Hummingbird | Distributed lock , distributed ID | Microservice library

by guoming C# Version: V1.17.0 License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | Hummingbird Summary

Hummingbird is a C# library typically used in Architecture, Microservice, MongoDB, Spring Boot, Docker, Kafka, RabbitMQ applications. Hummingbird has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Distributed lock, distributed ID, distributed message queue, configuration center, registration center, service registration discovery, timeout, retry, fuse, load balancing

Support

Quality

Security

License

Reuse

Support

Hummingbird has a low active ecosystem.

It has 168 star(s) with 19 fork(s). There are 6 watchers for this library.

It had no major release in the last 12 months.

Hummingbird has no issues reported. There are 12 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of Hummingbird is V1.17.0

Quality

Hummingbird has 0 bugs and 0 code smells.

Security

Hummingbird has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

Hummingbird code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

Hummingbird is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

Hummingbird releases are available to install and integrate.

Installation instructions are not available. Examples and code snippets are available.

Hummingbird saves you 15206 person hours of effort in developing the same functionality from scratch.

It has 30352 lines of code, 0 functions and 169 files.

It has low code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Hummingbird

Get all kandi verified functions for this library.

Hummingbird Key Features

No Key Features are available at this moment for Hummingbird.

Hummingbird Examples and Code Snippets

No Code Snippets are available at this moment for Hummingbird.

Community Discussions

Trending Discussions on Hummingbird

RainLab.Blog Post List: List Sub-Categories under a specific Top-Level Category

Adding supervisor and other info into bookdown pdf_book

OS Error in the listdir function of os module

Button Placement on split screen design

Python: nested dictionary problem: trying to run a 'if' command to print out a string

Display Only More Than One Unique Customer/Address Per Truck Number

How to extract key value from a JS object through a common function?

The same Flutter web build runs locally with `dhttp` but fails with `firebase serve` or `firebase deploy`

GCP error reporting stacktrace sample is not detected

Write csv to google cloud storage

QUESTION

RainLab.Blog Post List: List Sub-Categories under a specific Top-Level Category

Asked 2021-Jun-07 at 16:04

I'm working on an October CMS project which use a blog where I need to seperate blog posts in two major categories. When listing blog posts using the RainLab.Blog plugin's Post List component, I need to list categories that are sub-categories under a specific top-level category and exclude other categories.

In the TWIG template, I want to iterate through and list out the categories that belong to "Birds" and not "Sealife".

In the default Post List component, categories are listed like this:

...

ANSWER

Answered 2021-Jun-07 at 16:04

If it's totally fine to hardcode category then you can simply compare categories parent's slug or id to hardcoded value.

Here I am using the slug to compare parent, you can also use id it's totally up to you.

Source https://stackoverflow.com/questions/67866066

QUESTION

Adding supervisor and other info into bookdown pdf_book

Asked 2021-May-05 at 09:02

I want to include my supervisor's name, course name etc. for my paper written in bookdown. I specifically want this information to be in different lines. So far I have tried this in the yaml:

...

ANSWER

Answered 2021-May-05 at 09:02

Using a "line block" should do the trick:

Source https://stackoverflow.com/questions/67397354

QUESTION

OS Error in the listdir function of os module

Asked 2021-Apr-14 at 08:14

I am learning the os module of python, where I wrote the following code to try out the functions of the module.

Input:

...

ANSWER

Answered 2021-Apr-14 at 06:34

In python, the backslash is used as an ignore symbol. So after each backslash add another backslash

Source https://stackoverflow.com/questions/67086612

QUESTION

Button Placement on split screen design

Asked 2020-Aug-22 at 14:14

Im playing around with bootstrap and i've come up against something I am struggling to find an answer to.

I want to put a 'Login' on the bottom right of the screen, near the fold. Below is my code:

...

ANSWER

Answered 2020-Aug-22 at 14:14

Source https://stackoverflow.com/questions/63537039

QUESTION

Python: nested dictionary problem: trying to run a 'if' command to print out a string

Asked 2020-Jul-19 at 06:01

I am trying to do following 2 things for this nested dictionary:

If a bird is aggressive, print out a string advising us to 'cover our heads' using the 'actions' list in this print statement.
If a bird is endangered, print out a string advising us to 'back away', also using the actions list in this print statement.

Here's what I have so far. Any help is much appreciated!:

...

ANSWER

Answered 2020-Jul-19 at 04:49

final_actions={}
for key, value in rarebirds.items():
    if final_actions.get(key)==None:
        final_actions[key]=[]
    if 'Aggressive' in value and value.get("Aggressive")==True:
        final_actions[key].append(actions[1])
    if 'Endangered' in value and value.get("Endangered")==True:
        final_actions[key].append(actions[0])
    if ('Aggressive' in value and value.get("Aggressive")==False) and ('Endangered' in value and value.get("Endangered")==False):
        final_actions[key].append(actions[2])
print(final_actions)

Source https://stackoverflow.com/questions/62976274

QUESTION

Display Only More Than One Unique Customer/Address Per Truck Number

Asked 2020-Apr-29 at 15:40

Been working on a project in which a report will generated from the SQL Query. I wish to display all Shipments (based on unique automatic truck ID) which contain any combination of:

Unique Customers (based on Customer Number, more than one Customer Number per shipment)
Unique Addresses (based on defined Address Field, more than one unique Address per shipment)

The output should look like this when the code runs correct:

...

