mall | Microservice library
kandi X-RAY | mall Summary
kandi X-RAY | mall Summary
SpringCloud（Finchley.RELEASE）+SpringBoot（2.0.7）+LCN（5.0.2.RELEASE）项目骨架，eureka+config+bus+feign+ribbon+hystrix+zuul等组件支持，MyBatis+Redis+MongoDB+RabbitMQ+Elasticsearch等集群配置，LCN（5.0.2.RELEASE）分布式事务框架，支持Docker部署
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Top functions reviewed by kandi - BETA
- Find objects
- Issue a specific value
- The Redis template bean bean
- Returns a list of products by sn
- Get the cache for an order
- The main entry point
- Serializes the given object to JSON
- Starts the service order application
- Deserialize a JSON object
- Configures the http security
- Main entry point
- Default Redis cache configuration
- Find Product Client by SN
- Find a Product by SN
- Find user by username
- Find by sno client
- Create the Redis cache
- Find all things
- Update the amount
- Finds an order
mall Key Features
mall Examples and Code Snippets
Community Discussions
Trending Discussions on mall
QUESTION
I'm kinda new in HTML. I'm trying to make a page with HTML where I have text in the left of my page (the lyrics of a song) and then a picture that repeats itself at the right (just beside) of that text. But I want the picture to stop repeating itself at the bottom at some point. I want it to go just the length of the text, so I can write some thing below it, but the pictures just go endlessly. This is how I put the picture in the HTML file:
...ANSWER
Answered 2021-Jun-13 at 19:30You try to assign the repeating image pattern to the whole page body - which is why it continues forever. What you should do instead, is to create two DIVs (optionally wrapped inside a third, outer DIV), one for your text, one for the image, and make the CSS applicable only to the one with image. See this CodePen for an example code:
QUESTION
I have done the Einstein's Riddle exercise with linear programming. I implemented this solutions in Gusek. How can i tell if there is more than one solution?
Einsten's riddle:
There are 5 houses in five different colors. In each house lives a person with a different nationality. These five owners drink a certain type of beverage, smoke a certain brand of cigar and keep a certain pet. No owners have the same pet, smoke the same brand of cigar or drink the same beverage.
Constaints:
the Brit lives in the red house
the Swede keeps dogs as pets
the Dane drinks tea
the green house is on the left of the white house
the green house's owner drinks coffee
the person who smokes Pall Mall rears birds
the owner of the yellow house smokes Dunhill
the man living in the center house drinks milk
the Norwegian lives in the first house
the man who smokes blends lives next to the one who keeps cats
the man who keeps horses lives next to the man who smokes Dunhill
the owner who smokes BlueMaster drinks beer
the German smokes Prince
the Norwegian lives next to the blue house
the man who smokes blend has a neighbor who drinks water
Can I tell which constraints are redundant?
Thank you for your help
...ANSWER
Answered 2021-Jun-04 at 08:53Your decisions/solution will be in the form of binary or integer varibles.
If they are binary, add in a new constraint like the one below: (Y are all the binaries which were 1 and `Y are binaries which were 0.)
sum(Y) + sum(i-Y) != |Y|+|Y|
Keep repeating this till you get an infeasible model. This can be extended to the integer case too.
As for redundancy, you have to manually try removing them and see if the solution changes. However, in terms of reduncancy, you might have cases where constraint A and B are redundant OR constraint C is redundant. You could have multiple sets of potential redundant constraints depending on which you eliminate.
QUESTION
I've begun to maintain a PSQL database that stores data used by researchers for various analyses. I was asked to query this database and provide the results such that all the (one-to-many) joined records appear as separate columns instead of rows.
I found an approach that worked, but it required a lot of manual work. I had to figure out ahead of time the maximum number of child records for the parent, and write out a huge select_list.
Does anyone know a better/dynamic way than this? I'd even take a non-psql approach. My actual query had way more fields and joins than this.
...ANSWER
Answered 2021-May-28 at 18:36There are 2 approach you can follow:
- Use below function which will generate above query. use that query and get the result.
QUESTION
I'm a student learning Django. I'm trying to make a shopping mall, but I'm having a hard time registering the product. When a member registers a product himself, I would like to select the category designated in the database and register the product. My current code is this, how can I select a category as a drop-down and register it? Great developers, I'd really appreciate your help.
+I tried other methods, but the form is not applicable. Is there any other way than to designate category_code as Choice Field in the form? I'd like to implement a category selection using the drop-down.
model.py
...ANSWER
Answered 2021-May-27 at 05:27Please first remove the category field category = forms.CheckboxInput() from the model form bcoz you have added it twice.
by default, django render dropdown for foreign key
QUESTION
My approach to creating a choropleth map via plotly seems pretty straightforward--load in the DataFrame, load in the geojson, assign the necessary features to the custom polygons, and plot.
Obviously there is a missed step somewhere when referencing of the custom polygons as only a blank map appears after a lengthy loading time.
One major thing to note is that about half of the polygons are located within states, but are their own custom polygon within the states. Therefore to my knowledge, choropleth_mapbox is the more suitable solution.
A sample of the image, showing custom polygons within the states:
The code:
...ANSWER
Answered 2021-May-21 at 23:49Your output is not a choropleth_mapbox, it is a choropleth. Are you missing showing us any layout code? Without seeing all of your code, it's hard to determine the root cause of your issue so instead I'll show you a simple working example of how to connect a geojson to a dataframe and display it as a choropleth_mapbox below.
QUESTION
-- print out stores at the same regions and their addresses
SELECT A.address AS LE, B.address AS LC, C.address AS LW, D.address AS LS, E.address AS LN FROM
(SELECT region, address FROM postcode WHERE region = 'LE') A,
(SELECT region, address FROM postcode WHERE region = 'LC') B,
(SELECT region, address FROM postcode WHERE region = 'LW') C,
(SELECT region, address FROM postcode WHERE region = 'LS') D,
(SELECT region, address FROM postcode WHERE region = 'LN') E;
ANSWER
Answered 2021-May-20 at 05:13This kind of data manipulation is better done in the client. But you could do:
QUESTION
I would like to edit dynamic fields. One of Form.Item (name = timeSlotDate)is a RangePicker which will show TypeError: date1.isAfter is not a function when I init value. At the same time, My other Form.Items are working well.
Obviously, The Date only supports the moment format, but I provided array format.
Please help with my case.
...ANSWER
Answered 2021-May-14 at 18:14I have solved my issue. After I get my data from the API, the moment the format has been changed to the Date format, therefore the error is shown. So, I change the date format before I init the form format.
Below is my code:
QUESTION
I have javascript to fetch json information. I will be storing this json file locally (I downloaded an example file and added birthdate object for my use example from https://jsonplaceholder.typicode.com/users)
I am trying to parse the returned JSON information and post the contents into 2 seperate div's. I have a json object named "birthdate". In my script, I have a var set to call today's date named "today". It prints the date as "05-12" in console, and that is how I have the "birthdate" formatted in JSON as well. I don't need the year or time.
What I would like is to have the script compare "today" with the json object "birthdate". If today = birthdate, then I would like to have that entry information displayed in the user-list-today div to appear under the Birthday Today section of the page.
If today does not equal birthdate, I would like to have all other entries displayed in the user-list-future div to appear under the Birthday Future section of the page.
Nothing should be posted in both areas, only one or the other.
Any help that anyone could provide would be greatly appreciated. I will include all of my code below. The snippet may give error because I have local path to JSON file instead of online version.
Here is my codepen of it codepen doesnt have the birthday JSON object https://codepen.io/abc-123-webguy/pen/poegaLq
...ANSWER
Answered 2021-May-12 at 21:47This is because you are appending the same node to two different divs. If you look at the documentation to appendChild here, you can see this:
QUESTION
I just try to create .env file to use it for my first time file dev.env
...ANSWER
Answered 2021-May-12 at 08:21thanks to @Hancel Lin I just found the problem as mention in his comment "use = not :"
QUESTION
I have a question about word count using python.
Data Frame have three columns.(id, text, word)
First, This is example table.
[Data Frame]
...ANSWER
Answered 2021-May-06 at 06:00We can use re to extract all of the words in our list. Noting, this will only match words in your list, not numbers.
Then apply a function that returns a dict with the count of each word in the list. We can then apply this function to a new column in the df.
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Install mall
You can use mall like any standard Java library. Please include the the jar files in your classpath. You can also use any IDE and you can run and debug the mall component as you would do with any other Java program. Best practice is to use a build tool that supports dependency management such as Maven or Gradle. For Maven installation, please refer maven.apache.org. For Gradle installation, please refer gradle.org .
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