number from the other generator:

            ...

            ANSWER

            Answered 2022-Jan-28 at 18:43

            QUESTION

            facet_grid in ggplot2 returning a graph for (all), how to remove
            Asked 2022-Jan-24 at 22:44

            I am trying to create a facet_grid that contains histograms for measurements for three different measuring methods for three different objects. However, my code returns a fourth "(all)" graph.

            How can I remove the (all) graph and return a 3x3 facet_grid with the clavicle, phalanx, and sacrum as the columns, and calipers (cm), ruler (in), and your knuckle as the rows?

            The following is a sample data frame and the ggplot2 code to create the histogram facet_grid.

            ...

            ANSWER

            Answered 2022-Jan-24 at 22:44

            Set margins = FALSE in facet_grid:

            Source https://stackoverflow.com/questions/70841338

            QUESTION

            How to wrap part of my JSON with brackets using PHP?
            Asked 2021-Dec-24 at 11:09

            I have some JSON that looks like this:

            ...

            ANSWER

            Answered 2021-Dec-24 at 11:07

            First create your array

            Source https://stackoverflow.com/questions/70472185

            QUESTION

            spacy Entity Ruler pattern isn't working for ent_type
            Asked 2021-Dec-23 at 03:59

            I am trying to get the entity ruler patterns to use a combination of lemma & ent_type to generate a tag for the phrase "landed (or land) in Baltimore(location)". It seems to be working with the Matcher, but not the entity ruler I created. I set the override ents to True, so not really sure why this isn't working. It is most likely a user error, I am just not sure what it is. Below is the code example. From the output, you can see that the pattern rule was added after NER and I have set the override ents to true. Any input or suggestions would be appreciated!

            The matcher tags the entire phrase (landed in Baltimore), but the entity rule does not.

            Code Sample

            ...

            ANSWER

            Answered 2021-Dec-23 at 03:59

            Here is a working version of your code:

            Source https://stackoverflow.com/questions/70450784

            QUESTION

            How to use recording rules from Loki
            Asked 2021-Sep-28 at 13:39

            I'm trying to use Loki new Recording Rules without alerting.

            What is not clear to me is where would the result of the rule evaluation be available?

            Can the ruler be scraped for the metrics values or they have to be pushed to something like Prometheus Pushgateway?

            ...

            ANSWER

            Answered 2021-Sep-27 at 16:51

            Accordingly, to the Loki documentation, metrics must be pushed to Prometheus, Cortex, or Thanos:

            With recording rules, you can run these metric queries continually on an interval and have the resulting metrics written to a Prometheus-compatible remote-write endpoint. They produce Prometheus metrics from log entries.

            At the time of writing, these are the compatible backends that support this:

            • Prometheus (>=v2.25.0)
            • Cortex
            • Thanos (Receiver)

            Source https://stackoverflow.com/questions/69347773

            QUESTION

            How do I split text into a new row based on a match in R?
            Asked 2021-Sep-17 at 18:03

            I have the following dataframe (a smaller sample):

            ...

            ANSWER

            Answered 2021-Sep-16 at 17:01

            We need to replicate by the lengths of the list element for 'Date' and 'Signs'

            Source https://stackoverflow.com/questions/69212040

            QUESTION

            Fixed divs, scrolling in one direction only ("How to do rulers on canvas?")
            Asked 2021-Sep-02 at 08:30

            We've got a frame div that acts as scrollbox for a "canvas" div of arbitrary size (not an actual canvas element, it may be anything, e.g. a div with an image inside). Inside that frame div, two rulers should be tacked to the left and bottom border, and those rulers should scroll with the canvas: the left ruler should scroll vertically with the canvas and the bottom ruler should scroll horizontally with the canvas, but both should stay tacked at their respective frame border.

            Our approach until now works, IF the canvas and left ruler is higher than the frame:

            ...

            ANSWER

            Answered 2021-Sep-02 at 08:30

            When the bottom ruler is not at the bottom (i.e. not in its stuck position) it has the equivalent of position relative. The canvas has position absolute so does not influence this but the left ruler has position sticky. This means its height influences where the following element is positioned.

            One way to get the bottom ruler properly positioned is to make it be in its stuck position from the start. When the canvas height is greater than the frame height this happens, as the first snippet in the question shows. When the canvas (and therefore the left ruler which has the same height) is shorter than the frame the bottom ruler is placed immediately below it.

            If we make the left ruler have the same height as the frame then the bottom ruler will always be in its stuck position. We still need the left ruler to only show its 'markings' (the linear gradient in this example) for just the height of the canvas. This snippet does this by setting the size of the left ruler background accordingly. Click a button to alter canvas height.

            Source https://stackoverflow.com/questions/69014174

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Ruler

            AppStore (recommend) ARuler https://itunes.apple.com/us/app/id1287068680
            Manually compile git clone https://github.com/TBXark/Ruler pod install Compile project with Xcode

            Support

            We would love for you to contribute to Ruler, check the LICENSE file for more info.
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