ranked | Tracking kicker results | Microservice library
kandi X-RAY | ranked Summary
kandi X-RAY | ranked Summary
Application for tracking table-soccer results.
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QUESTION
I have a peculiar problem at hand. I need to rank in the following manner:
- Each ID gets a new rank.
- rank #1 is assigned to the ID with the lowest date. However, the subsequent dates for that particular ID can be higher but they will get the incremental rank w.r.t other IDs. (E.g. ADF32 series will be considered to be ranked first as it had the lowest date, although it ends with dates 09-Nov, and RT659 starts with 13-Aug it will be ranked subsequently)
- For a particular ID, if the days are consecutive then ranks are same, else they add by 1.
- For a particular ID, ranks are given in date ASC.
How to formulate a query?
...ANSWER
Answered 2021-May-21 at 19:43Try datediff on lead/lag and then perform partitioned ranking
QUESTION
ANSWER
Answered 2021-Jun-09 at 03:27If you know the index of an object in arr and you know it won't change then you can use index
to get the object and then destructure it
QUESTION
I'm attempting to select two tables that have the same columns and combining them into 1 which will rank column SalesAmount
from Highest to Lowest. I've attempted to do this by using UNION ALL
but currently, the returned select is ranking them both separately.
TableTwo
has a different ReportId
value then the values in TableOne
.
Here is an example of the returned select from TableOne
statement:
Here is an example of the returned select from TableTwo
which only has 1 value:
I am now attempting to combine these two tables and rank them accordingly. when using UNION ALL
Here is what is being returned:
The row Michigan
is ranked 3. It is selecting both tables into 1 statement but not ranking them as I am trying to do. How can I achieve this? My expected results is having both tables be Ordered By SalesRank
appropriately
Here is an example of my expected result:
StateId ReportTitle ReportId SalesAmount SalesRank 1 Online Sales in California 21 22 1 12 Online Sales in New York 37 13 2 14 Online Sales in Michigan 91 11 3 23 Online Sales in Nevada 14 9 4Here is a query of example:
...ANSWER
Answered 2021-May-24 at 23:30Your attempt doesn't have an order by
clause? So of course it won't be ordered. Add order by SalesRank
e.g.
QUESTION
I'm getting some data from a server and Un-Marshalling the JSON. When I cast the datetime string to a string, I get all my results as an Un-Marshalled object, but when I type it as time.Time
, the rest of the object is cut short. Also, the date is wrong, which might be a hint.
I started casting the time to a string:
...ANSWER
Answered 2021-Jun-07 at 00:51The time "2021-06-04T10:28:21.179-0400" is not in a recognized format. You have to parse it yourself. You can use this format to parse it:
QUESTION
I have ranked data from a survey in which participants have ranked multiple items (n=50) in the order from 1 to 5.
The data looks similar to the following example:
...ANSWER
Answered 2021-Jun-04 at 20:26I think the calculation will be much simpler if you convert the data to longer form.
QUESTION
Here is some fake/sample data:
...ANSWER
Answered 2021-Jun-03 at 20:40Try with:
QUESTION
Integer promotion works by promoting everything of an inferior rank to either int
or uint
. But why is this so?
It makes sense to make a difference between "upgrading" and "downgrading" a type. When you are converting a short
to a char
you may lose data.
However when going up in ranks (bool -> char -> short -> int -> long -> long long) there is no chance to lose data. If I have a char
it doesnt matter if I convert it to a short
or an int
, I still won't lose any data.
My question is why is int promotion only from a lower ranked type towards int
? Why was the decision made to have it like this? Why not towards the next higher ranked type for example (and the go on from there, try to promote again for example).
Seems to me that the implicit conversion semantics seem a bit arbitrary when you try to describe them. "most int
types can be "promoted", meaning a conversion with no possibility of data loss, but the promotion only works towards int
, not just any higher ranked type. If you convert anything to something else other than int
it is called a conversion"
Would it not be simpler to use the actual ranks of the int types to attempt a series of "promotions"? Or just to call any conversion towards a higher ranked int a "promotion"?
P.S. this is an educational question not one a bout a specific programming issue but rather for my own curiosity.
...ANSWER
Answered 2021-Jun-02 at 14:53In the C standard, Section 6.3.1.8 describes "Usual arithmetic conversions." (Added in C99, link is to C11 draft)
Many operators that expect operands of arithmetic type cause conversions and yield result types in a similar way. The purpose is to determine a common real type for the operands and result.
The C99 Rationale V5.10 describes the reason for this as:
Explicit license was added to perform calculations in a “wider” type than absolutely necessary, since this can sometimes produce smaller and faster code, not to mention the correct answer more often. Calculations can also be performed in a “narrower” type by the as if rule so long as the same end result is obtained. Explicit casting can always be used to obtain a value in a desired type.
From the rationale, it is reasonable to infer the committee sees this as the simplest solutions that captures the greatest number of possible uses.
From a simplicity standpoint, having a rank-by-rank promotion system would greatly increase the detail required to implement the standard. It would also create a wide variation of performance issues between platforms of different bit sizes. Programmers seeking to achieve specific objectives with data types are still given that flexibility through explicit casting of types.
QUESTION
I am completely new to all of this so please forgive any issues with how I'm describing and name things. I have an HTML page where the user enters a portion of a URL string in order to launch a new window with the complete URL string. I'd rather just lookup the portion of the URL using an API to create a JSON file and find it automatically. Any ideas how I can accomplish this without user intervention?
HTML (contains text box and button to launch a new window, which I would like to bypass this altogether)
...ANSWER
Answered 2021-May-28 at 17:25I was able to get what I wanted using:
QUESTION
Here, the desc
key has a value which is a string;
ANSWER
Answered 2021-May-29 at 13:58You can make use of innerHTML
to display the strings HTML.
- Change the
tag:
QUESTION
I'm new to programming and to Swift; apologies if I'm asking an obvious question. I'm trying to simulate a ranked-choice voting algorithm. Several parts of it work, but I'm stuck on a basic idea: I need to generate an arbitrary number of arrays that contain each voter's imaginary votes. I want software to produce many arrays that look more or less like this:
...ANSWER
Answered 2021-May-24 at 21:15Use an array of arrays, as jnpdx says in their comment.
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