ANSWER

Answered 2020-Apr-29 at 15:40

SELECT * FROM (SELECT DISTINCT shp.shipmentID
                                                       , ven.CustomerCode
                                                       , ven.CustomerName
                                                       , ads.FirstAddress
                                                       , ads.SecondAddress
                                                       , ads.ThirdAddress
                                                       , ads.City
                                                       , ads.State
                                                       , ads.Zip
                                                       , CASE WHEN(ads.Country LIKE 'US') THEN N'USA' ELSE 'CANADA' END AS Country
                                                       , COUNT (shp.shipmentID) OVER (PARTITION BY shipmentID ORDER BY shp.shpID) AS cntshpID


                        FROM dbo.OrderItems AS ori
                        JOIN dbo.OrderLineProducts AS olns ON olns.olnID = ori.olnID
                        JOIN dbo.OrderLines AS oln ON oln.olnID = olns.olnID
                        JOIN dbo.Orders AS ord ON oln.ordID = ord.ordID
                        JOIN dbo.VendorCustomer AS ven ON ven.venID = ord.venID
                        JOIN dbo.OrderAddresses AS oa ON oa.ordID = ord.ordID
                        JOIN dbo.Address AS ads ON ads.addID = oa.addID
                        JOIN dbo.AddressType AS adst ON adst.atcID = ads.atcID
                                                       AND adst.atcAddressTypeCode = N'SHIP'
                        JOIN dbo.OrderItemShipments AS shpo ON ori.itmID = shpo.itmID
                                                       AND ori.itmIDInstance = shpo.itmIDInstance
                                                       AND ori.olnID = shpo.olnID
                                                       AND ori.olnIDInstance = shpo.olnIDInstance
                        JOIN dbo.Shipments AS shp ON shp.shpID = shpo.shipmentID
                        WHERE shpo.shpID = shp.shipmentID

                        GROUP BY shp.shipmentID
                                         , ven.CustomerCode
                                         , ven.CustomerName
                                         , ads.FirstAddress
                                         , ads.SecondAddress
                                         , ads.ThirdAddress
                                         , ads.City
                                         , ads.State
                                         , ads.aZip
                                         , ads.Country) AS bb

WHERE bb.cntshpID > 1

ORDER BY shpID ASC

Source https://stackoverflow.com/questions/61488423

QUESTION

How to extract key value from a JS object through a common function?

Asked 2020-Jan-01 at 11:15

I try to extract a value from JS object.

Here is my data -

...

ANSWER

Answered 2020-Jan-01 at 08:21

You don't need a for loop. If you know the structure of your object, then you can simple do the following:

Source https://stackoverflow.com/questions/59550869

QUESTION

The same Flutter web build runs locally with `dhttp` but fails with `firebase serve` or `firebase deploy`

Asked 2019-Dec-21 at 13:50

I'm developing a Flutter app for both mobile and web. It uses several packages, including those for Firestore:

...

ANSWER

Answered 2019-Dec-18 at 16:59

Try to modify your web/index.html

from

Source https://stackoverflow.com/questions/59342808

QUESTION

GCP error reporting stacktrace sample is not detected

Asked 2019-Dec-10 at 09:44

I'm currently trying to implement the GCP error reporting for a Symfony project (PHP) in order to report any errors especially the stack trace of the application. The implementation is done by using the Google Cloud Client Library. However it appear that GCP is not detecting the stacktrace that I'm sending. Below is a screenshot of how it look like on the interface:

As documented in this documentation. I have to precise the type of message that I'm sending to the ReportedEventError (If i'm not mistaken the message should be prefix by the 'PHP Fatal Error') string in order for the message to be recognized as a stacktrace. But that didn't worked.

In order for you to help me solve my issues below is the JSON paylaod of what is send by the Google Cloud Client Library.

...

ANSWER

Answered 2019-Dec-10 at 09:44

The issue I had was that I used the Symfony default's method to print the error. In order to resolve this issue I replace this piece of code

Source https://stackoverflow.com/questions/59251709

QUESTION

Write csv to google cloud storage

Asked 2019-Nov-21 at 18:09

I am trying to understand how to write a multiple line csv file to google cloud storage. I'm just not following the documentation

Close to here: Unable to read csv file uploaded on google cloud storage bucket

Example:

...

ANSWER

Answered 2019-Nov-21 at 18:09

The blob.upload_from_string(data) method creates a new object whose contents are exactly the contents of the string data. It overwrites over existing objects rather than appending.

The easiest solution would be to write your whole CSV to a temporary file and then upload that file to GCS with the blob.upload_from_filename(filename) function.

Source https://stackoverflow.com/questions/43601294

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install Hummingbird

You can download it from GitHub.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: